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  ---
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  library_name: transformers
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- tags: []
 
 
 
 
 
 
 
 
 
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  ---
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- # Model Card for Model ID
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- <!-- Provide a quick summary of what the model is/does. -->
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- ## Model Details
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- ### Model Description
 
 
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- <!-- Provide a longer summary of what this model is. -->
 
 
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- This is the model card of a 🤗 transformers model that has been pushed on the Hub. This model card has been automatically generated.
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- - **Developed by:** [More Information Needed]
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- ### Model Sources [optional]
 
 
 
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- - **Repository:** [More Information Needed]
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- ## Uses
 
 
 
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- <!-- Address questions around how the model is intended to be used, including the foreseeable users of the model and those affected by the model. -->
 
 
 
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- ### Direct Use
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- [More Information Needed]
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- ### Downstream Use [optional]
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- <!-- This section is for the model use when fine-tuned for a task, or when plugged into a larger ecosystem/app -->
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- [More Information Needed]
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- ### Out-of-Scope Use
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- <!-- This section addresses misuse, malicious use, and uses that the model will not work well for. -->
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- ## Bias, Risks, and Limitations
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- <!-- This section is meant to convey both technical and sociotechnical limitations. -->
 
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- [More Information Needed]
 
 
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- ### Recommendations
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- <!-- This section is meant to convey recommendations with respect to the bias, risk, and technical limitations. -->
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- Users (both direct and downstream) should be made aware of the risks, biases and limitations of the model. More information needed for further recommendations.
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- ## How to Get Started with the Model
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- Use the code below to get started with the model.
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- [More Information Needed]
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- ## Training Details
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- ### Training Data
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- <!-- This should link to a Dataset Card, perhaps with a short stub of information on what the training data is all about as well as documentation related to data pre-processing or additional filtering. -->
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- ### Training Procedure
 
 
 
 
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- <!-- This relates heavily to the Technical Specifications. Content here should link to that section when it is relevant to the training procedure. -->
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- #### Preprocessing [optional]
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- [More Information Needed]
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- #### Training Hyperparameters
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- - **Training regime:** [More Information Needed] <!--fp32, fp16 mixed precision, bf16 mixed precision, bf16 non-mixed precision, fp16 non-mixed precision, fp8 mixed precision -->
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- #### Speeds, Sizes, Times [optional]
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- <!-- This section provides information about throughput, start/end time, checkpoint size if relevant, etc. -->
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- [More Information Needed]
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- ## Evaluation
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- <!-- This section describes the evaluation protocols and provides the results. -->
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- ### Testing Data, Factors & Metrics
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- #### Testing Data
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- #### Factors
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- <!-- These are the things the evaluation is disaggregating by, e.g., subpopulations or domains. -->
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- #### Metrics
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- <!-- These are the evaluation metrics being used, ideally with a description of why. -->
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- ### Results
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- #### Summary
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- ## Model Examination [optional]
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- <!-- Relevant interpretability work for the model goes here -->
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- ## Environmental Impact
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- Carbon emissions can be estimated using the [Machine Learning Impact calculator](https://mlco2.github.io/impact#compute) presented in [Lacoste et al. (2019)](https://arxiv.org/abs/1910.09700).
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- ## Technical Specifications [optional]
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- ### Model Architecture and Objective
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- #### Software
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- ## Citation [optional]
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- **BibTeX:**
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- ## Glossary [optional]
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- ## More Information [optional]
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- ## Model Card Authors [optional]
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- [More Information Needed]
 
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  ---
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  library_name: transformers
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+ base_model: Unbabel/TowerInstruct-7B-v0.2
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+ license: apache-2.0
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+ datasets:
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+ - Iker/InstructTranslation-EN-ES
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+ language:
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+ - en
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+ - es
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+ pipeline_tag: text-generation
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+ tags:
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+ - translation
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  ---
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+ This is a [TowerInstruct-7B](https://huggingface.co/Unbabel/TowerInstruct-7B-v0.2) model fine-tuned for translating instructions datasets from English into Spanish. This model has GPT4 translation quality, but you can run it on your own machine for free 🎉
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+ The model has been finetuned using ~1.500 prompts and answers from [teknium/OpenHermes-2.5](teknium/OpenHermes-2.5) translated to Spanish using GPT-4-0125-preview. The dataset is available here: https://huggingface.co/datasets/Iker/InstructTranslation-EN-ES/
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+ # Demo
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+ ```python
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+ import torch
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+ from transformers import pipeline
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+ og = pipeline("text-generation", model="Unbabel/TowerInstruct-13B-v0.1", torch_dtype=torch.bfloat16, device_map=0)
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+ fn7 = pipeline("text-generation", model="Iker/TowerInstruct-7B-v0.2-EN2ES", torch_dtype=torch.bfloat16, device_map=1)
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+ fn = pipeline("text-generation", model="Iker/TowerInstruct-13B-v0.1-EN2ES", torch_dtype=torch.bfloat16, device_map=2)
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+ msg = """
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+ Let's use Bayes' theorem again to solve this problem:\n\nLet A represent the event that the man actually has the ability to predict dice rolls with 90% accuracy, and C represent the event of predicting correctly on the first attempt.\n\nWe want to find P(A|C), the probability that the man actually has the ability given that he predicted correctly on his first attempt.\n\nBayes' theorem states that P(A|C) = P(C|A) * P(A) / P(C)\n\nFirst, let's find P(C|A): the probability of predicting correctly on the first attempt if the man actually has the ability. Since he claims 90% accuracy, this probability is 0.9.\n\nNext, let's find P(A): the probability that someone actually has the ability to predict dice rolls with 90% accuracy. We are told this is 1%, so P(A) = 0.01.\n\nNow we need to find P(C): the overall probability of predicting correctly on the first attempt. This can be calculated as the sum of probabilities for each case: P(C) = P(C|A) * P(A) + P(C|¬A) * P(¬A), where ¬A represents not having the ability and P(¬A) = 1 - P(A) = 0.99.\n\nTo find P(C|¬A), the probability of predicting correctly on the first attempt without the ability, we use the fact that there's a 1/6 chance of guessing correctly by random chance: P(C|¬A) = 1/6.\n\nSo, P(C) = (0.9)*(0.01) + (1/6)*(0.99) = 0.009 + 0.165 = 0.174.\n\nFinally, we can calculate P(A|C) using Bayes' theorem:\n\nP(A|C) = P(C|A) * P(A) / P(C) = (0.9)*(0.01) / (0.174) ≈ 0.0517.\n\nTherefore, the probability that the man actually has the ability to predict dice rolls with 90% accuracy is approximately 5.17%.
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+ """.strip()
 
 
 
 
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+ messages = [
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+ {"role": "user",
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+ "content": f"Translate the following text from English into Spanish.\n{msg}\nSpanish:"},
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+ ]
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+ prompt = og.tokenizer.apply_chat_template(messages, tokenize=False, add_generation_prompt=True)
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+ outputs = og(prompt, max_new_tokens=1024, do_sample=False)
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+ print(outputs[0]["generated_text"])
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+ prompt = fn7.tokenizer.apply_chat_template(messages, tokenize=False, add_generation_prompt=True)
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+ outputs = fn7(prompt, max_new_tokens=1024, do_sample=False)
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+ print(outputs[0]["generated_text"])
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+ prompt = fn.tokenizer.apply_chat_template(messages, tokenize=False, add_generation_prompt=True)
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+ outputs = fn(prompt, max_new_tokens=1024, do_sample=False)
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+ print(outputs[0]["generated_text"])
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+ ```
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+ ### Unbabel/TowerInstruct-13B-v0.1
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+ This model fails with very large inputs, the answer is in Russian instead of Spanish 🥴
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+ ```
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+ Воспроизвем теорему Байеса для решения этой задачи:
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+ Предположим, что A означает событие, когда человек действительно обладает способностью предсказывать результаты броска кубика с то��ностью 90%, а C означает событие правильного предсказания на первой попытке.
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+ Мы хотим найти P(A|C), вероятность того, что у человека действительно есть способность, если он правильно предсказал на первой попытке.
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+ Теорема Байеса утверждает, что P(A|C) = P(C|A) * P(A) / P(C)
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+ Сначала определим P(C|A): вероятность правильного предсказания на первой попытке, если у человека действительно есть способность. Поскольку он утверждает, что его точность составляет 90%, эта вероятность равна 0,9.
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+ Далее определим P(A): вероятность того, что у кого-то действительно есть способность предсказывать результаты броска кубика с точностью 90%. Нам сказано, что она составляет 1%, поэтому P(A) = 0,01.
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+ Теперь нам нужно найти P(C): общую вероятность правильного предсказания на первой попытке. Это можно рассчитать как сумму вероятностей для каждого случая: P(C) = P(C|A) * P(A) + P(C|¬A) * P(¬A), где ¬A означает отсутствие способности, и P(¬A) = 1 - P(A) = 0,99.
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+ Чтобы найти P(C|¬A), вероятность правильного предсказания на первой попытке без способности, мы используем тот факт, что существует 1/6 шанс сделать правильный выбор случайно: P(C|¬A) = 1/6.
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+ Таким образом, P(C) = (0,9)*(0,01) / (0,174) 0,009 + 0,165 = 0,174.
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+ Наконец, мы можем рассчитать P(A|C) с помощью теоремы Байеса:
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+ P(A|C) = P(C|A) * P(A) / P(C) = (0,9)*(0,01) / (0,174) 0,0517.
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+ Таким образом, вероятность того, что у человека действительно есть способность предсказывать результаты броска кубика с точностью 90%, составляет примерно 5,17%.
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+ ```
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+ ### Iker/TowerInstruct-7B-v0.2-EN2ES
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+ ```
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+ Vamos a usar de nuevo el teorema de Bayes para resolver este problema:
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+ A representa el evento de que el hombre realmente tenga la capacidad de predecir lanzamientos de dados con un 90% de precisión, y C representa el evento de predecir correctamente en el primer intento.
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+ Queremos encontrar P(A|C), la probabilidad de que el hombre realmente tenga la capacidad dado que predecía correctamente en su primer intento.
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+ El teorema de Bayes establece que P(A|C) = P(C|A) * P(A) / P(C)
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+ Primero, vamos a encontrar P(C|A): la probabilidad de predecir correctamente en el primer intento si el hombre realmente tiene la capacidad. Dado que afirma un 90% de precisión, esta probabilidad es 0.9.
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+ A continuación, vamos a encontrar P(A): la probabilidad de que alguien realmente tenga la capacidad de predecir lanzamientos de dados con un 90% de precisión. Nos dicen que esto es del 1%, así que P(A) = 0.01.
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+ Ahora necesitamos encontrar P(C): la probabilidad total de predecir correctamente en el primer intento. Esto se puede calcular como la suma de probabilidades para cada caso: P(C) = P(C|A) * P(A) + P(C|¬A) * P(¬A), donde ¬A representa no tener la capacidad y P(¬A) = 1 - P(A) = 0.99.
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+ Para encontrar P(C|¬A), la probabilidad de predecir correctamente en el primer intento sin la capacidad, usamos el hecho de que hay una probabilidad del 1/6 de adivinar correctamente por azar: P(C|¬A) = 1/6.
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+ Así, P(C) = (0.9)*(0.01) + (1/6)*(0.99) = 0.009 + 0.165 = 0.174.
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+ Finalmente, podemos calcular P(A|C) usando el teorema de Bayes:
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+ P(A|C) = P(C|A) * P(A) / P(C) = (0.9)*(0.01) / (0.174) ≈ 0.0517.
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+ Por lo tanto, la probabilidad de que el hombre realmente tenga la capacidad de predecir lanzamientos de dados con un 90% de precisión es aproximadamente del 5.17%.
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+ ```
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+ ### Iker/TowerInstruct-13B-v0.1-EN2ES
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+ ```
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+ Vamos a usar de nuevo el teorema de Bayes para resolver este problema:
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+ Sea A el evento de que el hombre realmente tenga la capacidad de predecir lanzamientos de dados con un 90% de precisión, y C el evento de predecir correctamente en el primer intento.
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+ Queremos encontrar P(A|C), la probabilidad de que el hombre realmente tenga la capacidad dada que predijo correctamente en su primer intento.
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+ El teorema de Bayes establece que P(A|C) = P(C|A) * P(A) / P(C)
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+ Primero, vamos a encontrar P(C|A): la probabilidad de predecir correctamente en el primer intento si el hombre realmente tiene la capacidad. Dado que afirma un 90% de precisión, esta probabilidad es 0.9.
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+ A continuación, vamos a encontrar P(A): la probabilidad de que alguien realmente tenga la capacidad de predecir lanzamientos de dados con un 90% de precisión. Se nos dice que este es 1%, así que P(A) = 0.01.
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+ Ahora necesitamos encontrar P(C): la probabilidad general de predecir correctamente en el primer intento. Esto puede calcularse como la suma de probabilidades para cada caso: P(C) = P(C|A) * P(A) + P(C|¬A) * P(¬A), donde ¬A representa no tener la capacidad y P(¬A) = 1 - P(A) = 0.99.
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+ Para encontrar P(C|¬A), la probabilidad de predecir correctamente en el primer intento sin la capacidad, utilizamos el hecho de que hay una probabilidad de 1/6 de adivinar correctamente por casualidad: P(C|¬A) = 1/6.
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+ Así que, P(C) = (0.9)*(0.01) + (1/6)*(0.99) = 0.009 + 0.165 = 0.174.
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+ Finalmente, podemos calcular P(A|C) usando el teorema de Bayes:
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+ P(A|C) = P(C|A) * P(A) / P(C) = (0.9)*(0.01) / (0.174) ≈ 0.0517.
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+ Por lo tanto, la probabilidad de que el hombre realmente tenga la capacidad de predecir lanzamientos de dados con un 90% de precisión es aproximadamente 5.17%.
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+ ```