NEET 25 final answer key change

data/metadata.jsonl

@@ -1,3 +1,3 @@
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results/google_gemini-2.5-pro-preview-03-25_NEET_2025_20250506_195634/predictions.jsonl

@@ -150,7 +150,7 @@
 {"question_id": "NEET_2025_45_150", "subject": "Biology", "ground_truth": [4], "predicted_answer": [4], "raw_response": "Productivity in an ecosystem refers to the rate at which biomass is produced. It is often expressed in terms of mass per unit area per unit time, or energy per unit area per unit time.\n\nLet's analyze each option:\n(1) gm\u207b\u00b2: This represents grams per square meter. This is a unit of biomass density or standing crop, not productivity because it lacks the time component. For example, the total biomass of plants in an area at a given time.\n\n(2) KCal m\u207b\u00b2: This represents kilocalories per square meter. This is a unit of energy density or standing crop in terms of energy, not productivity because it lacks the time component. For example, the total energy content of biomass in an area at a given time.\n\n(3) KCal m\u207b\u00b3: This represents kilocalories per cubic meter. This is a unit of energy per unit volume. While some aquatic ecosystems might consider volume, terrestrial ecosystems typically use area. More importantly, it is missing the time component for productivity.\n\n(4) (KCal m\u207b\u00b2)yr\u207b\u00b9: This represents kilocalories per square meter per year. This unit has energy (KCal), area (m\u207b\u00b2), and time (yr\u207b\u00b9). This is a valid unit for productivity. Productivity is a rate, so it must include a time dimension. It can be expressed as the rate of biomass production (e.g., g m\u207b\u00b2 yr\u207b\u00b9) or the rate of energy fixation (e.g., kJ m\u207b\u00b2 yr\u207b\u00b9 or KCal m\u207b\u00b2 yr\u207b\u00b9).\n\nThus, (KCal m\u207b\u00b2)yr\u207b\u00b9 is the correct unit for the productivity of an ecosystem.\n\nThe final answer is $\\boxed{4}$\n<answer>4</answer>", "parse_successful": true, "api_call_successful": true, "error": null, "attempt": 1, "evaluation_status": "correct", "marks_awarded": 4}
 {"question_id": "NEET_2025_45_151", "subject": "Biology", "ground_truth": [1], "predicted_answer": [1], "raw_response": "<answer>1</answer>", "parse_successful": true, "api_call_successful": true, "error": null, "attempt": 2, "evaluation_status": "correct", "marks_awarded": 4}
 {"question_id": "NEET_2025_45_152", "subject": "Biology", "ground_truth": [1], "predicted_answer": [2], "raw_response": "Step-by-step derivation:\n\n1.  **Analyze the legend and symbols:**\n    *   Square: Male; Circle: Female\n    *   White: Unaffected; Black: Affected\n    *   Circle with a dot: Carrier female (unaffected)\n    *   \"Unaffected female\" is a plain white circle.\n    *   The question defines a carrier as \"having no disease and has the disease mutation in one allele of the gene\". This is consistent with heterozygous genotype for a recessive trait.\n\n2.  **Determine the mode of inheritance:**\n    *   **Recessive vs. Dominant:** The existence of \"Carrier female\" who is unaffected (white with a dot, not black) implies the disease is recessive. If it were dominant, a carrier (heterozygote) would be affected.\n    *   So, the trait is recessive. Let 'A' be the dominant (normal) allele and 'a' be the recessive (disease) allele.\n        *   Affected individuals: aa (autosomal) or XaXa/XaY (X-linked).\n        *   Carrier individuals (unaffected): Aa (autosomal) or XAXa (X-linked female).\n        *   Unaffected non-carriers: AA (autosomal) or XAXA/XAY (X-linked, XAY male is not a carrier in the typical sense of heterozygosity but matches definition if A is normal allele).\n\n    *   **Autosomal Recessive (AR) vs. X-linked Recessive (XR):**\n        Let's examine the F0 generation and their F1 offspring who become parents.\n        F0 parents: Unaffected Male x Affected Female.\n        F1 individuals who mate: Unaffected Male x Carrier Female.\n\n        If XR:\n        F0 Parents: Unaffected Male (XAY) x Affected Female (XaXa).\n        All their male offspring (sons) must receive Xa from the mother and Y from the father, so their genotype would be XaY, making them affected.\n        All their female offspring (daughters) must receive Xa from the mother and XA from the father, so their genotype would be XAXa, making them carrier females.\n        The F1 generation shows an Unaffected Male mating with a Carrier Female.\n        If these F1 individuals are the offspring of the F0 couple:\n        - The F1 Carrier Female (XAXa) is consistent with being a daughter of F0(XAY) x F0(XaXa).\n        - The F1 Unaffected Male (XAY) is NOT consistent with being a son of F0(XAY) x F0(XaXa), because sons should be XaY (affected).\n        Therefore, X-linked recessive inheritance is ruled out, assuming the F1 individuals are children of the F0 couple shown, which is the standard interpretation of such a pedigree chart.\n\n        If AR:\n        F0 Parents: Unaffected Male (A_) x Affected Female (aa).\n        F1 individuals who mate: Unaffected Male x Carrier Female.\n        Let's determine the genotype of F1 parents from F2 generation.\n        F1 parents (let's call them P1-F1 Male and P2-F1 Female) have offspring in F2.\n        One F2 offspring is an Affected Male (F2-AM, genotype aa).\n        For an 'aa' child to be born:\n        - Mother P2-F1 (Carrier Female) must contribute an 'a' allele. Her genotype is Aa (consistent with carrier status).\n        - Father P1-F1 (Unaffected Male) must also contribute an 'a' allele. Since he is unaffected, his genotype must be Aa.\n        So, the F1 parents are: P1-F1 (Aa, Unaffected Male) and P2-F1 (Aa, Carrier Female).\n        Now, let's check if these F1 individuals (both Aa) can be offspring of F0: Unaffected Male (A_) x Affected Female (aa).\n        Mother F0 (aa) passes 'a' to her offspring. Father F0 (A_) passes 'A' to these Aa offspring.\n        So, F0 Unaffected Male must have at least one 'A' allele.\n        If F0 Unaffected Male is AA: Mating F0(AA) x F0(aa) -> All F1 offspring are Aa. This is consistent with F1 son being Aa and F1 daughter being Aa.\n        If F0 Unaffected Male is Aa: Mating F0(Aa) x F0(aa) -> 1/2 F1 offspring are Aa, 1/2 are aa. It is possible to have an Aa son and an Aa daughter. This is also consistent.\n        Thus, Autosomal Recessive inheritance is consistent with the entire pedigree.\n\n3.  **Determine genotypes of the F2 parents who produce the F3 generation:**\n    The F2 parents are F2-CF2 (Carrier Female) and F2-AM (Affected Male).\n    Based on autosomal recessive inheritance:\n    - F2-CF2 (Carrier Female) has genotype Aa.\n    - F2-AM (Affected Male) has genotype aa.\n\n4.  **Calculate the probability for the F3 child:**\n    The mating is between F2-CF2 (Aa) and F2-AM (aa).\n    Cross: Aa x aa\n    Possible gametes from Aa parent: 1/2 A, 1/2 a.\n    Possible gametes from aa parent: all a.\n    Offspring genotypes in F3:\n    - A (from Aa) + a (from aa) -> Aa (Probability = 1/2 * 1 = 1/2)\n    - a (from Aa) + a (from aa) -> aa (Probability = 1/2 * 1 = 1/2)\n\n    The question asks for the probability of a child in F3 generation \"having no disease AND being a carrier (has the disease mutation in one allele of the gene)\".\n    - Genotype Aa: individuals are unaffected (no disease) and are carriers (one disease allele 'a', one normal allele 'A'). This matches the requirement. Probability = 1/2.\n    - Genotype aa: individuals are affected (have the disease).\n\n    So, the probability of an F3 child having no disease and being a carrier is 1/2.\n\n5.  **Select the correct option:**\n    The calculated probability is 1/2.\n    The given options are:\n    (1) 1/4\n    (2) 1/2\n    (3) 1/8\n    (4) Zero\n    The correct option is (2).\n\nThe final answer is $\\boxed{2}$\n<answer>2</answer>", "parse_successful": true, "api_call_successful": true, "error": null, "attempt": 1, "evaluation_status": "incorrect", "marks_awarded": -1}
-{"question_id": "NEET_2025_45_153", "subject": "Biology", "ground_truth": [3], "predicted_answer": [1], "raw_response": "**Step-by-step analysis:**\n\n1.  **Analyze Assertion (A):** \"Cells of the tapetum possess dense cytoplasm and generally have more than one nucleus.\"\n    *   The tapetum is the innermost nutritive layer of the anther wall. Its cells are known to be metabolically very active.\n    *   Metabolically active cells typically have dense cytoplasm (rich in ribosomes, ER, mitochondria, etc.).\n    *   Tapetal cells often become multinucleate (due to nuclear divisions without cytokinesis, i.e., free nuclear division or endomitosis) or polyploid (due to endomitosis or nuclear fusion). This increases the amount of DNA and thus the capacity for protein synthesis and other metabolic activities related to nourishment.\n    *   So, Assertion (A) is true.\n\n2.  **Analyze Reason (R):** \"Presence of more than one nucleus in the tapetum increases the efficiency of nourishing the developing microspore mother cells.\"\n    *   The primary function of the tapetum is to provide nutrition to the developing microspore mother cells and subsequently to the developing microspores (pollen grains).\n    *   Having more than one nucleus (or being polyploid) allows for a greater rate of synthesis of enzymes, proteins, and other substances required for nourishment. This enhances the metabolic capacity of the cell.\n    *   Therefore, the presence of multiple nuclei contributes to the increased efficiency of the tapetum in its nutritive role.\n    *   So, Reason (R) is true.\n\n3.  **Evaluate if R is the correct explanation of A:**\n    *   Assertion A states two characteristics: dense cytoplasm and more than one nucleus.\n    *   Reason R explains the functional significance of having more than one nucleus \u2013 it increases nourishing efficiency.\n    *   The dense cytoplasm is also indicative of high metabolic activity, which is necessary for nourishment. The multinucleate condition further supports this high metabolic demand for producing and secreting nutritive substances.\n    *   Thus, the reason (increased nourishing efficiency) is a direct consequence and explanation for why tapetal cells have more than one nucleus (and by extension, are metabolically very active, leading to dense cytoplasm). The multinucleate condition (part of A) is an adaptation that enhances the tapetum's ability to nourish (as stated in R).\n\n    Therefore, both Assertion (A) and Reason (R) are true, and Reason (R) is the correct explanation of Assertion (A), particularly in relation to the multinucleate condition which is a key feature mentioned for its functional role.\n\n4.  **Match with the given options:**\n    *   (1) Both A and R are true and R is the correct explanation of A.\n    *   (2) Both A and R are true but R is not the correct explanation of A.\n    *   (3) A is true but R is false.\n    *   (4) A is false but R is true.\n\n    Based on the analysis, option (1) is the correct choice.\n\nFinal Answer Check:\nAssertion: Tapetum cells have dense cytoplasm and are multinucleate. This is a known fact.\nReason: Multinucleate condition increases efficiency of nourishing microspore mother cells. This is also true, as more nuclei allow for increased gene expression and metabolic activity required for producing and secreting nutrients.\nThe reason directly explains the biological significance of the multinucleate characteristic mentioned in the assertion.\n\nTherefore, option (1) is correct.\n\n<answer>1</answer>", "parse_successful": true, "api_call_successful": true, "error": null, "attempt": 1, "evaluation_status": "incorrect", "marks_awarded": -1}
+{"question_id": "NEET_2025_45_153", "subject": "Biology", "ground_truth": [1], "predicted_answer": [1], "raw_response": "**Step-by-step analysis:**\n\n1.  **Analyze Assertion (A):** \"Cells of the tapetum possess dense cytoplasm and generally have more than one nucleus.\"\n    *   The tapetum is the innermost nutritive layer of the anther wall. Its cells are known to be metabolically very active.\n    *   Metabolically active cells typically have dense cytoplasm (rich in ribosomes, ER, mitochondria, etc.).\n    *   Tapetal cells often become multinucleate (due to nuclear divisions without cytokinesis, i.e., free nuclear division or endomitosis) or polyploid (due to endomitosis or nuclear fusion). This increases the amount of DNA and thus the capacity for protein synthesis and other metabolic activities related to nourishment.\n    *   So, Assertion (A) is true.\n\n2.  **Analyze Reason (R):** \"Presence of more than one nucleus in the tapetum increases the efficiency of nourishing the developing microspore mother cells.\"\n    *   The primary function of the tapetum is to provide nutrition to the developing microspore mother cells and subsequently to the developing microspores (pollen grains).\n    *   Having more than one nucleus (or being polyploid) allows for a greater rate of synthesis of enzymes, proteins, and other substances required for nourishment. This enhances the metabolic capacity of the cell.\n    *   Therefore, the presence of multiple nuclei contributes to the increased efficiency of the tapetum in its nutritive role.\n    *   So, Reason (R) is true.\n\n3.  **Evaluate if R is the correct explanation of A:**\n    *   Assertion A states two characteristics: dense cytoplasm and more than one nucleus.\n    *   Reason R explains the functional significance of having more than one nucleus \u2013 it increases nourishing efficiency.\n    *   The dense cytoplasm is also indicative of high metabolic activity, which is necessary for nourishment. The multinucleate condition further supports this high metabolic demand for producing and secreting nutritive substances.\n    *   Thus, the reason (increased nourishing efficiency) is a direct consequence and explanation for why tapetal cells have more than one nucleus (and by extension, are metabolically very active, leading to dense cytoplasm). The multinucleate condition (part of A) is an adaptation that enhances the tapetum's ability to nourish (as stated in R).\n\n    Therefore, both Assertion (A) and Reason (R) are true, and Reason (R) is the correct explanation of Assertion (A), particularly in relation to the multinucleate condition which is a key feature mentioned for its functional role.\n\n4.  **Match with the given options:**\n    *   (1) Both A and R are true and R is the correct explanation of A.\n    *   (2) Both A and R are true but R is not the correct explanation of A.\n    *   (3) A is true but R is false.\n    *   (4) A is false but R is true.\n\n    Based on the analysis, option (1) is the correct choice.\n\nFinal Answer Check:\nAssertion: Tapetum cells have dense cytoplasm and are multinucleate. This is a known fact.\nReason: Multinucleate condition increases efficiency of nourishing microspore mother cells. This is also true, as more nuclei allow for increased gene expression and metabolic activity required for producing and secreting nutrients.\nThe reason directly explains the biological significance of the multinucleate characteristic mentioned in the assertion.\n\nTherefore, option (1) is correct.\n\n<answer>1</answer>", "parse_successful": true, "api_call_successful": true, "error": null, "attempt": 1, "evaluation_status": "correct", "marks_awarded": 4}
 {"question_id": "NEET_2025_45_154", "subject": "Biology", "ground_truth": [3], "predicted_answer": [3], "raw_response": "The development of a mature female gametophyte (embryo sac) in an angiosperm plant from the megaspore mother cell (MMC) involves the following steps:\n\n1.  **Formation of Megaspores:** The diploid (2n) megaspore mother cell undergoes one meiotic division. Meiosis consists of Meiosis I and Meiosis II, collectively considered as a single meiotic event that results in four haploid (n) megaspores.\n    *   So, **1 meiotic division** occurs.\n\n2.  **Development of the Functional Megaspore:** In most angiosperms (Polygonum type, which is the most common), three of the four megaspores degenerate. The remaining one megaspore becomes the functional megaspore.\n\n3.  **Formation of the Embryo Sac (Female Gametophyte):** The nucleus of the functional megaspore undergoes three successive mitotic divisions without immediate cell wall formation (free nuclear divisions).\n    *   **First mitotic division:** The functional megaspore nucleus divides to form two nuclei. These two nuclei move to opposite poles of the developing embryo sac.\n    *   **Second mitotic division:** Each of these two nuclei divides again, resulting in four nuclei (two at each pole).\n    *   **Third mitotic division:** Each of these four nuclei divides once more, resulting in a total of eight nuclei (four at each pole).\n\n    After these three mitotic divisions, cell walls are laid down, organizing the eight nuclei into a 7-celled, 8-nucleate embryo sac. This comprises:\n    *   An egg apparatus (one egg cell and two synergids) at the micropylar end.\n    *   Three antipodal cells at the chalazal end.\n    *   One large central cell with two polar nuclei (which may fuse to form a secondary nucleus).\n\nTherefore, the total number of divisions required from the megaspore mother cell for the development of a mature female gametophyte is:\n*   1 meiotic division (of the megaspore mother cell)\n*   3 mitotic divisions (of the functional megaspore nucleus)\n\nLet's match this with the given options:\n(1) 2 Meiosis and 3 Mitosis\n(2) 1 Meiosis and 2 Mitosis\n(3) 1 Meiosis and 3 Mitosis\n(4) No Meiosis and 2 Mitosis\n\nThe correct option is (3) 1 Meiosis and 3 Mitosis.\n\n<answer>3</answer>", "parse_successful": true, "api_call_successful": true, "error": null, "attempt": 1, "evaluation_status": "correct", "marks_awarded": 4}
 {"question_id": "NEET_2025_45_155", "subject": "Biology", "ground_truth": [3], "predicted_answer": [3], "raw_response": "<answer>3</answer>", "parse_successful": true, "api_call_successful": true, "error": null, "attempt": 1, "evaluation_status": "correct", "marks_awarded": 4}
 {"question_id": "NEET_2025_45_156", "subject": "Biology", "ground_truth": [4], "predicted_answer": [4], "raw_response": "<answer>4</answer>", "parse_successful": true, "api_call_successful": true, "error": null, "attempt": 2, "evaluation_status": "correct", "marks_awarded": 4}

results/google_gemini-2.5-pro-preview-03-25_NEET_2025_20250506_195634/summary.json

@@ -4,9 +4,9 @@
     "exam_year": "2025",
     "timestamp": "20250506_195634",
     "total_questions_in_dataset": 180,
-    "overall_score": 680,
-    "overall_correct": 172,
-    "overall_incorrect": 8,
+    "overall_score": 685,
+    "overall_correct": 173,
+    "overall_incorrect": 7,
     "overall_skipped": 0,
     "overall_api_parse_failures": 6,
     "total_questions_processed": 180,
@@ -14,8 +14,8 @@
     "section_breakdown": {
         "Biology": {
             "score": 340,
-            "correct": 86,
-            "incorrect": 4,
+            "correct": 87,
+            "incorrect": 3,
             "skipped": 0
         },
         "Chemistry": {

results/google_gemini-2.5-pro-preview-03-25_NEET_2025_20250506_195634/summary.md

@@ -7,9 +7,9 @@
 ---
 
 ## NEET Scoring Results
-**Overall Score:** **680 / 720**
-- **Correct Answers (+4):** 172
-- **Incorrect Answers (-1):** 8
+**Overall Score:** **685 / 720**
+- **Correct Answers (+4):** 173
+- **Incorrect Answers (-1):** 7
 - **Skipped Questions (0):** 0
 - **API/Parse Failures (-1):** 6
 - **Total Questions Processed:** 180
@@ -17,6 +17,6 @@
 ### Section Breakdown
 | Section       | Score | Correct | Incorrect | Skipped |
 |---------------|-------|---------|-----------|---------|
-| Biology       | 340   | 86      | 4         | 0       |
+| Biology       | 340   | 87      | 3         | 0       |
 | Chemistry     | 170   | 43      | 2         | 0       |
 | Physics       | 170   | 43      | 2         | 0       |