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python
HumanEval/0
has_close_elements
code_generation
[ [ "[1.0, 2.0, 3.9, 4.0, 5.0, 2.2], 0.3", "True" ], [ "[1.0, 2.0, 3.9, 4.0, 5.0, 2.2], 0.05", "False" ], [ "[1.0, 2.0, 5.9, 4.0, 5.0], 0.95", "True" ], [ "[1.0, 2.0, 5.9, 4.0, 5.0], 0.8", "False" ], [ "[1.0, 2.0, 3.0, 4.0, 5.0, 2.0], 0.1", "True" ], [ "[1.1, 2.2, 3.1, 4.1, 5.1], 1.0", "True" ], [ "[1.1, 2.2, 3.1, 4.1, 5.1], 0.5", "False" ] ]
null
[ [ "[1.0, 2.0, 3.0], 0.5", "False" ], [ "[1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3", "True" ] ]
[ "from typing import List" ]
Check if in given list of numbers, are any two numbers closer to each other than given threshold.
HumanEval
Check if in given list of numbers, are any two numbers closer to each other than given threshold.
[]
from typing import List def has_close_elements(numbers: List[float], threshold: float) -> bool: """ Check if in given list of numbers, are any two numbers closer to each other than given threshold. """
from typing import List def has_close_elements(numbers: List[float], threshold: float) -> bool: """ Check if in given list of numbers, are any two numbers closer to each other than given threshold. >>> has_close_elements([1.0, 2.0, 3.0], 0.5) False >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3) True """ for idx, elem in enumerate(numbers): for idx2, elem2 in enumerate(numbers): if idx != idx2: distance = abs(elem - elem2) if distance < threshold: return True return False
python
HumanEval/1
separate_paren_groups
code_generation
[ [ "'(()()) ((())) () ((())()())'", "[\n '(()())', '((()))', '()', '((())()())'\n ]" ], [ "'() (()) ((())) (((())))'", "[\n '()', '(())', '((()))', '(((())))'\n ]" ], [ "'(()(())((())))'", "[\n '(()(())((())))'\n ]" ], [ "'( ) (( )) (( )( ))'", "['()', '(())', '(()())']" ] ]
null
[ [ "'( ) (( )) (( )( ))'", "['()', '(())', '(()())']" ] ]
[ "from typing import List" ]
Input to this function is a string containing multiple groups of nested parentheses. Your goal is to separate those group into separate strings and return the list of those. Separate groups are balanced (each open brace is properly closed) and not nested within each other Ignore any spaces in the input string.
HumanEval
Input to this function is a string containing multiple groups of nested parentheses. Your goal is to separate those group into separate strings and return the list of those. Separate groups are balanced (each open brace is properly closed) and not nested within each other Ignore any spaces in the input string.
[]
from typing import List def separate_paren_groups(paren_string: str) -> List[str]: """ Input to this function is a string containing multiple groups of nested parentheses. Your goal is to separate those group into separate strings and return the list of those. Separate groups are balanced (each open brace is properly closed) and not nested within each other Ignore any spaces in the input string. """
from typing import List def separate_paren_groups(paren_string: str) -> List[str]: """ Input to this function is a string containing multiple groups of nested parentheses. Your goal is to separate those group into separate strings and return the list of those. Separate groups are balanced (each open brace is properly closed) and not nested within each other Ignore any spaces in the input string. >>> separate_paren_groups('( ) (( )) (( )( ))') ['()', '(())', '(()())'] """ result = [] current_string = [] current_depth = 0 for c in paren_string: if c == '(': current_depth += 1 current_string.append(c) elif c == ')': current_depth -= 1 current_string.append(c) if current_depth == 0: result.append(''.join(current_string)) current_string.clear() return result
python
HumanEval/2
truncate_number
code_generation
[ [ "3.5", "0.5" ] ]
null
[ [ "3.5", "0.5" ], [ "1.33", "0.33" ], [ "123.456", "0.456" ] ]
[]
Given a positive floating point number, it can be decomposed into and integer part (largest integer smaller than given number) and decimals (leftover part always smaller than 1). Return the decimal part of the number.
HumanEval
Given a positive floating point number, it can be decomposed into and integer part (largest integer smaller than given number) and decimals (leftover part always smaller than 1). Return the decimal part of the number.
[]
def truncate_number(number: float) -> float: """ Given a positive floating point number, it can be decomposed into and integer part (largest integer smaller than given number) and decimals (leftover part always smaller than 1). Return the decimal part of the number. """
def truncate_number(number: float) -> float: """ Given a positive floating point number, it can be decomposed into and integer part (largest integer smaller than given number) and decimals (leftover part always smaller than 1). Return the decimal part of the number. >>> truncate_number(3.5) 0.5 """ return number % 1.0
python
HumanEval/3
below_zero
code_generation
[ [ "[]", "False" ], [ "[1, 2, -3, 1, 2, -3]", "False" ], [ "[1, 2, -4, 5, 6]", "True" ], [ "[1, -1, 2, -2, 5, -5, 4, -4]", "False" ], [ "[1, -1, 2, -2, 5, -5, 4, -5]", "True" ], [ "[1, -2, 2, -2, 5, -5, 4, -4]", "True" ] ]
null
[ [ "[1, 2, 3]", "False" ], [ "[1, 2, -4, 5]", "True" ] ]
[ "from typing import List" ]
You're given a list of deposit and withdrawal operations on a bank account that starts with zero balance. Your task is to detect if at any point the balance of account fallls below zero, and at that point function should return True. Otherwise it should return False.
HumanEval
You're given a list of deposit and withdrawal operations on a bank account that starts with zero balance. Your task is to detect if at any point the balance of account fallls below zero, and at that point function should return True. Otherwise it should return False.
[]
from typing import List def below_zero(operations: List[int]) -> bool: """ You're given a list of deposit and withdrawal operations on a bank account that starts with zero balance. Your task is to detect if at any point the balance of account fallls below zero, and at that point function should return True. Otherwise it should return False. """
from typing import List def below_zero(operations: List[int]) -> bool: """ You're given a list of deposit and withdrawal operations on a bank account that starts with zero balance. Your task is to detect if at any point the balance of account fallls below zero, and at that point function should return True. Otherwise it should return False. >>> below_zero([1, 2, 3]) False >>> below_zero([1, 2, -4, 5]) True """ balance = 0 for op in operations: balance += op if balance < 0: return True return False
python
HumanEval/4
mean_absolute_deviation
code_generation
[ [ "[1.0, 2.0, 3.0]", "2.0/3.0" ], [ "[1.0, 2.0, 3.0, 4.0]", "1.0" ], [ "[1.0, 2.0, 3.0, 4.0, 5.0]", "6.0/5.0" ] ]
null
[ [ "[1.0, 2.0, 3.0, 4.0]", "1.0" ] ]
[ "from typing import List" ]
For a given list of input numbers, calculate Mean Absolute Deviation around the mean of this dataset. Mean Absolute Deviation is the average absolute difference between each element and a centerpoint (mean in this case): MAD = average | x - x_mean |
HumanEval
For a given list of input numbers, calculate Mean Absolute Deviation around the mean of this dataset. Mean Absolute Deviation is the average absolute difference between each element and a centerpoint (mean in this case): MAD = average | x - x_mean |
[]
from typing import List def mean_absolute_deviation(numbers: List[float]) -> float: """ For a given list of input numbers, calculate Mean Absolute Deviation around the mean of this dataset. Mean Absolute Deviation is the average absolute difference between each element and a centerpoint (mean in this case): MAD = average | x - x_mean | """
from typing import List def mean_absolute_deviation(numbers: List[float]) -> float: """ For a given list of input numbers, calculate Mean Absolute Deviation around the mean of this dataset. Mean Absolute Deviation is the average absolute difference between each element and a centerpoint (mean in this case): MAD = average | x - x_mean | >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0]) 1.0 """ mean = sum(numbers) / len(numbers) return sum(abs(x - mean) for x in numbers) / len(numbers)
python
HumanEval/5
intersperse
code_generation
[ [ "[], 7", "[]" ], [ "[5, 6, 3, 2], 8", "[5, 8, 6, 8, 3, 8, 2]" ], [ "[2, 2, 2], 2", "[2, 2, 2, 2, 2]" ] ]
null
[ [ "[], 4", "[]" ], [ "[1, 2, 3], 4", "[1, 4, 2, 4, 3]" ] ]
[ "from typing import List" ]
Insert a number 'delimeter' between every two consecutive elements of input list `numbers'
HumanEval
Insert a number 'delimeter' between every two consecutive elements of input list `numbers'
[]
from typing import List def intersperse(numbers: List[int], delimeter: int) -> List[int]: """ Insert a number 'delimeter' between every two consecutive elements of input list `numbers' """
from typing import List def intersperse(numbers: List[int], delimeter: int) -> List[int]: """ Insert a number 'delimeter' between every two consecutive elements of input list `numbers' >>> intersperse([], 4) [] >>> intersperse([1, 2, 3], 4) [1, 4, 2, 4, 3] """ if not numbers: return [] result = [] for n in numbers[:-1]: result.append(n) result.append(delimeter) result.append(numbers[-1]) return result
python
HumanEval/6
parse_nested_parens
code_generation
[ [ "'(()()) ((())) () ((())()())'", "[2, 3, 1, 3]" ], [ "'() (()) ((())) (((())))'", "[1, 2, 3, 4]" ], [ "'(()(())((())))'", "[4]" ] ]
null
[ [ "'(()()) ((())) () ((())()())'", "[2, 3, 1, 3]" ] ]
[ "from typing import List" ]
Input to this function is a string represented multiple groups for nested parentheses separated by spaces. For each of the group, output the deepest level of nesting of parentheses. E.g. (()()) has maximum two levels of nesting while ((())) has three.
HumanEval
Input to this function is a string represented multiple groups for nested parentheses separated by spaces. For each of the group, output the deepest level of nesting of parentheses. E.g. (()()) has maximum two levels of nesting while ((())) has three.
[]
from typing import List def parse_nested_parens(paren_string: str) -> List[int]: """ Input to this function is a string represented multiple groups for nested parentheses separated by spaces. For each of the group, output the deepest level of nesting of parentheses. E.g. (()()) has maximum two levels of nesting while ((())) has three. """
from typing import List def parse_nested_parens(paren_string: str) -> List[int]: """ Input to this function is a string represented multiple groups for nested parentheses separated by spaces. For each of the group, output the deepest level of nesting of parentheses. E.g. (()()) has maximum two levels of nesting while ((())) has three. >>> parse_nested_parens('(()()) ((())) () ((())()())') [2, 3, 1, 3] """ def parse_paren_group(s): depth = 0 max_depth = 0 for c in s: if c == '(': depth += 1 max_depth = max(depth, max_depth) else: depth -= 1 return max_depth return [parse_paren_group(x) for x in paren_string.split(' ') if x]
python
HumanEval/7
filter_by_substring
code_generation
[ [ "[], 'john'", "[]" ], [ "['xxx', 'asd', 'xxy', 'john doe', 'xxxAAA', 'xxx'], 'xxx'", "['xxx', 'xxxAAA', 'xxx']" ], [ "['xxx', 'asd', 'aaaxxy', 'john doe', 'xxxAAA', 'xxx'], 'xx'", "['xxx', 'aaaxxy', 'xxxAAA', 'xxx']" ], [ "['grunt', 'trumpet', 'prune', 'gruesome'], 'run'", "['grunt', 'prune']" ] ]
null
[ [ "[], 'a'", "[]" ], [ "['abc', 'bacd', 'cde', 'array'], 'a'", "['abc', 'bacd', 'array']" ] ]
[ "from typing import List" ]
Filter an input list of strings only for ones that contain given substring
HumanEval
Filter an input list of strings only for ones that contain given substring
[]
from typing import List def filter_by_substring(strings: List[str], substring: str) -> List[str]: """ Filter an input list of strings only for ones that contain given substring """
from typing import List def filter_by_substring(strings: List[str], substring: str) -> List[str]: """ Filter an input list of strings only for ones that contain given substring >>> filter_by_substring([], 'a') [] >>> filter_by_substring(['abc', 'bacd', 'cde', 'array'], 'a') ['abc', 'bacd', 'array'] """ return [x for x in strings if substring in x]
python
HumanEval/8
sum_product
code_generation
[ [ "[]", "(0, 1)" ], [ "[1, 1, 1]", "(3, 1)" ], [ "[100, 0]", "(100, 0)" ], [ "[3, 5, 7]", "(3 + 5 + 7, 3 * 5 * 7)" ], [ "[10]", "(10, 10)" ] ]
null
[ [ "[]", "(0, 1)" ], [ "[1, 2, 3, 4]", "(10, 24)" ] ]
[ "from typing import List, Tuple" ]
For a given list of integers, return a tuple consisting of a sum and a product of all the integers in a list. Empty sum should be equal to 0 and empty product should be equal to 1.
HumanEval
For a given list of integers, return a tuple consisting of a sum and a product of all the integers in a list. Empty sum should be equal to 0 and empty product should be equal to 1. >>> sum_product([]) (0, 1)
[]
from typing import List, Tuple def sum_product(numbers: List[int]) -> Tuple[int, int]: """ For a given list of integers, return a tuple consisting of a sum and a product of all the integers in a list. Empty sum should be equal to 0 and empty product should be equal to 1. >>> sum_product([]) (0, 1) """
from typing import List, Tuple def sum_product(numbers: List[int]) -> Tuple[int, int]: """ For a given list of integers, return a tuple consisting of a sum and a product of all the integers in a list. Empty sum should be equal to 0 and empty product should be equal to 1. >>> sum_product([]) (0, 1) >>> sum_product([1, 2, 3, 4]) (10, 24) """ sum_value = 0 prod_value = 1 for n in numbers: sum_value += n prod_value *= n return sum_value, prod_value
python
HumanEval/9
rolling_max
code_generation
[ [ "[]", "[]" ], [ "[1, 2, 3, 4]", "[1, 2, 3, 4]" ], [ "[4, 3, 2, 1]", "[4, 4, 4, 4]" ], [ "[3, 2, 3, 100, 3]", "[3, 3, 3, 100, 100]" ] ]
null
[ [ "[1, 2, 3, 2, 3, 4, 2]", "[1, 2, 3, 3, 3, 4, 4]" ] ]
[ "from typing import List, Tuple" ]
From a given list of integers, generate a list of rolling maximum element found until given moment in the sequence.
HumanEval
From a given list of integers, generate a list of rolling maximum element found until given moment in the sequence.
[]
from typing import List, Tuple def rolling_max(numbers: List[int]) -> List[int]: """ From a given list of integers, generate a list of rolling maximum element found until given moment in the sequence. """
from typing import List, Tuple def rolling_max(numbers: List[int]) -> List[int]: """ From a given list of integers, generate a list of rolling maximum element found until given moment in the sequence. >>> rolling_max([1, 2, 3, 2, 3, 4, 2]) [1, 2, 3, 3, 3, 4, 4] """ running_max = None result = [] for n in numbers: if running_max is None: running_max = n else: running_max = max(running_max, n) result.append(running_max) return result
python
HumanEval/10
make_palindrome
code_generation
[ [ "''", "''" ], [ "'x'", "'x'" ], [ "'xyz'", "'xyzyx'" ], [ "'xyx'", "'xyx'" ], [ "'jerry'", "'jerryrrej'" ] ]
null
[ [ "''", "''" ], [ "'cat'", "'catac'" ], [ "'cata'", "'catac'" ] ]
[]
Test if given string is a palindrome return string == string[::-1] def make_palindrome(string: str) -> str: Find the shortest palindrome that begins with a supplied string. Algorithm idea is simple: - Find the longest postfix of supplied string that is a palindrome. - Append to the end of the string reverse of a string prefix that comes before the palindromic suffix.
HumanEval
Test if given string is a palindrome
[]
def is_palindrome(string: str) -> bool: """ Test if given string is a palindrome """ return string == string[::-1] def make_palindrome(string: str) -> str: """ Find the shortest palindrome that begins with a supplied string. Algorithm idea is simple: - Find the longest postfix of supplied string that is a palindrome. - Append to the end of the string reverse of a string prefix that comes before the palindromic suffix. """
def is_palindrome(string: str) -> bool: """ Test if given string is a palindrome """ return string == string[::-1] def make_palindrome(string: str) -> str: """ Find the shortest palindrome that begins with a supplied string. Algorithm idea is simple: - Find the longest postfix of supplied string that is a palindrome. - Append to the end of the string reverse of a string prefix that comes before the palindromic suffix. >>> make_palindrome('') '' >>> make_palindrome('cat') 'catac' >>> make_palindrome('cata') 'catac' """ if not string: return '' beginning_of_suffix = 0 while not is_palindrome(string[beginning_of_suffix:]): beginning_of_suffix += 1 return string + string[:beginning_of_suffix][::-1]
python
HumanEval/11
string_xor
code_generation
[ [ "'111000', '101010'", "'010010'" ], [ "'1', '1'", "'0'" ], [ "'0101', '0000'", "'0101'" ] ]
null
[ [ "'010', '110'", "'100'" ] ]
[ "from typing import List" ]
Input are two strings a and b consisting only of 1s and 0s. Perform binary XOR on these inputs and return result also as a string.
HumanEval
Input are two strings a and b consisting only of 1s and 0s. Perform binary XOR on these inputs and return result also as a string.
[]
from typing import List def string_xor(a: str, b: str) -> str: """ Input are two strings a and b consisting only of 1s and 0s. Perform binary XOR on these inputs and return result also as a string. """
from typing import List def string_xor(a: str, b: str) -> str: """ Input are two strings a and b consisting only of 1s and 0s. Perform binary XOR on these inputs and return result also as a string. >>> string_xor('010', '110') '100' """ def xor(i, j): if i == j: return '0' else: return '1' return ''.join(xor(x, y) for x, y in zip(a, b))
python
HumanEval/12
longest
code_generation
[ [ "[]", "None" ], [ "['x', 'y', 'z']", "'x'" ], [ "['x', 'yyy', 'zzzz', 'www', 'kkkk', 'abc']", "'zzzz'" ] ]
null
[ [ "[]", "" ], [ "['a', 'b', 'c']", "'a'" ], [ "['a', 'bb', 'ccc']", "'ccc'" ] ]
[ "from typing import List, Optional" ]
Out of list of strings, return the longest one. Return the first one in case of multiple strings of the same length. Return None in case the input list is empty.
HumanEval
Out of list of strings, return the longest one. Return the first one in case of multiple strings of the same length. Return None in case the input list is empty.
[]
from typing import List, Optional def longest(strings: List[str]) -> Optional[str]: """ Out of list of strings, return the longest one. Return the first one in case of multiple strings of the same length. Return None in case the input list is empty. """
from typing import List, Optional def longest(strings: List[str]) -> Optional[str]: """ Out of list of strings, return the longest one. Return the first one in case of multiple strings of the same length. Return None in case the input list is empty. >>> longest([]) >>> longest(['a', 'b', 'c']) 'a' >>> longest(['a', 'bb', 'ccc']) 'ccc' """ if not strings: return None maxlen = max(len(x) for x in strings) for s in strings: if len(s) == maxlen: return s
python
HumanEval/13
greatest_common_divisor
code_generation
[ [ "3, 7", "1" ], [ "10, 15", "5" ], [ "49, 14", "7" ], [ "144, 60", "12" ] ]
null
[ [ "3, 5", "1" ], [ "25, 15", "5" ] ]
[]
Return a greatest common divisor of two integers a and b
HumanEval
Return a greatest common divisor of two integers a and b
[]
def greatest_common_divisor(a: int, b: int) -> int: """ Return a greatest common divisor of two integers a and b """
def greatest_common_divisor(a: int, b: int) -> int: """ Return a greatest common divisor of two integers a and b >>> greatest_common_divisor(3, 5) 1 >>> greatest_common_divisor(25, 15) 5 """ while b: a, b = b, a % b return a
python
HumanEval/14
all_prefixes
code_generation
[ [ "''", "[]" ], [ "'asdfgh'", "['a', 'as', 'asd', 'asdf', 'asdfg', 'asdfgh']" ], [ "'WWW'", "['W', 'WW', 'WWW']" ] ]
null
[ [ "'abc'", "['a', 'ab', 'abc']" ] ]
[ "from typing import List" ]
Return list of all prefixes from shortest to longest of the input string
HumanEval
Return list of all prefixes from shortest to longest of the input string
[]
from typing import List def all_prefixes(string: str) -> List[str]: """ Return list of all prefixes from shortest to longest of the input string """
from typing import List def all_prefixes(string: str) -> List[str]: """ Return list of all prefixes from shortest to longest of the input string >>> all_prefixes('abc') ['a', 'ab', 'abc'] """ result = [] for i in range(len(string)): result.append(string[:i+1]) return result
python
HumanEval/15
string_sequence
code_generation
[ [ "0", "'0'" ], [ "3", "'0 1 2 3'" ], [ "10", "'0 1 2 3 4 5 6 7 8 9 10'" ] ]
null
[ [ "0", "'0'" ], [ "5", "'0 1 2 3 4 5'" ] ]
[]
Return a string containing space-delimited numbers starting from 0 upto n inclusive.
HumanEval
Return a string containing space-delimited numbers starting from 0 upto n inclusive.
[]
def string_sequence(n: int) -> str: """ Return a string containing space-delimited numbers starting from 0 upto n inclusive. """
def string_sequence(n: int) -> str: """ Return a string containing space-delimited numbers starting from 0 upto n inclusive. >>> string_sequence(0) '0' >>> string_sequence(5) '0 1 2 3 4 5' """ return ' '.join([str(x) for x in range(n + 1)])
python
HumanEval/16
count_distinct_characters
code_generation
[ [ "''", "0" ], [ "'abcde'", "5" ], [ "'abcde' + 'cade' + 'CADE'", "5" ], [ "'aaaaAAAAaaaa'", "1" ], [ "'Jerry jERRY JeRRRY'", "5" ] ]
null
[ [ "'xyzXYZ'", "3" ], [ "'Jerry'", "4" ] ]
[]
Given a string, find out how many distinct characters (regardless of case) does it consist of
HumanEval
Given a string, find out how many distinct characters (regardless of case) does it consist of
[]
def count_distinct_characters(string: str) -> int: """ Given a string, find out how many distinct characters (regardless of case) does it consist of """
def count_distinct_characters(string: str) -> int: """ Given a string, find out how many distinct characters (regardless of case) does it consist of >>> count_distinct_characters('xyzXYZ') 3 >>> count_distinct_characters('Jerry') 4 """ return len(set(string.lower()))
python
HumanEval/17
parse_music
code_generation
[ [ "''", "[]" ], [ "'o o o o'", "[4, 4, 4, 4]" ], [ "'.| .| .| .|'", "[1, 1, 1, 1]" ], [ "'o| o| .| .| o o o o'", "[2, 2, 1, 1, 4, 4, 4, 4]" ], [ "'o| .| o| .| o o| o o|'", "[2, 1, 2, 1, 4, 2, 4, 2]" ] ]
null
[ [ "'o o| .| o| o| .| .| .| .| o o'", "[4, 2, 1, 2, 2, 1, 1, 1, 1, 4, 4]" ] ]
[ "from typing import List" ]
Input to this function is a string representing musical notes in a special ASCII format. Your task is to parse this string and return list of integers corresponding to how many beats does each not last. Here is a legend: 'o' - whole note, lasts four beats 'o|' - half note, lasts two beats '.|' - quater note, lasts one beat
HumanEval
Input to this function is a string representing musical notes in a special ASCII format. Your task is to parse this string and return list of integers corresponding to how many beats does each not last. Here is a legend: 'o' - whole note, lasts four beats 'o|' - half note, lasts two beats '.|' - quater note, lasts one beat
[]
from typing import List def parse_music(music_string: str) -> List[int]: """ Input to this function is a string representing musical notes in a special ASCII format. Your task is to parse this string and return list of integers corresponding to how many beats does each not last. Here is a legend: 'o' - whole note, lasts four beats 'o|' - half note, lasts two beats '.|' - quater note, lasts one beat """
from typing import List def parse_music(music_string: str) -> List[int]: """ Input to this function is a string representing musical notes in a special ASCII format. Your task is to parse this string and return list of integers corresponding to how many beats does each not last. Here is a legend: 'o' - whole note, lasts four beats 'o|' - half note, lasts two beats '.|' - quater note, lasts one beat >>> parse_music('o o| .| o| o| .| .| .| .| o o') [4, 2, 1, 2, 2, 1, 1, 1, 1, 4, 4] """ note_map = {'o': 4, 'o|': 2, '.|': 1} return [note_map[x] for x in music_string.split(' ') if x]
python
HumanEval/18
how_many_times
code_generation
[ [ "'', 'x'", "0" ], [ "'xyxyxyx', 'x'", "4" ], [ "'cacacacac', 'cac'", "4" ], [ "'john doe', 'john'", "1" ] ]
null
[ [ "'', 'a'", "0" ], [ "'aaa', 'a'", "3" ], [ "'aaaa', 'aa'", "3" ] ]
[]
Find how many times a given substring can be found in the original string. Count overlaping cases.
HumanEval
Find how many times a given substring can be found in the original string. Count overlaping cases.
[]
def how_many_times(string: str, substring: str) -> int: """ Find how many times a given substring can be found in the original string. Count overlaping cases. """
def how_many_times(string: str, substring: str) -> int: """ Find how many times a given substring can be found in the original string. Count overlaping cases. >>> how_many_times('', 'a') 0 >>> how_many_times('aaa', 'a') 3 >>> how_many_times('aaaa', 'aa') 3 """ times = 0 for i in range(len(string) - len(substring) + 1): if string[i:i+len(substring)] == substring: times += 1 return times
python
HumanEval/19
sort_numbers
code_generation
[ [ "''", "''" ], [ "'three'", "'three'" ], [ "'three five nine'", "'three five nine'" ], [ "'five zero four seven nine eight'", "'zero four five seven eight nine'" ], [ "'six five four three two one zero'", "'zero one two three four five six'" ] ]
null
[ [ "'three one five'", "'one three five'" ] ]
[ "from typing import List" ]
Input is a space-delimited string of numberals from 'zero' to 'nine'. Valid choices are 'zero', 'one', 'two', 'three', 'four', 'five', 'six', 'seven', 'eight' and 'nine'. Return the string with numbers sorted from smallest to largest
HumanEval
Input is a space-delimited string of numberals from 'zero' to 'nine'. Valid choices are 'zero', 'one', 'two', 'three', 'four', 'five', 'six', 'seven', 'eight' and 'nine'. Return the string with numbers sorted from smallest to largest
[]
from typing import List def sort_numbers(numbers: str) -> str: """ Input is a space-delimited string of numberals from 'zero' to 'nine'. Valid choices are 'zero', 'one', 'two', 'three', 'four', 'five', 'six', 'seven', 'eight' and 'nine'. Return the string with numbers sorted from smallest to largest """
from typing import List def sort_numbers(numbers: str) -> str: """ Input is a space-delimited string of numberals from 'zero' to 'nine'. Valid choices are 'zero', 'one', 'two', 'three', 'four', 'five', 'six', 'seven', 'eight' and 'nine'. Return the string with numbers sorted from smallest to largest >>> sort_numbers('three one five') 'one three five' """ value_map = { 'zero': 0, 'one': 1, 'two': 2, 'three': 3, 'four': 4, 'five': 5, 'six': 6, 'seven': 7, 'eight': 8, 'nine': 9 } return ' '.join(sorted([x for x in numbers.split(' ') if x], key=lambda x: value_map[x]))
python
HumanEval/20
find_closest_elements
code_generation
[ [ "[1.0, 2.0, 3.9, 4.0, 5.0, 2.2]", "(3.9, 4.0)" ], [ "[1.0, 2.0, 5.9, 4.0, 5.0]", "(5.0, 5.9)" ], [ "[1.0, 2.0, 3.0, 4.0, 5.0, 2.2]", "(2.0, 2.2)" ], [ "[1.0, 2.0, 3.0, 4.0, 5.0, 2.0]", "(2.0, 2.0)" ], [ "[1.1, 2.2, 3.1, 4.1, 5.1]", "(2.2, 3.1)" ] ]
null
[ [ "[1.0, 2.0, 3.0, 4.0, 5.0, 2.2]", "(2.0, 2.2)" ], [ "[1.0, 2.0, 3.0, 4.0, 5.0, 2.0]", "(2.0, 2.0)" ] ]
[ "from typing import List, Tuple" ]
From a supplied list of numbers (of length at least two) select and return two that are the closest to each other and return them in order (smaller number, larger number).
HumanEval
From a supplied list of numbers (of length at least two) select and return two that are the closest to each other and return them in order (smaller number, larger number).
[]
from typing import List, Tuple def find_closest_elements(numbers: List[float]) -> Tuple[float, float]: """ From a supplied list of numbers (of length at least two) select and return two that are the closest to each other and return them in order (smaller number, larger number). """
from typing import List, Tuple def find_closest_elements(numbers: List[float]) -> Tuple[float, float]: """ From a supplied list of numbers (of length at least two) select and return two that are the closest to each other and return them in order (smaller number, larger number). >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2]) (2.0, 2.2) >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0]) (2.0, 2.0) """ closest_pair = None distance = None for idx, elem in enumerate(numbers): for idx2, elem2 in enumerate(numbers): if idx != idx2: if distance is None: distance = abs(elem - elem2) closest_pair = tuple(sorted([elem, elem2])) else: new_distance = abs(elem - elem2) if new_distance < distance: distance = new_distance closest_pair = tuple(sorted([elem, elem2])) return closest_pair
python
HumanEval/21
rescale_to_unit
code_generation
[ [ "[2.0, 49.9]", "[0.0, 1.0]" ], [ "[100.0, 49.9]", "[1.0, 0.0]" ], [ "[1.0, 2.0, 3.0, 4.0, 5.0]", "[0.0, 0.25, 0.5, 0.75, 1.0]" ], [ "[2.0, 1.0, 5.0, 3.0, 4.0]", "[0.25, 0.0, 1.0, 0.5, 0.75]" ], [ "[12.0, 11.0, 15.0, 13.0, 14.0]", "[0.25, 0.0, 1.0, 0.5, 0.75]" ] ]
null
[ [ "[1.0, 2.0, 3.0, 4.0, 5.0]", "[0.0, 0.25, 0.5, 0.75, 1.0]" ] ]
[ "from typing import List" ]
Given list of numbers (of at least two elements), apply a linear transform to that list, such that the smallest number will become 0 and the largest will become 1
HumanEval
Given list of numbers (of at least two elements), apply a linear transform to that list, such that the smallest number will become 0 and the largest will become 1
[]
from typing import List def rescale_to_unit(numbers: List[float]) -> List[float]: """ Given list of numbers (of at least two elements), apply a linear transform to that list, such that the smallest number will become 0 and the largest will become 1 """
from typing import List def rescale_to_unit(numbers: List[float]) -> List[float]: """ Given list of numbers (of at least two elements), apply a linear transform to that list, such that the smallest number will become 0 and the largest will become 1 >>> rescale_to_unit([1.0, 2.0, 3.0, 4.0, 5.0]) [0.0, 0.25, 0.5, 0.75, 1.0] """ min_number = min(numbers) max_number = max(numbers) return [(x - min_number) / (max_number - min_number) for x in numbers]
python
HumanEval/22
filter_integers
code_generation
[ [ "[]", "[]" ], [ "[4, {}, [], 23.2, 9, 'adasd']", "[4, 9]" ], [ "[3, 'c', 3, 3, 'a', 'b']", "[3, 3, 3]" ] ]
null
[ [ "['a', 3.14, 5]", "[5]" ], [ "[1, 2, 3, 'abc', {}, []]", "[1, 2, 3]" ] ]
[ "from typing import List, Any" ]
Filter given list of any python values only for integers
HumanEval
Filter given list of any python values only for integers
[]
from typing import List, Any def filter_integers(values: List[Any]) -> List[int]: """ Filter given list of any python values only for integers """
from typing import List, Any def filter_integers(values: List[Any]) -> List[int]: """ Filter given list of any python values only for integers >>> filter_integers(['a', 3.14, 5]) [5] >>> filter_integers([1, 2, 3, 'abc', {}, []]) [1, 2, 3] """ return [x for x in values if isinstance(x, int)]
python
HumanEval/23
strlen
code_generation
[ [ "''", "0" ], [ "'x'", "1" ], [ "'asdasnakj'", "9" ] ]
null
[ [ "''", "0" ], [ "'abc'", "3" ] ]
[]
Return length of given string
HumanEval
Return length of given string
[]
def strlen(string: str) -> int: """ Return length of given string """
def strlen(string: str) -> int: """ Return length of given string >>> strlen('') 0 >>> strlen('abc') 3 """ return len(string)
python
HumanEval/24
largest_divisor
code_generation
[ [ "3", "1" ], [ "7", "1" ], [ "10", "5" ], [ "100", "50" ], [ "49", "7" ] ]
null
[ [ "15", "5" ] ]
[]
For a given number n, find the largest number that divides n evenly, smaller than n
HumanEval
For a given number n, find the largest number that divides n evenly, smaller than n
[]
def largest_divisor(n: int) -> int: """ For a given number n, find the largest number that divides n evenly, smaller than n """
def largest_divisor(n: int) -> int: """ For a given number n, find the largest number that divides n evenly, smaller than n >>> largest_divisor(15) 5 """ for i in reversed(range(n)): if n % i == 0: return i
python
HumanEval/25
factorize
code_generation
[ [ "2", "[2]" ], [ "4", "[2, 2]" ], [ "8", "[2, 2, 2]" ], [ "3 * 19", "[3, 19]" ], [ "3 * 19 * 3 * 19", "[3, 3, 19, 19]" ], [ "3 * 19 * 3 * 19 * 3 * 19", "[3, 3, 3, 19, 19, 19]" ], [ "3 * 19 * 19 * 19", "[3, 19, 19, 19]" ], [ "3 * 2 * 3", "[2, 3, 3]" ] ]
null
[ [ "8", "[2, 2, 2]" ], [ "25", "[5, 5]" ], [ "70", "[2, 5, 7]" ] ]
[ "from typing import List" ]
Return list of prime factors of given integer in the order from smallest to largest. Each of the factors should be listed number of times corresponding to how many times it appeares in factorization. Input number should be equal to the product of all factors
HumanEval
Return list of prime factors of given integer in the order from smallest to largest. Each of the factors should be listed number of times corresponding to how many times it appeares in factorization. Input number should be equal to the product of all factors
[]
from typing import List def factorize(n: int) -> List[int]: """ Return list of prime factors of given integer in the order from smallest to largest. Each of the factors should be listed number of times corresponding to how many times it appeares in factorization. Input number should be equal to the product of all factors """
from typing import List def factorize(n: int) -> List[int]: """ Return list of prime factors of given integer in the order from smallest to largest. Each of the factors should be listed number of times corresponding to how many times it appeares in factorization. Input number should be equal to the product of all factors >>> factorize(8) [2, 2, 2] >>> factorize(25) [5, 5] >>> factorize(70) [2, 5, 7] """ import math fact = [] i = 2 while i <= int(math.sqrt(n) + 1): if n % i == 0: fact.append(i) n //= i else: i += 1 if n > 1: fact.append(n) return fact
python
HumanEval/26
remove_duplicates
code_generation
[ [ "[]", "[]" ], [ "[1, 2, 3, 4]", "[1, 2, 3, 4]" ], [ "[1, 2, 3, 2, 4, 3, 5]", "[1, 4, 5]" ] ]
null
[ [ "[1, 2, 3, 2, 4]", "[1, 3, 4]" ] ]
[ "from typing import List" ]
From a list of integers, remove all elements that occur more than once. Keep order of elements left the same as in the input.
HumanEval
From a list of integers, remove all elements that occur more than once. Keep order of elements left the same as in the input.
[]
from typing import List def remove_duplicates(numbers: List[int]) -> List[int]: """ From a list of integers, remove all elements that occur more than once. Keep order of elements left the same as in the input. """
from typing import List def remove_duplicates(numbers: List[int]) -> List[int]: """ From a list of integers, remove all elements that occur more than once. Keep order of elements left the same as in the input. >>> remove_duplicates([1, 2, 3, 2, 4]) [1, 3, 4] """ import collections c = collections.Counter(numbers) return [n for n in numbers if c[n] <= 1]
python
HumanEval/27
flip_case
code_generation
[ [ "''", "''" ], [ "'Hello!'", "'hELLO!'" ], [ "'These violent delights have violent ends'", "'tHESE VIOLENT DELIGHTS HAVE VIOLENT ENDS'" ] ]
null
[ [ "'Hello'", "'hELLO'" ] ]
[]
For a given string, flip lowercase characters to uppercase and uppercase to lowercase.
HumanEval
For a given string, flip lowercase characters to uppercase and uppercase to lowercase.
[]
def flip_case(string: str) -> str: """ For a given string, flip lowercase characters to uppercase and uppercase to lowercase. """
def flip_case(string: str) -> str: """ For a given string, flip lowercase characters to uppercase and uppercase to lowercase. >>> flip_case('Hello') 'hELLO' """ return string.swapcase()
python
HumanEval/28
concatenate
code_generation
[ [ "[]", "''" ], [ "['x', 'y', 'z']", "'xyz'" ], [ "['x', 'y', 'z', 'w', 'k']", "'xyzwk'" ] ]
null
[ [ "[]", "''" ], [ "['a', 'b', 'c']", "'abc'" ] ]
[ "from typing import List" ]
Concatenate list of strings into a single string
HumanEval
Concatenate list of strings into a single string
[]
from typing import List def concatenate(strings: List[str]) -> str: """ Concatenate list of strings into a single string """
from typing import List def concatenate(strings: List[str]) -> str: """ Concatenate list of strings into a single string >>> concatenate([]) '' >>> concatenate(['a', 'b', 'c']) 'abc' """ return ''.join(strings)
python
HumanEval/29
filter_by_prefix
code_generation
[ [ "[], 'john'", "[]" ], [ "['xxx', 'asd', 'xxy', 'john doe', 'xxxAAA', 'xxx'], 'xxx'", "['xxx', 'xxxAAA', 'xxx']" ] ]
null
[ [ "[], 'a'", "[]" ], [ "['abc', 'bcd', 'cde', 'array'], 'a'", "['abc', 'array']" ] ]
[ "from typing import List" ]
Filter an input list of strings only for ones that start with a given prefix.
HumanEval
Filter an input list of strings only for ones that start with a given prefix.
[]
from typing import List def filter_by_prefix(strings: List[str], prefix: str) -> List[str]: """ Filter an input list of strings only for ones that start with a given prefix. """
from typing import List def filter_by_prefix(strings: List[str], prefix: str) -> List[str]: """ Filter an input list of strings only for ones that start with a given prefix. >>> filter_by_prefix([], 'a') [] >>> filter_by_prefix(['abc', 'bcd', 'cde', 'array'], 'a') ['abc', 'array'] """ return [x for x in strings if x.startswith(prefix)]
python
HumanEval/30
get_positive
code_generation
[ [ "[-1, -2, 4, 5, 6]", "[4, 5, 6]" ], [ "[5, 3, -5, 2, 3, 3, 9, 0, 123, 1, -10]", "[5, 3, 2, 3, 3, 9, 123, 1]" ], [ "[-1, -2]", "[]" ], [ "[]", "[]" ] ]
null
[ [ "[-1, 2, -4, 5, 6]", "[2, 5, 6]" ], [ "[5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]", "[5, 3, 2, 3, 9, 123, 1]" ] ]
[]
Return only positive numbers in the list.
HumanEval
Return only positive numbers in the list.
[]
def get_positive(l: list): """Return only positive numbers in the list. """
def get_positive(l: list): """Return only positive numbers in the list. >>> get_positive([-1, 2, -4, 5, 6]) [2, 5, 6] >>> get_positive([5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) [5, 3, 2, 3, 9, 123, 1] """ return [e for e in l if e > 0]
python
HumanEval/31
is_prime
code_generation
[ [ "6", "False" ], [ "101", "True" ], [ "11", "True" ], [ "13441", "True" ], [ "61", "True" ], [ "4", "False" ], [ "1", "False" ], [ "5", "True" ], [ "11", "True" ], [ "17", "True" ], [ "5 * 17", "False" ], [ "11 * 7", "False" ], [ "13441 * 19", "False" ] ]
null
[ [ "6", "False" ], [ "101", "True" ], [ "11", "True" ], [ "13441", "True" ], [ "61", "True" ], [ "4", "False" ], [ "1", "False" ] ]
[]
Return true if a given number is prime, and false otherwise.
HumanEval
Return true if a given number is prime, and false otherwise.
[]
def is_prime(n): """Return true if a given number is prime, and false otherwise. """
def is_prime(n): """Return true if a given number is prime, and false otherwise. >>> is_prime(6) False >>> is_prime(101) True >>> is_prime(11) True >>> is_prime(13441) True >>> is_prime(61) True >>> is_prime(4) False >>> is_prime(1) False """ if n < 2: return False for k in range(2, n - 1): if n % k == 0: return False return True
python
HumanEval/32
find_zero
code_generation
[]
null
[ [ "x", "0." ], [ "find_zero([1, 2]), 2) # f(x", "1 + 2x" ], [ "find_zero([-6, 11, -6, 1]), 2) # (x - 1) * (x - 2) * (x - 3", "-6 + 11x - 6x^2 + x^3" ] ]
[ "import math" ]
Evaluates polynomial with coefficients xs at point x. return xs[0] + xs[1] * x + xs[1] * x^2 + .... xs[n] * x^n return sum([coeff * math.pow(x, i) for i, coeff in enumerate(xs)]) def find_zero(xs: list): xs are coefficients of a polynomial. find_zero find x such that poly(x) = 0. find_zero returns only only zero point, even if there are many. Moreover, find_zero only takes list xs having even number of coefficients and largest non zero coefficient as it guarantees a solution.
HumanEval
Evaluates polynomial with coefficients xs at point x. return xs[0] + xs[1] * x + xs[1] * x^2 + .... xs[n] * x^n
[]
import math def poly(xs: list, x: float): """ Evaluates polynomial with coefficients xs at point x. return xs[0] + xs[1] * x + xs[1] * x^2 + .... xs[n] * x^n """ return sum([coeff * math.pow(x, i) for i, coeff in enumerate(xs)]) def find_zero(xs: list): """ xs are coefficients of a polynomial. find_zero find x such that poly(x) = 0. find_zero returns only only zero point, even if there are many. Moreover, find_zero only takes list xs having even number of coefficients and largest non zero coefficient as it guarantees a solution. """
import math def poly(xs: list, x: float): """ Evaluates polynomial with coefficients xs at point x. return xs[0] + xs[1] * x + xs[1] * x^2 + .... xs[n] * x^n """ return sum([coeff * math.pow(x, i) for i, coeff in enumerate(xs)]) def find_zero(xs: list): """ xs are coefficients of a polynomial. find_zero find x such that poly(x) = 0. find_zero returns only only zero point, even if there are many. Moreover, find_zero only takes list xs having even number of coefficients and largest non zero coefficient as it guarantees a solution. >>> round(find_zero([1, 2]), 2) # f(x) = 1 + 2x -0.5 >>> round(find_zero([-6, 11, -6, 1]), 2) # (x - 1) * (x - 2) * (x - 3) = -6 + 11x - 6x^2 + x^3 1.0 """ begin, end = -1., 1. while poly(xs, begin) * poly(xs, end) > 0: begin *= 2.0 end *= 2.0 while end - begin > 1e-10: center = (begin + end) / 2.0 if poly(xs, center) * poly(xs, begin) > 0: begin = center else: end = center return begin
python
HumanEval/33
sort_third
code_generation
[]
null
[ [ "[1, 2, 3]", "[1, 2, 3]" ], [ "[5, 6, 3, 4, 8, 9, 2]", "[2, 6, 3, 4, 8, 9, 5]" ] ]
[]
This function takes a list l and returns a list l' such that l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal to the values of the corresponding indicies of l, but sorted.
HumanEval
This function takes a list l and returns a list l' such that l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal to the values of the corresponding indicies of l, but sorted.
[]
def sort_third(l: list): """This function takes a list l and returns a list l' such that l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal to the values of the corresponding indicies of l, but sorted. """
def sort_third(l: list): """This function takes a list l and returns a list l' such that l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal to the values of the corresponding indicies of l, but sorted. >>> sort_third([1, 2, 3]) [1, 2, 3] >>> sort_third([5, 6, 3, 4, 8, 9, 2]) [2, 6, 3, 4, 8, 9, 5] """ l = list(l) l[::3] = sorted(l[::3]) return l
python
HumanEval/34
unique
code_generation
[ [ "[5, 3, 5, 2, 3, 3, 9, 0, 123]", "[0, 2, 3, 5, 9, 123]" ] ]
null
[ [ "[5, 3, 5, 2, 3, 3, 9, 0, 123]", "[0, 2, 3, 5, 9, 123]" ] ]
[]
Return sorted unique elements in a list
HumanEval
Return sorted unique elements in a list
[]
def unique(l: list): """Return sorted unique elements in a list """
def unique(l: list): """Return sorted unique elements in a list >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123]) [0, 2, 3, 5, 9, 123] """ return sorted(list(set(l)))
python
HumanEval/35
max_element
code_generation
[ [ "[1, 2, 3]", "3" ], [ "[5, 3, -5, 2, -3, 3, 9, 0, 124, 1, -10]", "124" ] ]
null
[ [ "[1, 2, 3]", "3" ], [ "[5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]", "123" ] ]
[]
Return maximum element in the list.
HumanEval
Return maximum element in the list.
[]
def max_element(l: list): """Return maximum element in the list. """
def max_element(l: list): """Return maximum element in the list. >>> max_element([1, 2, 3]) 3 >>> max_element([5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) 123 """ m = l[0] for e in l: if e > m: m = e return m
python
HumanEval/36
fizz_buzz
code_generation
[ [ "50", "0" ], [ "78", "2" ], [ "79", "3" ], [ "100", "3" ], [ "200", "6" ], [ "4000", "192" ], [ "10000", "639" ], [ "100000", "8026" ] ]
null
[ [ "50", "0" ], [ "78", "2" ], [ "79", "3" ] ]
[]
Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.
HumanEval
Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.
[]
def fizz_buzz(n: int): """Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13. """
def fizz_buzz(n: int): """Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13. >>> fizz_buzz(50) 0 >>> fizz_buzz(78) 2 >>> fizz_buzz(79) 3 """ ns = [] for i in range(n): if i % 11 == 0 or i % 13 == 0: ns.append(i) s = ''.join(list(map(str, ns))) ans = 0 for c in s: ans += (c == '7') return ans
python
HumanEval/37
sort_even
code_generation
[]
null
[ [ "[1, 2, 3]", "[1, 2, 3]" ], [ "[5, 6, 3, 4]", "[3, 6, 5, 4]" ] ]
[]
This function takes a list l and returns a list l' such that l' is identical to l in the odd indicies, while its values at the even indicies are equal to the values of the even indicies of l, but sorted.
HumanEval
This function takes a list l and returns a list l' such that l' is identical to l in the odd indicies, while its values at the even indicies are equal to the values of the even indicies of l, but sorted.
[]
def sort_even(l: list): """This function takes a list l and returns a list l' such that l' is identical to l in the odd indicies, while its values at the even indicies are equal to the values of the even indicies of l, but sorted. """
def sort_even(l: list): """This function takes a list l and returns a list l' such that l' is identical to l in the odd indicies, while its values at the even indicies are equal to the values of the even indicies of l, but sorted. >>> sort_even([1, 2, 3]) [1, 2, 3] >>> sort_even([5, 6, 3, 4]) [3, 6, 5, 4] """ evens = l[::2] odds = l[1::2] evens.sort() ans = [] for e, o in zip(evens, odds): ans.extend([e, o]) if len(evens) > len(odds): ans.append(evens[-1]) return ans
python
HumanEval/38
decode_cyclic
code_generation
[ [ "'eaztdrcpoojjs'", "'zeartdocpjojs'" ], [ "'fcsasgmhiqc'", "'sfcgasimhqc'" ], [ "'avmirjdeqbylxuau'", "'mavjirqdelbyaxuu'" ], [ "'azhacmsfsnfsg'", "'hazmacssfsnfg'" ], [ "'zbvkvwoatdccvw'", "'vzbwkvtoacdcvw'" ], [ "'mqzfshjknuz'", "'zmqhfsnjkuz'" ], [ "'bgpjjqmghur'", "'pbgqjjhmgur'" ], [ "'skuuqfixmobqarshlnfv'", "'uskfuqmixqobsarnhlfv'" ], [ "'bwcoqbjzilceuidscgn'", "'cbwboqijzelcduigscn'" ], [ "'lpoyfvzavtysssduxn'", "'olpvyfvzastydssnux'" ], [ "'rguzukgsizsrmvrnt'", "'urgkzuigsrzsrmvnt'" ], [ "'orjrnmyozyhwc'", "'jormrnzyowyhc'" ], [ "'egkdzdeufufsupt'", "'kegddzfeusuftup'" ], [ "'kuqnvecsetyvdfero'", "'qkuenvecsvtyedfro'" ], [ "'rglvlgjtgesicfkcmkm'", "'lrggvlgjtieskcfkcmm'" ], [ "'jpdxznnaqylzmmh'", "'djpnxzqnazylhmm'" ], [ "'zwmgzcntpbawwlfbex'", "'mzwcgzpntwbafwlxbe'" ], [ "'unjdpwbxpxkpqdopaalb'", "'junwdppbxpxkoqdapalb'" ], [ "'zeukiguxndy'", "'uzegkinuxdy'" ], [ "'sjnaktdnbnokqjg'", "'nsjtakbdnknogqj'" ], [ "'vrmtirlygzhf'", "'mvrrtiglyfzh'" ], [ "'mhtgmpslldrhjl'", "'tmhpgmlslhdrjl'" ], [ "'mpvjpdatrmhtdx'", "'vmpdjprattmhdx'" ], [ "'jimzixallctnnsg'", "'mjixzilalnctgns'" ], [ "'gahjootuomivad'", "'hgaojootuvmiad'" ], [ "'ulilcmoplpsqqoyrppbh'", "'iulmlclopqpsyqoprpbh'" ], [ "'oznykgwonynglp'", "'nozgyknwogynlp'" ], [ "'fzvyarmdbmeogatu'", "'vfzryabmdometgau'" ], [ "'mfnngxdggewb'", "'nmfxnggdgbew'" ], [ "'qvacnekscjxe'", "'aqvecncksejx'" ], [ "'nmcapqndnkuh'", "'cnmqapnndhku'" ], [ "'nnennffezagabnfa'", "'ennfnnzfeaagfbna'" ], [ "'ifgknbekvs'", "'gifbknveks'" ], [ "'drtekkfffj'", "'tdrkekfffj'" ], [ "'tswtymazbcejja'", "'wtsmtybazjceja'" ], [ "'vlcyvzwvjbrc'", "'cvlzyvjwvcbr'" ], [ "'jvlybcuhdjhoixz'", "'ljvcybduhojhzix'" ], [ "'gtpwuynlrwoimpersbri'", "'pgtywurnliwoempbrsri'" ], [ "'gxkyyxeiltkdiuq'", "'kgxxyyleidtkqiu'" ], [ "'lsxrlnsbrxispzf'", "'xlsnrlrsbsxifpz'" ], [ "'hkwqbehapilpgesmj'", "'whkeqbphapilsgemj'" ], [ "'qgxkrqvsvsrwesnwot'", "'xqgqkrvvswsrnestwo'" ], [ "'tkjskkxoqalpnajqidr'", "'jtkkskqxopaljnadqir'" ], [ "'djekkirzcafg'", "'edjikkcrzgaf'" ], [ "'srfgcpgexwdbajohros'", "'fsrpgcxgebwdoajohrs'" ], [ "'sfckdzevjqezdxmcso'", "'csfzkdjevzqemdxocs'" ], [ "'aaikokcghtbyunigyq'", "'iaakkohcgytbiunqgy'" ], [ "'jaldcwbuxzqvlsff'", "'ljawdcxbuvzqflsf'" ], [ "'hyjfibztlplww'", "'jhybfilztwplw'" ], [ "'irsuppaksqoxgkyak'", "'sirpupsakxqoygkak'" ], [ "'rvhlirxndd'", "'hrvrlidxnd'" ], [ "'fwofairkckdyffng'", "'ofwifacrkykdnffg'" ], [ "'idmgovtowjfmf'", "'midvgowtomjff'" ], [ "'ovfdtilllkla'", "'fovidtlllakl'" ], [ "'kmmlbgisttsjhpgeo'", "'mkmglbtisjtsghpeo'" ], [ "'wvnqidnuhafydcdqqbzv'", "'nwvdqihnuyafddcbqqzv'" ], [ "'suhgzhdxuwp'", "'hsuhgzudxwp'" ], [ "'wovjwmvixtut'", "'vwomjwxvittu'" ], [ "'cghripgisjeihgsbkme'", "'hcgprisgiijeshgmbke'" ], [ "'vpnnwihekt'", "'nvpinwkhet'" ], [ "'oakdzvyxwcubs'", "'koavdzwyxbcus'" ], [ "'yiizrtxhhmazu'", "'iyitzrhxhzmau'" ], [ "'ykzsucdlyah'", "'zykcsuydlah'" ], [ "'wikxqjfoudburqasd'", "'kwijxqufoudbarqsd'" ], [ "'cssoeuoaspnhxaeipsc'", "'scsuoesoahpnexasipc'" ], [ "'yiztlakgbpfqpnvrwxl'", "'zyiatlbkgqpfvpnxrwl'" ], [ "'faljwqdqsyeghhccnrvz'", "'lfaqjwsdqgyechhrcnvz'" ], [ "'okdezkfuvnml'", "'dokkezvfulnm'" ], [ "'klkbfzkqofdmtcg'", "'kklzbfokqmfdgtc'" ], [ "'uqzurwhizdjvr'", "'zuqwurzhivdjr'" ], [ "'jrgrscrapvjpfqj'", "'gjrcrsprapvjjfq'" ], [ "'nwenxrwcrfaeb'", "'enwrnxrwcefab'" ], [ "'pldrrczxefqs'", "'dplcrrezxsfq'" ], [ "'ksvouegvkjyfecan'", "'vkseoukgvfjyaecn'" ], [ "'ijqaxfmbwjkevttzbxk'", "'qijfaxwmbejktvtxzbk'" ], [ "'irewkmbwkh'", "'eirmwkkbwh'" ], [ "'mhqhodamvtgiev'", "'qmhdhovamitgev'" ], [ "'ryjpgtgwucmyeulwhydh'", "'jrytpgugwycmleuywhdh'" ], [ "'ttkwvupppyakk'", "'kttuwvpppkyak'" ], [ "'dsgidvchdrln'", "'gdsviddchnrl'" ], [ "'nklhmphxejdcwx'", "'lnkphmehxcjdwx'" ], [ "'plwenneudaqxtwheh'", "'wplnendeuxaqhtweh'" ], [ "'pasolfzaalcs'", "'spafolazaslc'" ], [ "'mvohmjdjtvggijdbxbnh'", "'omvjhmtdjgvgdijbbxnh'" ], [ "'olbcwcvbnhh'", "'bolccwnvbhh'" ], [ "'nttkuqayrlcuxioymcl'", "'tntqkurayulcoxicyml'" ], [ "'jxhrreunodmezni'", "'hjxerrounedmizn'" ], [ "'wsrxjpqyzkxhbxc'", "'rwspxjzqyhkxcbx'" ], [ "'kxkqlaosighdfirrgd'", "'kkxaqliosdghrfidrg'" ], [ "'jwlphbvzsosmfdq'", "'ljwbphsvzmosqfd'" ], [ "'osdfiyiitm'", "'dosyfitiim'" ], [ "'yndqfrdeuthbcwhhvizq'", "'dynrqfudebthhcwihvzq'" ], [ "'cmqnxmwxnrv'", "'qcmmnxnwxrv'" ], [ "'qvfdfgsgqkwa'", "'fqvgdfqsgakw'" ], [ "'zzuimcybadfunvwd'", "'uzzcimaybudfwnvd'" ], [ "'bsrzyntvnvsppnz'", "'rbsnzyntvpvszpn'" ], [ "'mjrvpbrpqemkws'", "'rmjbvpqrpkemws'" ], [ "'ekwvxxlganvrot'", "'wekxvxalgrnvot'" ], [ "'onlzsrfkdqfuvl'", "'lonrzsdfkuqfvl'" ], [ "'rcwvivhovywyfnqsefv'", "'wrcvvivhoyywqfnfsev'" ] ]
null
[ [ "group", "3 else group for group in groups]" ] ]
[]
returns encoded string by cycling groups of three characters. # split string to groups. Each of length 3. groups = [s[(3 * i):min((3 * i + 3), len(s))] for i in range((len(s) + 2) // 3)] # cycle elements in each group. Unless group has fewer elements than 3. groups = [(group[1:] + group[0]) if len(group) == 3 else group for group in groups] return "".join(groups) def decode_cyclic(s: str): takes as input string encoded with encode_cyclic function. Returns decoded string.
HumanEval
returns encoded string by cycling groups of three characters.
[]
def encode_cyclic(s: str): """ returns encoded string by cycling groups of three characters. """ # split string to groups. Each of length 3. groups = [s[(3 * i):min((3 * i + 3), len(s))] for i in range((len(s) + 2) // 3)] # cycle elements in each group. Unless group has fewer elements than 3. groups = [(group[1:] + group[0]) if len(group) == 3 else group for group in groups] return "".join(groups) def decode_cyclic(s: str): """ takes as input string encoded with encode_cyclic function. Returns decoded string. """
def encode_cyclic(s: str): """ returns encoded string by cycling groups of three characters. """ # split string to groups. Each of length 3. groups = [s[(3 * i):min((3 * i + 3), len(s))] for i in range((len(s) + 2) // 3)] # cycle elements in each group. Unless group has fewer elements than 3. groups = [(group[1:] + group[0]) if len(group) == 3 else group for group in groups] return "".join(groups) def decode_cyclic(s: str): """ takes as input string encoded with encode_cyclic function. Returns decoded string. """ return encode_cyclic(encode_cyclic(s))
python
HumanEval/39
prime_fib
code_generation
[ [ "1", "2" ], [ "2", "3" ], [ "3", "5" ], [ "4", "13" ], [ "5", "89" ], [ "6", "233" ], [ "7", "1597" ], [ "8", "28657" ], [ "9", "514229" ], [ "10", "433494437" ] ]
null
[ [ "1", "2" ], [ "2", "3" ], [ "3", "5" ], [ "4", "13" ], [ "5", "89" ] ]
[]
prime_fib returns n-th number that is a Fibonacci number and it's also prime.
HumanEval
prime_fib returns n-th number that is a Fibonacci number and it's also prime.
[]
def prime_fib(n: int): """ prime_fib returns n-th number that is a Fibonacci number and it's also prime. """
def prime_fib(n: int): """ prime_fib returns n-th number that is a Fibonacci number and it's also prime. >>> prime_fib(1) 2 >>> prime_fib(2) 3 >>> prime_fib(3) 5 >>> prime_fib(4) 13 >>> prime_fib(5) 89 """ import math def is_prime(p): if p < 2: return False for k in range(2, min(int(math.sqrt(p)) + 1, p - 1)): if p % k == 0: return False return True f = [0, 1] while True: f.append(f[-1] + f[-2]) if is_prime(f[-1]): n -= 1 if n == 0: return f[-1]
python
HumanEval/40
triples_sum_to_zero
code_generation
[ [ "[1, 3, 5, 0]", "False" ], [ "[1, 3, 5, -1]", "False" ], [ "[1, 3, -2, 1]", "True" ], [ "[1, 2, 3, 7]", "False" ], [ "[1, 2, 5, 7]", "False" ], [ "[2, 4, -5, 3, 9, 7]", "True" ], [ "[1]", "False" ], [ "[1, 3, 5, -100]", "False" ], [ "[100, 3, 5, -100]", "False" ] ]
null
[ [ "[1, 3, 5, 0]", "False" ], [ "[1, 3, -2, 1]", "True" ], [ "[1, 2, 3, 7]", "False" ], [ "[2, 4, -5, 3, 9, 7]", "True" ], [ "[1]", "False" ] ]
[]
triples_sum_to_zero takes a list of integers as an input. it returns True if there are three distinct elements in the list that sum to zero, and False otherwise.
HumanEval
triples_sum_to_zero takes a list of integers as an input. it returns True if there are three distinct elements in the list that sum to zero, and False otherwise.
[]
def triples_sum_to_zero(l: list): """ triples_sum_to_zero takes a list of integers as an input. it returns True if there are three distinct elements in the list that sum to zero, and False otherwise. """
def triples_sum_to_zero(l: list): """ triples_sum_to_zero takes a list of integers as an input. it returns True if there are three distinct elements in the list that sum to zero, and False otherwise. >>> triples_sum_to_zero([1, 3, 5, 0]) False >>> triples_sum_to_zero([1, 3, -2, 1]) True >>> triples_sum_to_zero([1, 2, 3, 7]) False >>> triples_sum_to_zero([2, 4, -5, 3, 9, 7]) True >>> triples_sum_to_zero([1]) False """ for i in range(len(l)): for j in range(i + 1, len(l)): for k in range(j + 1, len(l)): if l[i] + l[j] + l[k] == 0: return True return False
python
HumanEval/41
car_race_collision
code_generation
[ [ "2", "4" ], [ "3", "9" ], [ "4", "16" ], [ "8", "64" ], [ "10", "100" ] ]
null
[]
[]
Imagine a road that's a perfectly straight infinitely long line. n cars are driving left to right; simultaneously, a different set of n cars are driving right to left. The two sets of cars start out being very far from each other. All cars move in the same speed. Two cars are said to collide when a car that's moving left to right hits a car that's moving right to left. However, the cars are infinitely sturdy and strong; as a result, they continue moving in their trajectory as if they did not collide. This function outputs the number of such collisions.
HumanEval
Imagine a road that's a perfectly straight infinitely long line. n cars are driving left to right; simultaneously, a different set of n cars are driving right to left. The two sets of cars start out being very far from each other. All cars move in the same speed. Two cars are said to collide when a car that's moving left to right hits a car that's moving right to left. However, the cars are infinitely sturdy and strong; as a result, they continue moving in their trajectory as if they did not collide. This function outputs the number of such collisions.
[]
def car_race_collision(n: int): """ Imagine a road that's a perfectly straight infinitely long line. n cars are driving left to right; simultaneously, a different set of n cars are driving right to left. The two sets of cars start out being very far from each other. All cars move in the same speed. Two cars are said to collide when a car that's moving left to right hits a car that's moving right to left. However, the cars are infinitely sturdy and strong; as a result, they continue moving in their trajectory as if they did not collide. This function outputs the number of such collisions. """
def car_race_collision(n: int): """ Imagine a road that's a perfectly straight infinitely long line. n cars are driving left to right; simultaneously, a different set of n cars are driving right to left. The two sets of cars start out being very far from each other. All cars move in the same speed. Two cars are said to collide when a car that's moving left to right hits a car that's moving right to left. However, the cars are infinitely sturdy and strong; as a result, they continue moving in their trajectory as if they did not collide. This function outputs the number of such collisions. """ return n**2
python
HumanEval/42
incr_list
code_generation
[ [ "[]", "[]" ], [ "[3, 2, 1]", "[4, 3, 2]" ], [ "[5, 2, 5, 2, 3, 3, 9, 0, 123]", "[6, 3, 6, 3, 4, 4, 10, 1, 124]" ] ]
null
[ [ "[1, 2, 3]", "[2, 3, 4]" ], [ "[5, 3, 5, 2, 3, 3, 9, 0, 123]", "[6, 4, 6, 3, 4, 4, 10, 1, 124]" ] ]
[]
Return list with elements incremented by 1.
HumanEval
Return list with elements incremented by 1.
[]
def incr_list(l: list): """Return list with elements incremented by 1. """
def incr_list(l: list): """Return list with elements incremented by 1. >>> incr_list([1, 2, 3]) [2, 3, 4] >>> incr_list([5, 3, 5, 2, 3, 3, 9, 0, 123]) [6, 4, 6, 3, 4, 4, 10, 1, 124] """ return [(e + 1) for e in l]
python
HumanEval/43
pairs_sum_to_zero
code_generation
[ [ "[1, 3, 5, 0]", "False" ], [ "[1, 3, -2, 1]", "False" ], [ "[1, 2, 3, 7]", "False" ], [ "[2, 4, -5, 3, 5, 7]", "True" ], [ "[1]", "False" ], [ "[-3, 9, -1, 3, 2, 30]", "True" ], [ "[-3, 9, -1, 3, 2, 31]", "True" ], [ "[-3, 9, -1, 4, 2, 30]", "False" ], [ "[-3, 9, -1, 4, 2, 31]", "False" ] ]
null
[ [ "[1, 3, 5, 0]", "False" ], [ "[1, 3, -2, 1]", "False" ], [ "[1, 2, 3, 7]", "False" ], [ "[2, 4, -5, 3, 5, 7]", "True" ], [ "[1]", "False" ] ]
[]
pairs_sum_to_zero takes a list of integers as an input. it returns True if there are two distinct elements in the list that sum to zero, and False otherwise.
HumanEval
pairs_sum_to_zero takes a list of integers as an input. it returns True if there are two distinct elements in the list that sum to zero, and False otherwise.
[]
def pairs_sum_to_zero(l): """ pairs_sum_to_zero takes a list of integers as an input. it returns True if there are two distinct elements in the list that sum to zero, and False otherwise. """
def pairs_sum_to_zero(l): """ pairs_sum_to_zero takes a list of integers as an input. it returns True if there are two distinct elements in the list that sum to zero, and False otherwise. >>> pairs_sum_to_zero([1, 3, 5, 0]) False >>> pairs_sum_to_zero([1, 3, -2, 1]) False >>> pairs_sum_to_zero([1, 2, 3, 7]) False >>> pairs_sum_to_zero([2, 4, -5, 3, 5, 7]) True >>> pairs_sum_to_zero([1]) False """ for i, l1 in enumerate(l): for j in range(i + 1, len(l)): if l1 + l[j] == 0: return True return False
python
HumanEval/44
change_base
code_generation
[ [ "8, 3", "\"22\"" ], [ "9, 3", "\"100\"" ], [ "234, 2", "\"11101010\"" ], [ "16, 2", "\"10000\"" ], [ "8, 2", "\"1000\"" ], [ "7, 2", "\"111\"" ] ]
null
[ [ "8, 3", "'22'" ], [ "8, 2", "'1000'" ], [ "7, 2", "'111'" ] ]
[]
Change numerical base of input number x to base. return string representation after the conversion. base numbers are less than 10.
HumanEval
Change numerical base of input number x to base. return string representation after the conversion. base numbers are less than 10.
[]
def change_base(x: int, base: int): """Change numerical base of input number x to base. return string representation after the conversion. base numbers are less than 10. """
def change_base(x: int, base: int): """Change numerical base of input number x to base. return string representation after the conversion. base numbers are less than 10. >>> change_base(8, 3) '22' >>> change_base(8, 2) '1000' >>> change_base(7, 2) '111' """ ret = "" while x > 0: ret = str(x % base) + ret x //= base return ret
python
HumanEval/45
triangle_area
code_generation
[ [ "5, 3", "7.5" ], [ "2, 2", "2.0" ], [ "10, 8", "40.0" ] ]
null
[ [ "5, 3", "7.5" ] ]
[]
Given length of a side and high return area for a triangle.
HumanEval
Given length of a side and high return area for a triangle.
[]
def triangle_area(a, h): """Given length of a side and high return area for a triangle. """
def triangle_area(a, h): """Given length of a side and high return area for a triangle. >>> triangle_area(5, 3) 7.5 """ return a * h / 2.0
python
HumanEval/46
fib4
code_generation
[ [ "5", "4" ], [ "8", "28" ], [ "10", "104" ], [ "12", "386" ] ]
null
[ [ "5", "4" ], [ "6", "8" ], [ "7", "14" ] ]
[]
The Fib4 number sequence is a sequence similar to the Fibbonacci sequnece that's defined as follows: fib4(0) -> 0 fib4(1) -> 0 fib4(2) -> 2 fib4(3) -> 0 fib4(n) -> fib4(n-1) + fib4(n-2) + fib4(n-3) + fib4(n-4). Please write a function to efficiently compute the n-th element of the fib4 number sequence. Do not use recursion.
HumanEval
The Fib4 number sequence is a sequence similar to the Fibbonacci sequnece that's defined as follows: fib4(0) -> 0 fib4(1) -> 0 fib4(2) -> 2 fib4(3) -> 0 fib4(n) -> fib4(n-1) + fib4(n-2) + fib4(n-3) + fib4(n-4). Please write a function to efficiently compute the n-th element of the fib4 number sequence. Do not use recursion. >>> fib4(5) 4 >>> fib4(6) 8 >>> fib4(7) 14
[]
def fib4(n: int): """The Fib4 number sequence is a sequence similar to the Fibbonacci sequnece that's defined as follows: fib4(0) -> 0 fib4(1) -> 0 fib4(2) -> 2 fib4(3) -> 0 fib4(n) -> fib4(n-1) + fib4(n-2) + fib4(n-3) + fib4(n-4). Please write a function to efficiently compute the n-th element of the fib4 number sequence. Do not use recursion. >>> fib4(5) 4 >>> fib4(6) 8 >>> fib4(7) 14 """
def fib4(n: int): """The Fib4 number sequence is a sequence similar to the Fibbonacci sequnece that's defined as follows: fib4(0) -> 0 fib4(1) -> 0 fib4(2) -> 2 fib4(3) -> 0 fib4(n) -> fib4(n-1) + fib4(n-2) + fib4(n-3) + fib4(n-4). Please write a function to efficiently compute the n-th element of the fib4 number sequence. Do not use recursion. >>> fib4(5) 4 >>> fib4(6) 8 >>> fib4(7) 14 """ results = [0, 0, 2, 0] if n < 4: return results[n] for _ in range(4, n + 1): results.append(results[-1] + results[-2] + results[-3] + results[-4]) results.pop(0) return results[-1]
python
HumanEval/47
median
code_generation
[ [ "[3, 1, 2, 4, 5]", "3" ], [ "[-10, 4, 6, 1000, 10, 20]", "8.0" ], [ "[5]", "5" ], [ "[6, 5]", "5.5" ], [ "[8, 1, 3, 9, 9, 2, 7]", "7" ] ]
null
[ [ "[3, 1, 2, 4, 5]", "3" ], [ "[-10, 4, 6, 1000, 10, 20]", "15.0" ] ]
[]
Return median of elements in the list l.
HumanEval
Return median of elements in the list l.
[]
def median(l: list): """Return median of elements in the list l. """
def median(l: list): """Return median of elements in the list l. >>> median([3, 1, 2, 4, 5]) 3 >>> median([-10, 4, 6, 1000, 10, 20]) 15.0 """ l = sorted(l) if len(l) % 2 == 1: return l[len(l) // 2] else: return (l[len(l) // 2 - 1] + l[len(l) // 2]) / 2.0
python
HumanEval/48
is_palindrome
code_generation
[ [ "''", "True" ], [ "'aba'", "True" ], [ "'aaaaa'", "True" ], [ "'zbcd'", "False" ], [ "'xywyx'", "True" ], [ "'xywyz'", "False" ], [ "'xywzx'", "False" ] ]
null
[ [ "''", "True" ], [ "'aba'", "True" ], [ "'aaaaa'", "True" ], [ "'zbcd'", "False" ] ]
[]
Checks if given string is a palindrome
HumanEval
Checks if given string is a palindrome
[]
def is_palindrome(text: str): """ Checks if given string is a palindrome """
def is_palindrome(text: str): """ Checks if given string is a palindrome >>> is_palindrome('') True >>> is_palindrome('aba') True >>> is_palindrome('aaaaa') True >>> is_palindrome('zbcd') False """ for i in range(len(text)): if text[i] != text[len(text) - 1 - i]: return False return True
python
HumanEval/49
modp
code_generation
[ [ "3, 5", "3" ], [ "1101, 101", "2" ], [ "0, 101", "1" ], [ "3, 11", "8" ], [ "100, 101", "1" ], [ "30, 5", "4" ], [ "31, 5", "3" ] ]
null
[ [ "3, 5", "3" ], [ "1101, 101", "2" ], [ "0, 101", "1" ], [ "3, 11", "8" ], [ "100, 101", "1" ] ]
[]
Return 2^n modulo p (be aware of numerics).
HumanEval
Return 2^n modulo p (be aware of numerics).
[]
def modp(n: int, p: int): """Return 2^n modulo p (be aware of numerics). """
def modp(n: int, p: int): """Return 2^n modulo p (be aware of numerics). >>> modp(3, 5) 3 >>> modp(1101, 101) 2 >>> modp(0, 101) 1 >>> modp(3, 11) 8 >>> modp(100, 101) 1 """ ret = 1 for i in range(n): ret = (2 * ret) % p return ret
python
HumanEval/50
decode_shift
code_generation
[ [ "\"nppetuavkhytds\"", "\"ikkzopvqfctoyn\"" ], [ "\"jkwevzwwetoiui\"", "\"efrzqurrzojdpd\"" ], [ "\"deqhgbmrgyvolvllvgu\"", "\"yzlcbwhmbtqjgqggqbp\"" ], [ "\"adwtpwmzzsba\"", "\"vyrokrhuunwv\"" ], [ "\"kviyfxcqqk\"", "\"fqdtasxllf\"" ], [ "\"owuxsmtkqyi\"", "\"jrpsnhofltd\"" ], [ "\"nnmfgsupnnlfnyke\"", "\"iihabnpkiigaitfz\"" ], [ "\"neklmdclmzoro\"", "\"izfghyxghujmj\"" ], [ "\"lesnecsgpsgcya\"", "\"gznizxnbknbxtv\"" ], [ "\"oxbtwcbwsxinxvdwir\"", "\"jsworxwrnsdisqyrdm\"" ], [ "\"sdghpnyvoqrwpzgvdu\"", "\"nybckitqjlmrkubqyp\"" ], [ "\"jyzljgmjrbquen\"", "\"etugebhemwlpzi\"" ], [ "\"zgyrlfbwabpjhperjslh\"", "\"ubtmgawrvwkeckzmengc\"" ], [ "\"qleffvhomvtyngciggde\"", "\"lgzaaqcjhqotibxdbbyz\"" ], [ "\"qqpicuvmrtkj\"", "\"llkdxpqhmofe\"" ], [ "\"jyyevmecuetxqrirfd\"", "\"ettzqhzxpzoslmdmay\"" ], [ "\"lmbsrqvjevdtb\"", "\"ghwnmlqezqyow\"" ], [ "\"whxcodekelxlmln\"", "\"rcsxjyzfzgsghgi\"" ], [ "\"delrtygeoyvml\"", "\"yzgmotbzjtqhg\"" ], [ "\"apdqbcrttlq\"", "\"vkylwxmoogl\"" ], [ "\"xttskzvkfh\"", "\"soonfuqfac\"" ], [ "\"olbwqqdnru\"", "\"jgwrllyimp\"" ], [ "\"ehdpgbpcwbqsqr\"", "\"zcykbwkxrwlnlm\"" ], [ "\"oxbdypniamafgtsz\"", "\"jswytkidvhvabonu\"" ], [ "\"sdnuydcckyvllunfbxi\"", "\"nyiptyxxftqggpiawsd\"" ], [ "\"antvcacedbucqjmhl\"", "\"vioqxvxzywpxlehcg\"" ], [ "\"zogbormycllavatve\"", "\"ujbwjmhtxggvqvoqz\"" ], [ "\"fuueutygaxwywovpnigy\"", "\"appzpotbvsrtrjqkidbt\"" ], [ "\"jknughmjbqvtcrulb\"", "\"efipbchewlqoxmpgw\"" ], [ "\"xbvxtynbqwz\"", "\"swqsotiwlru\"" ], [ "\"mgctjkezbtnklcsw\"", "\"hbxoefzuwoifgxnr\"" ], [ "\"fmelllajoemkowluz\"", "\"ahzgggvejzhfjrgpu\"" ], [ "\"ptozvzdtyvnhzime\"", "\"kojuquyotqicudhz\"" ], [ "\"xxhgplwbzs\"", "\"sscbkgrwun\"" ], [ "\"rfzoarauxuka\"", "\"maujvmvpspfv\"" ], [ "\"twqnkxildqtbrbjwyqrh\"", "\"orlifsdgylowmwertlmc\"" ], [ "\"eildvqeupsl\"", "\"zdgyqlzpkng\"" ], [ "\"pnzptdzfhzxpn\"", "\"kiukoyuacuski\"" ], [ "\"hbmzwirdoar\"", "\"cwhurdmyjvm\"" ], [ "\"gaqxkjkpnwkca\"", "\"bvlsfefkirfxv\"" ], [ "\"xddhfaftiziqebsa\"", "\"syycavaodudlzwnv\"" ], [ "\"ydyqdhblfckp\"", "\"tytlycwgaxfk\"" ], [ "\"ymypgwmwogoudeq\"", "\"thtkbrhrjbjpyzl\"" ], [ "\"unvmuxgbdyhchso\"", "\"piqhpsbwytcxcnj\"" ], [ "\"dhghjsovcb\"", "\"ycbcenjqxw\"" ], [ "\"piinwbmppf\"", "\"kddirwhkka\"" ], [ "\"zvyoceomaxjcgwprqm\"", "\"uqtjxzjhvsexbrkmlh\"" ], [ "\"eijmnrfqtqudyv\"", "\"zdehimalolpytq\"" ], [ "\"qpeqklfmwnry\"", "\"lkzlfgahrimt\"" ], [ "\"fwnkdnyqbo\"", "\"arifyitlwj\"" ], [ "\"smcxegzdxbfd\"", "\"nhxszbuysway\"" ], [ "\"jvtkgaecmqnpszjvf\"", "\"eqofbvzxhliknueqa\"" ], [ "\"aurjwvkebktdv\"", "\"vpmerqfzwfoyq\"" ], [ "\"nfmmmhjeliakugh\"", "\"iahhhcezgdvfpbc\"" ], [ "\"eyfxptmpshohi\"", "\"ztaskohkncjcd\"" ], [ "\"glaoltrkxsmxspdvow\"", "\"bgvjgomfsnhsnkyqjr\"" ], [ "\"zwyupdxanebym\"", "\"urtpkysvizwth\"" ], [ "\"xkoigfpvcvqcxcgeoq\"", "\"sfjdbakqxqlxsxbzjl\"" ], [ "\"fgizxalyjcpkvkt\"", "\"abdusvgtexkfqfo\"" ], [ "\"zirsuhlzwi\"", "\"udmnpcgurd\"" ], [ "\"zhwqbyhkbqeomarlldcb\"", "\"ucrlwtcfwlzjhvmggyxw\"" ], [ "\"rvshqbrvsxnjfjakul\"", "\"mqnclwmqnsieaevfpg\"" ], [ "\"nktgcnuxplhfsm\"", "\"ifobxipskgcanh\"" ], [ "\"baoiqymypxkvlrn\"", "\"wvjdlthtksfqgmi\"" ], [ "\"nwagelwecafiphlj\"", "\"irvbzgrzxvadkcge\"" ], [ "\"kbqtmzbujxumptcvyl\"", "\"fwlohuwpesphkoxqtg\"" ], [ "\"dujvyrdslwf\"", "\"ypeqtmyngra\"" ], [ "\"vujolzbqoqekvv\"", "\"qpejguwljlzfqq\"" ], [ "\"hbbdoumleckjwhws\"", "\"cwwyjphgzxfercrn\"" ], [ "\"aykhykkfnxckhmzndki\"", "\"vtfctffaisxfchuiyfd\"" ], [ "\"wpidhybggvempzrfa\"", "\"rkdyctwbbqzhkumav\"" ], [ "\"dwgrdroeuiduby\"", "\"yrbmymjzpdypwt\"" ], [ "\"yptrachqjtgrgqxy\"", "\"tkomvxcleobmblst\"" ], [ "\"gjragaaocfbadfbeebky\"", "\"bemvbvvjxawvyawzzwft\"" ], [ "\"rnisigwzqqshj\"", "\"midndbrullnce\"" ], [ "\"gzivhmjtyysqsuqubbur\"", "\"budqcheottnlnplpwwpm\"" ], [ "\"gfmeiuvbyuuiiflplahw\"", "\"bahzdpqwtppddagkgvcr\"" ], [ "\"iczpwzppirpxfm\"", "\"dxukrukkdmksah\"" ], [ "\"hwtxjblmlsikphbivd\"", "\"crosewghgndfkcwdqy\"" ], [ "\"fwzjefnnnjwhv\"", "\"aruezaiiiercq\"" ], [ "\"sysvhbbqkh\"", "\"ntnqcwwlfc\"" ], [ "\"lbwiwpvlcdtvh\"", "\"gwrdrkqgxyoqc\"" ], [ "\"rlehhmhevv\"", "\"mgzcchczqq\"" ], [ "\"qtrfjsocbsldii\"", "\"lomaenjxwngydd\"" ], [ "\"eszhonrsle\"", "\"znucjimngz\"" ], [ "\"jvzxprqiyfqfj\"", "\"equskmldtalae\"" ], [ "\"wdzasevrfyobkbro\"", "\"ryuvnzqmatjwfwmj\"" ], [ "\"hzvhjetyyntxiplf\"", "\"cuqcezottiosdkga\"" ], [ "\"yfskmymfdjqooty\"", "\"tanfhthayeljjot\"" ], [ "\"rrtepprngbbv\"", "\"mmozkkmibwwq\"" ], [ "\"zsqaqzsbxtwpqa\"", "\"unlvlunwsorklv\"" ], [ "\"kneyiarobkgl\"", "\"fiztdvmjwfbg\"" ], [ "\"xxbudxuwlhi\"", "\"sswpysprgcd\"" ], [ "\"fetivyuynb\"", "\"azodqtptiw\"" ], [ "\"syswumgxpgxmcwzgedq\"", "\"ntnrphbskbshxrubzyl\"" ], [ "\"xychwdsfyfoly\"", "\"stxcrynatajgt\"" ], [ "\"nfwrujwavgavutrxuzsg\"", "\"iarmpervqbvqpomspunb\"" ], [ "\"vuhhhndgmzkwplolb\"", "\"qpccciybhufrkgjgw\"" ], [ "\"fwqxfhbqjbgryci\"", "\"arlsacwlewbmtxd\"" ], [ "\"amzcptlnzkor\"", "\"vhuxkogiufjm\"" ] ]
null
[]
[]
returns encoded string by shifting every character by 5 in the alphabet. return "".join([chr(((ord(ch) + 5 - ord("a")) % 26) + ord("a")) for ch in s]) def decode_shift(s: str): takes as input string encoded with encode_shift function. Returns decoded string.
HumanEval
returns encoded string by shifting every character by 5 in the alphabet.
[]
def encode_shift(s: str): """ returns encoded string by shifting every character by 5 in the alphabet. """ return "".join([chr(((ord(ch) + 5 - ord("a")) % 26) + ord("a")) for ch in s]) def decode_shift(s: str): """ takes as input string encoded with encode_shift function. Returns decoded string. """
def encode_shift(s: str): """ returns encoded string by shifting every character by 5 in the alphabet. """ return "".join([chr(((ord(ch) + 5 - ord("a")) % 26) + ord("a")) for ch in s]) def decode_shift(s: str): """ takes as input string encoded with encode_shift function. Returns decoded string. """ return "".join([chr(((ord(ch) - 5 - ord("a")) % 26) + ord("a")) for ch in s])
python
HumanEval/51
remove_vowels
code_generation
[ [ "''", "''" ], [ "\"abcdef\\nghijklm\"", "'bcdf\\nghjklm'" ], [ "'fedcba'", "'fdcb'" ], [ "'eeeee'", "''" ], [ "'acBAA'", "'cB'" ], [ "'EcBOO'", "'cB'" ], [ "'ybcd'", "'ybcd'" ] ]
null
[ [ "''", "''" ], [ "\"abcdef\\nghijklm\"", "'bcdf\\nghjklm'" ], [ "'abcdef'", "'bcdf'" ], [ "'aaaaa'", "''" ], [ "'aaBAA'", "'B'" ], [ "'zbcd'", "'zbcd'" ] ]
[]
remove_vowels is a function that takes string and returns string without vowels.
HumanEval
remove_vowels is a function that takes string and returns string without vowels.
[]
def remove_vowels(text): """ remove_vowels is a function that takes string and returns string without vowels. """
def remove_vowels(text): """ remove_vowels is a function that takes string and returns string without vowels. >>> remove_vowels('') '' >>> remove_vowels("abcdef\nghijklm") 'bcdf\nghjklm' >>> remove_vowels('abcdef') 'bcdf' >>> remove_vowels('aaaaa') '' >>> remove_vowels('aaBAA') 'B' >>> remove_vowels('zbcd') 'zbcd' """ return "".join([s for s in text if s.lower() not in ["a", "e", "i", "o", "u"]])
python
HumanEval/52
below_threshold
code_generation
[]
null
[ [ "[1, 2, 4, 10], 100", "True" ], [ "[1, 20, 4, 10], 5", "False" ] ]
[]
Return True if all numbers in the list l are below threshold t.
HumanEval
Return True if all numbers in the list l are below threshold t.
[]
def below_threshold(l: list, t: int): """Return True if all numbers in the list l are below threshold t. """
def below_threshold(l: list, t: int): """Return True if all numbers in the list l are below threshold t. >>> below_threshold([1, 2, 4, 10], 100) True >>> below_threshold([1, 20, 4, 10], 5) False """ for e in l: if e >= t: return False return True
python
HumanEval/53
add
code_generation
[ [ "0, 1", "1" ], [ "1, 0", "1" ], [ "2, 3", "5" ], [ "5, 7", "12" ], [ "7, 5", "12" ] ]
null
[ [ "2, 3", "5" ], [ "5, 7", "12" ] ]
[]
Add two numbers x and y
HumanEval
Add two numbers x and y
[]
def add(x: int, y: int): """Add two numbers x and y """
def add(x: int, y: int): """Add two numbers x and y >>> add(2, 3) 5 >>> add(5, 7) 12 """ return x + y
python
HumanEval/54
same_chars
code_generation
[ [ "'eabcdzzzz', 'dddzzzzzzzddeddabc'", "True" ], [ "'abcd', 'dddddddabc'", "True" ], [ "'dddddddabc', 'abcd'", "True" ], [ "'eabcd', 'dddddddabc'", "False" ], [ "'abcd', 'dddddddabcf'", "False" ], [ "'eabcdzzzz', 'dddzzzzzzzddddabc'", "False" ], [ "'aabb', 'aaccc'", "False" ] ]
null
[ [ "'eabcdzzzz', 'dddzzzzzzzddeddabc'", "True" ], [ "'abcd', 'dddddddabc'", "True" ], [ "'dddddddabc', 'abcd'", "True" ], [ "'eabcd', 'dddddddabc'", "False" ], [ "'abcd', 'dddddddabce'", "False" ], [ "'eabcdzzzz', 'dddzzzzzzzddddabc'", "False" ] ]
[]
Check if two words have the same characters.
HumanEval
Check if two words have the same characters.
[]
def same_chars(s0: str, s1: str): """ Check if two words have the same characters. """
def same_chars(s0: str, s1: str): """ Check if two words have the same characters. >>> same_chars('eabcdzzzz', 'dddzzzzzzzddeddabc') True >>> same_chars('abcd', 'dddddddabc') True >>> same_chars('dddddddabc', 'abcd') True >>> same_chars('eabcd', 'dddddddabc') False >>> same_chars('abcd', 'dddddddabce') False >>> same_chars('eabcdzzzz', 'dddzzzzzzzddddabc') False """ return set(s0) == set(s1)
python
HumanEval/55
fib
code_generation
[ [ "10", "55" ], [ "1", "1" ], [ "8", "21" ], [ "11", "89" ], [ "12", "144" ] ]
null
[ [ "10", "55" ], [ "1", "1" ], [ "8", "21" ] ]
[]
Return n-th Fibonacci number.
HumanEval
Return n-th Fibonacci number.
[]
def fib(n: int): """Return n-th Fibonacci number. """
def fib(n: int): """Return n-th Fibonacci number. >>> fib(10) 55 >>> fib(1) 1 >>> fib(8) 21 """ if n == 0: return 0 if n == 1: return 1 return fib(n - 1) + fib(n - 2)
python
HumanEval/56
correct_bracketing
code_generation
[]
null
[ [ "\"<\"", "False" ], [ "\"<>\"", "True" ], [ "\"<<><>>\"", "True" ], [ "\"><<>\"", "False" ] ]
[]
brackets is a string of "<" and ">". return True if every opening bracket has a corresponding closing bracket.
HumanEval
brackets is a string of "<" and ">". return True if every opening bracket has a corresponding closing bracket.
[]
def correct_bracketing(brackets: str): """ brackets is a string of "<" and ">". return True if every opening bracket has a corresponding closing bracket. """
def correct_bracketing(brackets: str): """ brackets is a string of "<" and ">". return True if every opening bracket has a corresponding closing bracket. >>> correct_bracketing("<") False >>> correct_bracketing("<>") True >>> correct_bracketing("<<><>>") True >>> correct_bracketing("><<>") False """ depth = 0 for b in brackets: if b == "<": depth += 1 else: depth -= 1 if depth < 0: return False return depth == 0
python
HumanEval/57
monotonic
code_generation
[ [ "[1, 2, 4, 10]", "True" ], [ "[1, 2, 4, 20]", "True" ], [ "[1, 20, 4, 10]", "False" ], [ "[4, 1, 0, -10]", "True" ], [ "[4, 1, 1, 0]", "True" ], [ "[1, 2, 3, 2, 5, 60]", "False" ], [ "[1, 2, 3, 4, 5, 60]", "True" ], [ "[9, 9, 9, 9]", "True" ] ]
null
[ [ "[1, 2, 4, 20]", "True" ], [ "[1, 20, 4, 10]", "False" ], [ "[4, 1, 0, -10]", "True" ] ]
[]
Return True is list elements are monotonically increasing or decreasing.
HumanEval
Return True is list elements are monotonically increasing or decreasing.
[]
def monotonic(l: list): """Return True is list elements are monotonically increasing or decreasing. """
def monotonic(l: list): """Return True is list elements are monotonically increasing or decreasing. >>> monotonic([1, 2, 4, 20]) True >>> monotonic([1, 20, 4, 10]) False >>> monotonic([4, 1, 0, -10]) True """ if l == sorted(l) or l == sorted(l, reverse=True): return True return False
python
HumanEval/58
common
code_generation
[ [ "[1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121]", "[1, 5, 653]" ], [ "[5, 3, 2, 8], [3, 2]", "[2, 3]" ], [ "[4, 3, 2, 8], [3, 2, 4]", "[2, 3, 4]" ], [ "[4, 3, 2, 8], []", "[]" ] ]
null
[ [ "[1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121]", "[1, 5, 653]" ], [ "[5, 3, 2, 8], [3, 2]", "[2, 3]" ] ]
[]
Return sorted unique common elements for two lists.
HumanEval
Return sorted unique common elements for two lists.
[]
def common(l1: list, l2: list): """Return sorted unique common elements for two lists. """
def common(l1: list, l2: list): """Return sorted unique common elements for two lists. >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121]) [1, 5, 653] >>> common([5, 3, 2, 8], [3, 2]) [2, 3] """ ret = set() for e1 in l1: for e2 in l2: if e1 == e2: ret.add(e1) return sorted(list(ret))
python
HumanEval/59
largest_prime_factor
code_generation
[ [ "15", "5" ], [ "27", "3" ], [ "63", "7" ], [ "330", "11" ], [ "13195", "29" ] ]
null
[ [ "13195", "29" ], [ "2048", "2" ] ]
[]
Return the largest prime factor of n. Assume n > 1 and is not a prime.
HumanEval
Return the largest prime factor of n. Assume n > 1 and is not a prime.
[]
def largest_prime_factor(n: int): """Return the largest prime factor of n. Assume n > 1 and is not a prime. """
def largest_prime_factor(n: int): """Return the largest prime factor of n. Assume n > 1 and is not a prime. >>> largest_prime_factor(13195) 29 >>> largest_prime_factor(2048) 2 """ def is_prime(k): if k < 2: return False for i in range(2, k - 1): if k % i == 0: return False return True largest = 1 for j in range(2, n + 1): if n % j == 0 and is_prime(j): largest = max(largest, j) return largest
python
HumanEval/60
sum_to_n
code_generation
[ [ "1", "1" ], [ "6", "21" ], [ "11", "66" ], [ "30", "465" ], [ "100", "5050" ] ]
null
[ [ "30", "465" ], [ "100", "5050" ], [ "5", "15" ], [ "10", "55" ], [ "1", "1" ] ]
[]
sum_to_n is a function that sums numbers from 1 to n.
HumanEval
sum_to_n is a function that sums numbers from 1 to n.
[]
def sum_to_n(n: int): """sum_to_n is a function that sums numbers from 1 to n. """
def sum_to_n(n: int): """sum_to_n is a function that sums numbers from 1 to n. >>> sum_to_n(30) 465 >>> sum_to_n(100) 5050 >>> sum_to_n(5) 15 >>> sum_to_n(10) 55 >>> sum_to_n(1) 1 """ return sum(range(n + 1))
python
HumanEval/61
correct_bracketing
code_generation
[]
null
[ [ "\"(\"", "False" ], [ "\"()\"", "True" ], [ "\"(()())\"", "True" ], [ "\")(()\"", "False" ] ]
[]
brackets is a string of "(" and ")". return True if every opening bracket has a corresponding closing bracket.
HumanEval
brackets is a string of "(" and ")". return True if every opening bracket has a corresponding closing bracket.
[]
def correct_bracketing(brackets: str): """ brackets is a string of "(" and ")". return True if every opening bracket has a corresponding closing bracket. """
def correct_bracketing(brackets: str): """ brackets is a string of "(" and ")". return True if every opening bracket has a corresponding closing bracket. >>> correct_bracketing("(") False >>> correct_bracketing("()") True >>> correct_bracketing("(()())") True >>> correct_bracketing(")(()") False """ depth = 0 for b in brackets: if b == "(": depth += 1 else: depth -= 1 if depth < 0: return False return depth == 0
python
HumanEval/62
derivative
code_generation
[ [ "[3, 1, 2, 4, 5]", "[1, 4, 12, 20]" ], [ "[1, 2, 3]", "[2, 6]" ], [ "[3, 2, 1]", "[2, 2]" ], [ "[3, 2, 1, 0, 4]", "[2, 2, 0, 16]" ], [ "[1]", "[]" ] ]
null
[ [ "[3, 1, 2, 4, 5]", "[1, 4, 12, 20]" ], [ "[1, 2, 3]", "[2, 6]" ] ]
[]
xs represent coefficients of a polynomial. xs[0] + xs[1] * x + xs[2] * x^2 + .... Return derivative of this polynomial in the same form.
HumanEval
xs represent coefficients of a polynomial. xs[0] + xs[1] * x + xs[2] * x^2 + .... Return derivative of this polynomial in the same form.
[]
def derivative(xs: list): """ xs represent coefficients of a polynomial. xs[0] + xs[1] * x + xs[2] * x^2 + .... Return derivative of this polynomial in the same form. """
def derivative(xs: list): """ xs represent coefficients of a polynomial. xs[0] + xs[1] * x + xs[2] * x^2 + .... Return derivative of this polynomial in the same form. >>> derivative([3, 1, 2, 4, 5]) [1, 4, 12, 20] >>> derivative([1, 2, 3]) [2, 6] """ return [(i * x) for i, x in enumerate(xs)][1:]
python
HumanEval/63
fibfib
code_generation
[ [ "2", "1" ], [ "1", "0" ], [ "5", "4" ], [ "8", "24" ], [ "10", "81" ], [ "12", "274" ], [ "14", "927" ] ]
null
[ [ "1", "0" ], [ "5", "4" ], [ "8", "24" ] ]
[]
The FibFib number sequence is a sequence similar to the Fibbonacci sequnece that's defined as follows: fibfib(0) == 0 fibfib(1) == 0 fibfib(2) == 1 fibfib(n) == fibfib(n-1) + fibfib(n-2) + fibfib(n-3). Please write a function to efficiently compute the n-th element of the fibfib number sequence.
HumanEval
The FibFib number sequence is a sequence similar to the Fibbonacci sequnece that's defined as follows: fibfib(0) == 0 fibfib(1) == 0 fibfib(2) == 1 fibfib(n) == fibfib(n-1) + fibfib(n-2) + fibfib(n-3). Please write a function to efficiently compute the n-th element of the fibfib number sequence.
[]
def fibfib(n: int): """The FibFib number sequence is a sequence similar to the Fibbonacci sequnece that's defined as follows: fibfib(0) == 0 fibfib(1) == 0 fibfib(2) == 1 fibfib(n) == fibfib(n-1) + fibfib(n-2) + fibfib(n-3). Please write a function to efficiently compute the n-th element of the fibfib number sequence. """
def fibfib(n: int): """The FibFib number sequence is a sequence similar to the Fibbonacci sequnece that's defined as follows: fibfib(0) == 0 fibfib(1) == 0 fibfib(2) == 1 fibfib(n) == fibfib(n-1) + fibfib(n-2) + fibfib(n-3). Please write a function to efficiently compute the n-th element of the fibfib number sequence. >>> fibfib(1) 0 >>> fibfib(5) 4 >>> fibfib(8) 24 """ if n == 0: return 0 if n == 1: return 0 if n == 2: return 1 return fibfib(n - 1) + fibfib(n - 2) + fibfib(n - 3)
python
HumanEval/64
vowels_count
code_generation
[ [ "\"abcde\"", "2" ], [ "\"Alone\"", "3" ], [ "\"key\"", "2" ], [ "\"bye\"", "1" ], [ "\"keY\"", "2" ], [ "\"bYe\"", "1" ], [ "\"ACEDY\"", "3" ] ]
null
[ [ "\"abcde\"", "2" ], [ "\"ACEDY\"", "3" ] ]
[]
FIX = Add more test cases. def vowels_count(s): Write a function vowels_count which takes a string representing a word as input and returns the number of vowels in the string. Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a vowel, but only when it is at the end of the given word.
HumanEval
Add more test cases.
[]
FIX = """ Add more test cases. """ def vowels_count(s): """Write a function vowels_count which takes a string representing a word as input and returns the number of vowels in the string. Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a vowel, but only when it is at the end of the given word. """
FIX = """ Add more test cases. """ def vowels_count(s): """Write a function vowels_count which takes a string representing a word as input and returns the number of vowels in the string. Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a vowel, but only when it is at the end of the given word. Example: >>> vowels_count("abcde") 2 >>> vowels_count("ACEDY") 3 """ vowels = "aeiouAEIOU" n_vowels = sum(c in vowels for c in s) if s[-1] == 'y' or s[-1] == 'Y': n_vowels += 1 return n_vowels
python
HumanEval/65
circular_shift
code_generation
[ [ "100, 2", "\"001\"" ], [ "12, 2", "\"12\"" ], [ "97, 8", "\"79\"" ], [ "12, 1", "\"21\"" ], [ "11, 101", "\"11\"" ] ]
null
[ [ "12, 1", "\"21\"" ], [ "12, 2", "\"12\"" ] ]
[]
Circular shift the digits of the integer x, shift the digits right by shift and return the result as a string. If shift > number of digits, return digits reversed.
HumanEval
Circular shift the digits of the integer x, shift the digits right by shift and return the result as a string. If shift > number of digits, return digits reversed.
[]
def circular_shift(x, shift): """Circular shift the digits of the integer x, shift the digits right by shift and return the result as a string. If shift > number of digits, return digits reversed. """
def circular_shift(x, shift): """Circular shift the digits of the integer x, shift the digits right by shift and return the result as a string. If shift > number of digits, return digits reversed. >>> circular_shift(12, 1) "21" >>> circular_shift(12, 2) "12" """ s = str(x) if shift > len(s): return s[::-1] else: return s[len(s) - shift:] + s[:len(s) - shift]
python
HumanEval/66
digitSum
code_generation
[ [ "\"\"", "0" ], [ "\"abAB\"", "131" ], [ "\"abcCd\"", "67" ], [ "\"helloE\"", "69" ], [ "\"woArBld\"", "131" ], [ "\"aAaaaXa\"", "153" ], [ "\" How are yOu?\"", "151" ], [ "\"You arE Very Smart\"", "327" ] ]
null
[ [ "\"\"", "0" ], [ "\"abAB\"", "131" ], [ "\"abcCd\"", "67" ], [ "\"helloE\"", "69" ], [ "\"woArBld\"", "131" ], [ "\"aAaaaXa\"", "153" ] ]
[]
Task Write a function that takes a string as input and returns the sum of the upper characters only' ASCII codes.
HumanEval
Task Write a function that takes a string as input and returns the sum of the upper characters only' ASCII codes.
[]
def digitSum(s): """Task Write a function that takes a string as input and returns the sum of the upper characters only' ASCII codes. """
def digitSum(s): """Task Write a function that takes a string as input and returns the sum of the upper characters only' ASCII codes. Examples: digitSum("") => 0 digitSum("abAB") => 131 digitSum("abcCd") => 67 digitSum("helloE") => 69 digitSum("woArBld") => 131 digitSum("aAaaaXa") => 153 """ if s == "": return 0 return sum(ord(char) if char.isupper() else 0 for char in s)
python
HumanEval/67
fruit_distribution
code_generation
[ [ "\"5 apples and 6 oranges\", 19", "8" ], [ "\"5 apples and 6 oranges\", 21", "10" ], [ "\"0 apples and 1 oranges\", 3", "2" ], [ "\"1 apples and 0 oranges\", 3", "2" ], [ "\"2 apples and 3 oranges\", 100", "95" ], [ "\"2 apples and 3 oranges\", 5", "0" ], [ "\"1 apples and 100 oranges\", 120", "19" ] ]
null
[ [ "\"5 apples and 6 oranges\", 19", "19 - 5 - 6 = 8" ], [ "\"0 apples and 1 oranges\",3", "3 - 0 - 1 = 2" ], [ "\"2 apples and 3 oranges\", 100", "100 - 2 - 3 = 95" ], [ "\"100 apples and 1 oranges\",120", "120 - 100 - 1 = 19" ] ]
[]
In this task, you will be given a string that represents a number of apples and oranges that are distributed in a basket of fruit this basket contains apples, oranges, and mango fruits. Given the string that represents the total number of the oranges and apples and an integer that represent the total number of the fruits in the basket return the number of the mango fruits in the basket. for examble: fruit_distribution("5 apples and 6 oranges", 19) ->19 - 5 - 6 = 8 fruit_distribution("0 apples and 1 oranges",3) -> 3 - 0 - 1 = 2 fruit_distribution("2 apples and 3 oranges", 100) -> 100 - 2 - 3 = 95 fruit_distribution("100 apples and 1 oranges",120) -> 120 - 100 - 1 = 19
HumanEval
In this task, you will be given a string that represents a number of apples and oranges that are distributed in a basket of fruit this basket contains apples, oranges, and mango fruits. Given the string that represents the total number of the oranges and apples and an integer that represent the total number of the fruits in the basket return the number of the mango fruits in the basket.
[]
def fruit_distribution(s,n): """ In this task, you will be given a string that represents a number of apples and oranges that are distributed in a basket of fruit this basket contains apples, oranges, and mango fruits. Given the string that represents the total number of the oranges and apples and an integer that represent the total number of the fruits in the basket return the number of the mango fruits in the basket. """
def fruit_distribution(s,n): """ In this task, you will be given a string that represents a number of apples and oranges that are distributed in a basket of fruit this basket contains apples, oranges, and mango fruits. Given the string that represents the total number of the oranges and apples and an integer that represent the total number of the fruits in the basket return the number of the mango fruits in the basket. for examble: fruit_distribution("5 apples and 6 oranges", 19) ->19 - 5 - 6 = 8 fruit_distribution("0 apples and 1 oranges",3) -> 3 - 0 - 1 = 2 fruit_distribution("2 apples and 3 oranges", 100) -> 100 - 2 - 3 = 95 fruit_distribution("100 apples and 1 oranges",120) -> 120 - 100 - 1 = 19 """ lis = list() for i in s.split(' '): if i.isdigit(): lis.append(int(i)) return n - sum(lis)
python
HumanEval/68
pluck
code_generation
[ [ "[4,2,3]", "[2, 1]" ], [ "[1,2,3]", "[2, 1]" ], [ "[]", "[]" ], [ "[5, 0, 3, 0, 4, 2]", "[0, 1]" ], [ "[1, 2, 3, 0, 5, 3]", "[0, 3]" ], [ "[5, 4, 8, 4 ,8]", "[4, 1]" ], [ "[7, 6, 7, 1]", "[6, 1]" ], [ "[7, 9, 7, 1]", "[]" ] ]
null
[ [ "[4,2,3]", "[2, 1]" ], [ "[1,2,3]", "[2, 1]" ], [ "[]", "[]" ], [ "[5, 0, 3, 0, 4, 2]", "[0, 1]" ] ]
[]
"Given an array representing a branch of a tree that has non-negative integer nodes your task is to pluck one of the nodes and return it. The plucked node should be the node with the smallest even value. If multiple nodes with the same smallest even value are found return the node that has smallest index. The plucked node should be returned in a list, [ smalest_value, its index ], If there are no even values or the given array is empty, return [].
HumanEval
"Given an array representing a branch of a tree that has non-negative integer nodes your task is to pluck one of the nodes and return it. The plucked node should be the node with the smallest even value. If multiple nodes with the same smallest even value are found return the node that has smallest index. The plucked node should be returned in a list, [ smalest_value, its index ], If there are no even values or the given array is empty, return [].
[]
def pluck(arr): """ "Given an array representing a branch of a tree that has non-negative integer nodes your task is to pluck one of the nodes and return it. The plucked node should be the node with the smallest even value. If multiple nodes with the same smallest even value are found return the node that has smallest index. The plucked node should be returned in a list, [ smalest_value, its index ], If there are no even values or the given array is empty, return []. """
def pluck(arr): """ "Given an array representing a branch of a tree that has non-negative integer nodes your task is to pluck one of the nodes and return it. The plucked node should be the node with the smallest even value. If multiple nodes with the same smallest even value are found return the node that has smallest index. The plucked node should be returned in a list, [ smalest_value, its index ], If there are no even values or the given array is empty, return []. Example 1: Input: [4,2,3] Output: [2, 1] Explanation: 2 has the smallest even value, and 2 has the smallest index. Example 2: Input: [1,2,3] Output: [2, 1] Explanation: 2 has the smallest even value, and 2 has the smallest index. Example 3: Input: [] Output: [] Example 4: Input: [5, 0, 3, 0, 4, 2] Output: [0, 1] Explanation: 0 is the smallest value, but there are two zeros, so we will choose the first zero, which has the smallest index. Constraints: * 1 <= nodes.length <= 10000 * 0 <= node.value """ if(len(arr) == 0): return [] evens = list(filter(lambda x: x%2 == 0, arr)) if(evens == []): return [] return [min(evens), arr.index(min(evens))]
python
HumanEval/69
search
code_generation
[ [ "[5, 5, 5, 5, 1]", "1" ], [ "[4, 1, 4, 1, 4, 4]", "4" ], [ "[3, 3]", "-1" ], [ "[8, 8, 8, 8, 8, 8, 8, 8]", "8" ], [ "[2, 3, 3, 2, 2]", "2" ], [ "[2, 7, 8, 8, 4, 8, 7, 3, 9, 6, 5, 10, 4, 3, 6, 7, 1, 7, 4, 10, 8, 1]", "1" ], [ "[3, 2, 8, 2]", "2" ], [ "[6, 7, 1, 8, 8, 10, 5, 8, 5, 3, 10]", "1" ], [ "[8, 8, 3, 6, 5, 6, 4]", "-1" ], [ "[6, 9, 6, 7, 1, 4, 7, 1, 8, 8, 9, 8, 10, 10, 8, 4, 10, 4, 10, 1, 2, 9, 5, 7, 9]", "1" ], [ "[1, 9, 10, 1, 3]", "1" ], [ "[6, 9, 7, 5, 8, 7, 5, 3, 7, 5, 10, 10, 3, 6, 10, 2, 8, 6, 5, 4, 9, 5, 3, 10]", "5" ], [ "[1]", "1" ], [ "[8, 8, 10, 6, 4, 3, 5, 8, 2, 4, 2, 8, 4, 6, 10, 4, 2, 1, 10, 2, 1, 1, 5]", "4" ], [ "[2, 10, 4, 8, 2, 10, 5, 1, 2, 9, 5, 5, 6, 3, 8, 6, 4, 10]", "2" ], [ "[1, 6, 10, 1, 6, 9, 10, 8, 6, 8, 7, 3]", "1" ], [ "[9, 2, 4, 1, 5, 1, 5, 2, 5, 7, 7, 7, 3, 10, 1, 5, 4, 2, 8, 4, 1, 9, 10, 7, 10, 2, 8, 10, 9, 4]", "4" ], [ "[2, 6, 4, 2, 8, 7, 5, 6, 4, 10, 4, 6, 3, 7, 8, 8, 3, 1, 4, 2, 2, 10, 7]", "4" ], [ "[9, 8, 6, 10, 2, 6, 10, 2, 7, 8, 10, 3, 8, 2, 6, 2, 3, 1]", "2" ], [ "[5, 5, 3, 9, 5, 6, 3, 2, 8, 5, 6, 10, 10, 6, 8, 4, 10, 7, 7, 10, 8]", "-1" ], [ "[10]", "-1" ], [ "[9, 7, 7, 2, 4, 7, 2, 10, 9, 7, 5, 7, 2]", "2" ], [ "[5, 4, 10, 2, 1, 1, 10, 3, 6, 1, 8]", "1" ], [ "[7, 9, 9, 9, 3, 4, 1, 5, 9, 1, 2, 1, 1, 10, 7, 5, 6, 7, 6, 7, 7, 6]", "1" ], [ "[3, 10, 10, 9, 2]", "-1" ] ]
null
[ [ "[4, 1, 2, 2, 3, 1]", "2" ], [ "[1, 2, 2, 3, 3, 3, 4, 4, 4]", "3" ], [ "[5, 5, 4, 4, 4]", "-1" ] ]
[]
HumanEval
You are given a non-empty list of positive integers. Return the greatest integer that is greater than zero, and has a frequency greater than or equal to the value of the integer itself. The frequency of an integer is the number of times it appears in the list. If no such a value exist, return -1. Examples: search([4, 1, 2, 2, 3, 1]) == 2 search([1, 2, 2, 3, 3, 3, 4, 4, 4]) == 3 search([5, 5, 4, 4, 4]) == -1
[]
def search(lst): ''' You are given a non-empty list of positive integers. Return the greatest integer that is greater than zero, and has a frequency greater than or equal to the value of the integer itself. The frequency of an integer is the number of times it appears in the list. If no such a value exist, return -1. Examples: search([4, 1, 2, 2, 3, 1]) == 2 search([1, 2, 2, 3, 3, 3, 4, 4, 4]) == 3 search([5, 5, 4, 4, 4]) == -1 '''
def search(lst): ''' You are given a non-empty list of positive integers. Return the greatest integer that is greater than zero, and has a frequency greater than or equal to the value of the integer itself. The frequency of an integer is the number of times it appears in the list. If no such a value exist, return -1. Examples: search([4, 1, 2, 2, 3, 1]) == 2 search([1, 2, 2, 3, 3, 3, 4, 4, 4]) == 3 search([5, 5, 4, 4, 4]) == -1 ''' frq = [0] * (max(lst) + 1) for i in lst: frq[i] += 1; ans = -1 for i in range(1, len(frq)): if frq[i] >= i: ans = i return ans
python
HumanEval/70
strange_sort_list
code_generation
[ [ "[1, 2, 3, 4]", "[1, 4, 2, 3]" ], [ "[5, 6, 7, 8, 9]", "[5, 9, 6, 8, 7]" ], [ "[1, 2, 3, 4, 5]", "[1, 5, 2, 4, 3]" ], [ "[5, 6, 7, 8, 9, 1]", "[1, 9, 5, 8, 6, 7]" ], [ "[5, 5, 5, 5]", "[5, 5, 5, 5]" ], [ "[]", "[]" ], [ "[1,2,3,4,5,6,7,8]", "[1, 8, 2, 7, 3, 6, 4, 5]" ], [ "[0,2,2,2,5,5,-5,-5]", "[-5, 5, -5, 5, 0, 2, 2, 2]" ], [ "[111111]", "[111111]" ] ]
null
[ [ "[1, 2, 3, 4]", "[1, 4, 2, 3]" ], [ "[5, 5, 5, 5]", "[5, 5, 5, 5]" ], [ "[]", "[]" ] ]
[]
HumanEval
Given list of integers, return list in strange order. Strange sorting, is when you start with the minimum value, then maximum of the remaining integers, then minimum and so on.
[]
def strange_sort_list(lst): ''' Given list of integers, return list in strange order. Strange sorting, is when you start with the minimum value, then maximum of the remaining integers, then minimum and so on. '''
def strange_sort_list(lst): ''' Given list of integers, return list in strange order. Strange sorting, is when you start with the minimum value, then maximum of the remaining integers, then minimum and so on. Examples: strange_sort_list([1, 2, 3, 4]) == [1, 4, 2, 3] strange_sort_list([5, 5, 5, 5]) == [5, 5, 5, 5] strange_sort_list([]) == [] ''' res, switch = [], True while lst: res.append(min(lst) if switch else max(lst)) lst.remove(res[-1]) switch = not switch return res
python
HumanEval/71
triangle_area
code_generation
[ [ "3, 4, 5", "6.00" ], [ "1, 2, 10", "-1" ], [ "4, 8, 5", "8.18" ], [ "2, 2, 2", "1.73" ], [ "1, 2, 3", "-1" ], [ "10, 5, 7", "16.25" ], [ "2, 6, 3", "-1" ], [ "1, 1, 1", "0.43" ], [ "2, 2, 10", "-1" ] ]
null
[ [ "3, 4, 5", "6.00" ], [ "1, 2, 10", "-1" ] ]
[]
HumanEval
Given the lengths of the three sides of a triangle. Return the area of the triangle rounded to 2 decimal points if the three sides form a valid triangle. Otherwise return -1 Three sides make a valid triangle when the sum of any two sides is greater than the third side.
[]
def triangle_area(a, b, c): ''' Given the lengths of the three sides of a triangle. Return the area of the triangle rounded to 2 decimal points if the three sides form a valid triangle. Otherwise return -1 Three sides make a valid triangle when the sum of any two sides is greater than the third side. '''
def triangle_area(a, b, c): ''' Given the lengths of the three sides of a triangle. Return the area of the triangle rounded to 2 decimal points if the three sides form a valid triangle. Otherwise return -1 Three sides make a valid triangle when the sum of any two sides is greater than the third side. Example: triangle_area(3, 4, 5) == 6.00 triangle_area(1, 2, 10) == -1 ''' if a + b <= c or a + c <= b or b + c <= a: return -1 s = (a + b + c)/2 area = (s * (s - a) * (s - b) * (s - c)) ** 0.5 area = round(area, 2) return area
python
HumanEval/72
will_it_fly
code_generation
[ [ "[3, 2, 3], 9", "True" ], [ "[1, 2], 5", "False" ], [ "[3], 5", "True" ], [ "[3, 2, 3], 1", "False" ], [ "[1, 2, 3], 6", "False" ], [ "[5], 5", "True" ] ]
null
[ [ "[1, 2], 5", "False" ], [ "[3, 2, 3], 1", "False" ], [ "[3, 2, 3], 9", "True" ], [ "[3], 5", "True" ] ]
[]
HumanEval
Write a function that returns True if the object q will fly, and False otherwise. The object q will fly if it's balanced (it is a palindromic list) and the sum of its elements is less than or equal the maximum possible weight w.
[]
def will_it_fly(q,w): ''' Write a function that returns True if the object q will fly, and False otherwise. The object q will fly if it's balanced (it is a palindromic list) and the sum of its elements is less than or equal the maximum possible weight w. '''
def will_it_fly(q,w): ''' Write a function that returns True if the object q will fly, and False otherwise. The object q will fly if it's balanced (it is a palindromic list) and the sum of its elements is less than or equal the maximum possible weight w. Example: will_it_fly([1, 2], 5) โžž False # 1+2 is less than the maximum possible weight, but it's unbalanced. will_it_fly([3, 2, 3], 1) โžž False # it's balanced, but 3+2+3 is more than the maximum possible weight. will_it_fly([3, 2, 3], 9) โžž True # 3+2+3 is less than the maximum possible weight, and it's balanced. will_it_fly([3], 5) โžž True # 3 is less than the maximum possible weight, and it's balanced. ''' if sum(q) > w: return False i, j = 0, len(q)-1 while i<j: if q[i] != q[j]: return False i+=1 j-=1 return True
python
HumanEval/73
smallest_change
code_generation
[ [ "[1,2,3,5,4,7,9,6]", "4" ], [ "[1, 2, 3, 4, 3, 2, 2]", "1" ], [ "[1, 4, 2]", "1" ], [ "[1, 4, 4, 2]", "1" ], [ "[1, 2, 3, 2, 1]", "0" ], [ "[3, 1, 1, 3]", "0" ], [ "[1]", "0" ], [ "[0, 1]", "1" ] ]
null
[ [ "[1,2,3,5,4,7,9,6]", "4" ], [ "[1, 2, 3, 4, 3, 2, 2]", "1" ], [ "[1, 2, 3, 2, 1]", "0" ] ]
[]
Given an array arr of integers, find the minimum number of elements that need to be changed to make the array palindromic. A palindromic array is an array that is read the same backwards and forwards. In one change, you can change one element to any other element.
HumanEval
Given an array arr of integers, find the minimum number of elements that need to be changed to make the array palindromic. A palindromic array is an array that is read the same backwards and forwards. In one change, you can change one element to any other element.
[]
def smallest_change(arr): """ Given an array arr of integers, find the minimum number of elements that need to be changed to make the array palindromic. A palindromic array is an array that is read the same backwards and forwards. In one change, you can change one element to any other element. """
def smallest_change(arr): """ Given an array arr of integers, find the minimum number of elements that need to be changed to make the array palindromic. A palindromic array is an array that is read the same backwards and forwards. In one change, you can change one element to any other element. For example: smallest_change([1,2,3,5,4,7,9,6]) == 4 smallest_change([1, 2, 3, 4, 3, 2, 2]) == 1 smallest_change([1, 2, 3, 2, 1]) == 0 """ ans = 0 for i in range(len(arr) // 2): if arr[i] != arr[len(arr) - i - 1]: ans += 1 return ans
python
HumanEval/74
total_match
code_generation
[ [ "[], []", "[]" ], [ "['hi', 'admin'], ['hi', 'hi']", "['hi', 'hi']" ], [ "['hi', 'admin'], ['hi', 'hi', 'admin', 'project']", "['hi', 'admin']" ], [ "['4'], ['1', '2', '3', '4', '5']", "['4']" ], [ "['hi', 'admin'], ['hI', 'Hi']", "['hI', 'Hi']" ], [ "['hi', 'admin'], ['hI', 'hi', 'hi']", "['hI', 'hi', 'hi']" ], [ "['hi', 'admin'], ['hI', 'hi', 'hii']", "['hi', 'admin']" ], [ "[], ['this']", "[]" ], [ "['this'], []", "[]" ] ]
null
[ [ "[], []", "[]" ], [ "['hi', 'admin'], ['hI', 'Hi']", "['hI', 'Hi']" ], [ "['hi', 'admin'], ['hi', 'hi', 'admin', 'project']", "['hi', 'admin']" ], [ "['hi', 'admin'], ['hI', 'hi', 'hi']", "['hI', 'hi', 'hi']" ], [ "['4'], ['1', '2', '3', '4', '5']", "['4']" ] ]
[]
HumanEval
Write a function that accepts two lists of strings and returns the list that has total number of chars in the all strings of the list less than the other list. if the two lists have the same number of chars, return the first list.
[]
def total_match(lst1, lst2): ''' Write a function that accepts two lists of strings and returns the list that has total number of chars in the all strings of the list less than the other list. if the two lists have the same number of chars, return the first list. '''
def total_match(lst1, lst2): ''' Write a function that accepts two lists of strings and returns the list that has total number of chars in the all strings of the list less than the other list. if the two lists have the same number of chars, return the first list. Examples total_match([], []) โžž [] total_match(['hi', 'admin'], ['hI', 'Hi']) โžž ['hI', 'Hi'] total_match(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) โžž ['hi', 'admin'] total_match(['hi', 'admin'], ['hI', 'hi', 'hi']) โžž ['hI', 'hi', 'hi'] total_match(['4'], ['1', '2', '3', '4', '5']) โžž ['4'] ''' l1 = 0 for st in lst1: l1 += len(st) l2 = 0 for st in lst2: l2 += len(st) if l1 <= l2: return lst1 else: return lst2
python
HumanEval/75
is_multiply_prime
code_generation
[ [ "5", "False" ], [ "30", "True" ], [ "8", "True" ], [ "10", "False" ], [ "125", "True" ], [ "3 * 5 * 7", "True" ], [ "3 * 6 * 7", "False" ], [ "9 * 9 * 9", "False" ], [ "11 * 9 * 9", "False" ], [ "11 * 13 * 7", "True" ] ]
null
[ [ "30", "True" ] ]
[]
Write a function that returns true if the given number is the multiplication of 3 prime numbers and false otherwise. Knowing that (a) is less then 100.
HumanEval
Write a function that returns true if the given number is the multiplication of 3 prime numbers and false otherwise. Knowing that (a) is less then 100.
[]
def is_multiply_prime(a): """Write a function that returns true if the given number is the multiplication of 3 prime numbers and false otherwise. Knowing that (a) is less then 100. """
def is_multiply_prime(a): """Write a function that returns true if the given number is the multiplication of 3 prime numbers and false otherwise. Knowing that (a) is less then 100. Example: is_multiply_prime(30) == True 30 = 2 * 3 * 5 """ def is_prime(n): for j in range(2,n): if n%j == 0: return False return True for i in range(2,101): if not is_prime(i): continue for j in range(2,101): if not is_prime(j): continue for k in range(2,101): if not is_prime(k): continue if i*j*k == a: return True return False
python
HumanEval/76
is_simple_power
code_generation
[ [ "16, 2", "True" ], [ "143214, 16", "False" ], [ "4, 2", "True" ], [ "9, 3", "True" ], [ "16, 4", "True" ], [ "24, 2", "False" ], [ "128, 4", "False" ], [ "12, 6", "False" ], [ "1, 1", "True" ], [ "1, 12", "True" ] ]
null
[ [ "1, 4", "true" ], [ "2, 2", "true" ], [ "8, 2", "true" ], [ "3, 2", "false" ], [ "3, 1", "false" ], [ "5, 3", "false" ] ]
[]
Your task is to write a function that returns true if a number x is a simple power of n and false in other cases. x is a simple power of n if n**int=x
HumanEval
Your task is to write a function that returns true if a number x is a simple power of n and false in other cases. x is a simple power of n if n**int=x
[]
def is_simple_power(x, n): """Your task is to write a function that returns true if a number x is a simple power of n and false in other cases. x is a simple power of n if n**int=x """
def is_simple_power(x, n): """Your task is to write a function that returns true if a number x is a simple power of n and false in other cases. x is a simple power of n if n**int=x For example: is_simple_power(1, 4) => true is_simple_power(2, 2) => true is_simple_power(8, 2) => true is_simple_power(3, 2) => false is_simple_power(3, 1) => false is_simple_power(5, 3) => false """ if (n == 1): return (x == 1) power = 1 while (power < x): power = power * n return (power == x)
python
HumanEval/77
iscube
code_generation
[ [ "1", "True" ], [ "2", "False" ], [ "-1", "True" ], [ "64", "True" ], [ "180", "False" ], [ "1000", "True" ], [ "0", "True" ], [ "1729", "False" ] ]
null
[ [ "1", "> True" ], [ "2", "> False" ], [ "-1", "> True" ], [ "64", "> True" ], [ "0", "> True" ], [ "180", "> False" ] ]
[]
HumanEval
Write a function that takes an integer a and returns True if this ingeger is a cube of some integer number. Note: you may assume the input is always valid.
[]
def iscube(a): ''' Write a function that takes an integer a and returns True if this ingeger is a cube of some integer number. Note: you may assume the input is always valid. '''
def iscube(a): ''' Write a function that takes an integer a and returns True if this ingeger is a cube of some integer number. Note: you may assume the input is always valid. Examples: iscube(1) ==> True iscube(2) ==> False iscube(-1) ==> True iscube(64) ==> True iscube(0) ==> True iscube(180) ==> False ''' a = abs(a) return int(round(a ** (1. / 3))) ** 3 == a
python
HumanEval/78
hex_key
code_generation
[ [ "\"AB\"", "1" ], [ "\"1077E\"", "2" ], [ "\"ABED1A33\"", "4" ], [ "\"2020\"", "2" ], [ "\"123456789ABCDEF0\"", "6" ], [ "\"112233445566778899AABBCCDDEEFF00\"", "12" ], [ "[]", "0" ] ]
null
[ [ "\"AB\"", "1" ], [ "\"1077E\"", "2" ], [ "\"ABED1A33\"", "4" ], [ "\"123456789ABCDEF0\"", "6" ], [ "\"2020\"", "2" ] ]
[]
You have been tasked to write a function that receives a hexadecimal number as a string and counts the number of hexadecimal digits that are primes (prime number, or a prime, is a natural number greater than 1 that is not a product of two smaller natural numbers). Hexadecimal digits are 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, A, B, C, D, E, F. Prime numbers are 2, 3, 5, 7, 11, 13, 17,... So you have to determine a number of the following digits: 2, 3, 5, 7, B (=decimal 11), D (=decimal 13). Note: you may assume the input is always correct or empty string, and symbols A,B,C,D,E,F are always uppercase.
HumanEval
You have been tasked to write a function that receives a hexadecimal number as a string and counts the number of hexadecimal digits that are primes (prime number, or a prime, is a natural number greater than 1 that is not a product of two smaller natural numbers). Hexadecimal digits are 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, A, B, C, D, E, F. Prime numbers are 2, 3, 5, 7, 11, 13, 17,... So you have to determine a number of the following digits: 2, 3, 5, 7, B (=decimal 11), D (=decimal 13). Note: you may assume the input is always correct or empty string, and symbols A,B,C,D,E,F are always uppercase.
[]
def hex_key(num): """You have been tasked to write a function that receives a hexadecimal number as a string and counts the number of hexadecimal digits that are primes (prime number, or a prime, is a natural number greater than 1 that is not a product of two smaller natural numbers). Hexadecimal digits are 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, A, B, C, D, E, F. Prime numbers are 2, 3, 5, 7, 11, 13, 17,... So you have to determine a number of the following digits: 2, 3, 5, 7, B (=decimal 11), D (=decimal 13). Note: you may assume the input is always correct or empty string, and symbols A,B,C,D,E,F are always uppercase. """
def hex_key(num): """You have been tasked to write a function that receives a hexadecimal number as a string and counts the number of hexadecimal digits that are primes (prime number, or a prime, is a natural number greater than 1 that is not a product of two smaller natural numbers). Hexadecimal digits are 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, A, B, C, D, E, F. Prime numbers are 2, 3, 5, 7, 11, 13, 17,... So you have to determine a number of the following digits: 2, 3, 5, 7, B (=decimal 11), D (=decimal 13). Note: you may assume the input is always correct or empty string, and symbols A,B,C,D,E,F are always uppercase. Examples: For num = "AB" the output should be 1. For num = "1077E" the output should be 2. For num = "ABED1A33" the output should be 4. For num = "123456789ABCDEF0" the output should be 6. For num = "2020" the output should be 2. """ primes = ('2', '3', '5', '7', 'B', 'D') total = 0 for i in range(0, len(num)): if num[i] in primes: total += 1 return total
python
HumanEval/79
decimal_to_binary
code_generation
[ [ "0", "\"db0db\"" ], [ "32", "\"db100000db\"" ], [ "103", "\"db1100111db\"" ], [ "15", "\"db1111db\"" ] ]
null
[ [ "15", "\"db1111db\"" ], [ "32", "\"db100000db\"" ] ]
[]
You will be given a number in decimal form and your task is to convert it to binary format. The function should return a string, with each character representing a binary number. Each character in the string will be '0' or '1'. There will be an extra couple of characters 'db' at the beginning and at the end of the string. The extra characters are there to help with the format.
HumanEval
You will be given a number in decimal form and your task is to convert it to binary format. The function should return a string, with each character representing a binary number. Each character in the string will be '0' or '1'. There will be an extra couple of characters 'db' at the beginning and at the end of the string. The extra characters are there to help with the format.
[]
def decimal_to_binary(decimal): """You will be given a number in decimal form and your task is to convert it to binary format. The function should return a string, with each character representing a binary number. Each character in the string will be '0' or '1'. There will be an extra couple of characters 'db' at the beginning and at the end of the string. The extra characters are there to help with the format. """
def decimal_to_binary(decimal): """You will be given a number in decimal form and your task is to convert it to binary format. The function should return a string, with each character representing a binary number. Each character in the string will be '0' or '1'. There will be an extra couple of characters 'db' at the beginning and at the end of the string. The extra characters are there to help with the format. Examples: decimal_to_binary(15) # returns "db1111db" decimal_to_binary(32) # returns "db100000db" """ return "db" + bin(decimal)[2:] + "db"
python
HumanEval/80
is_happy
code_generation
[ [ "\"a\"", "False" ], [ "\"aa\"", "False" ], [ "\"abcd\"", "True" ], [ "\"aabb\"", "False" ], [ "\"adb\"", "True" ], [ "\"xyy\"", "False" ], [ "\"iopaxpoi\"", "True" ], [ "\"iopaxioi\"", "False" ] ]
null
[ [ "a", "False" ], [ "aa", "False" ], [ "abcd", "True" ], [ "aabb", "False" ], [ "adb", "True" ], [ "xyy", "False" ] ]
[]
You are given a string s. Your task is to check if the string is happy or not. A string is happy if its length is at least 3 and every 3 consecutive letters are distinct
HumanEval
You are given a string s. Your task is to check if the string is happy or not. A string is happy if its length is at least 3 and every 3 consecutive letters are distinct
[]
def is_happy(s): """You are given a string s. Your task is to check if the string is happy or not. A string is happy if its length is at least 3 and every 3 consecutive letters are distinct """
def is_happy(s): """You are given a string s. Your task is to check if the string is happy or not. A string is happy if its length is at least 3 and every 3 consecutive letters are distinct For example: is_happy(a) => False is_happy(aa) => False is_happy(abcd) => True is_happy(aabb) => False is_happy(adb) => True is_happy(xyy) => False """ if len(s) < 3: return False for i in range(len(s) - 2): if s[i] == s[i+1] or s[i+1] == s[i+2] or s[i] == s[i+2]: return False return True
python
HumanEval/81
numerical_letter_grade
code_generation
[ [ "[4.0, 3, 1.7, 2, 3.5]", "['A+', 'B', 'C-', 'C', 'A-']" ], [ "[1.2]", "['D+']" ], [ "[0.5]", "['D-']" ], [ "[0.0]", "['E']" ], [ "[1, 0.3, 1.5, 2.8, 3.3]", "['D', 'D-', 'C-', 'B', 'B+']" ], [ "[0, 0.7]", "['E', 'D-']" ] ]
null
[ [ "[4.0, 3, 1.7, 2, 3.5]", "> ['A+', 'B', 'C-', 'C', 'A-']" ] ]
[]
It is the last week of the semester and the teacher has to give the grades to students. The teacher has been making her own algorithm for grading. The only problem is, she has lost the code she used for grading. She has given you a list of GPAs for some students and you have to write a function that can output a list of letter grades using the following table: GPA | Letter grade 4.0 A+ > 3.7 A > 3.3 A- > 3.0 B+ > 2.7 B > 2.3 B- > 2.0 C+ > 1.7 C > 1.3 C- > 1.0 D+ > 0.7 D > 0.0 D- 0.0 E
HumanEval
It is the last week of the semester and the teacher has to give the grades to students. The teacher has been making her own algorithm for grading. The only problem is, she has lost the code she used for grading. She has given you a list of GPAs for some students and you have to write a function that can output a list of letter grades using the following table: GPA | Letter grade 4.0 A+ > 3.7 A > 3.3 A- > 3.0 B+ > 2.7 B > 2.3 B- > 2.0 C+ > 1.7 C > 1.3 C- > 1.0 D+ > 0.7 D > 0.0 D- 0.0 E
[]
def numerical_letter_grade(grades): """It is the last week of the semester and the teacher has to give the grades to students. The teacher has been making her own algorithm for grading. The only problem is, she has lost the code she used for grading. She has given you a list of GPAs for some students and you have to write a function that can output a list of letter grades using the following table: GPA | Letter grade 4.0 A+ > 3.7 A > 3.3 A- > 3.0 B+ > 2.7 B > 2.3 B- > 2.0 C+ > 1.7 C > 1.3 C- > 1.0 D+ > 0.7 D > 0.0 D- 0.0 E """
def numerical_letter_grade(grades): """It is the last week of the semester and the teacher has to give the grades to students. The teacher has been making her own algorithm for grading. The only problem is, she has lost the code she used for grading. She has given you a list of GPAs for some students and you have to write a function that can output a list of letter grades using the following table: GPA | Letter grade 4.0 A+ > 3.7 A > 3.3 A- > 3.0 B+ > 2.7 B > 2.3 B- > 2.0 C+ > 1.7 C > 1.3 C- > 1.0 D+ > 0.7 D > 0.0 D- 0.0 E Example: grade_equation([4.0, 3, 1.7, 2, 3.5]) ==> ['A+', 'B', 'C-', 'C', 'A-'] """ letter_grade = [] for gpa in grades: if gpa == 4.0: letter_grade.append("A+") elif gpa > 3.7: letter_grade.append("A") elif gpa > 3.3: letter_grade.append("A-") elif gpa > 3.0: letter_grade.append("B+") elif gpa > 2.7: letter_grade.append("B") elif gpa > 2.3: letter_grade.append("B-") elif gpa > 2.0: letter_grade.append("C+") elif gpa > 1.7: letter_grade.append("C") elif gpa > 1.3: letter_grade.append("C-") elif gpa > 1.0: letter_grade.append("D+") elif gpa > 0.7: letter_grade.append("D") elif gpa > 0.0: letter_grade.append("D-") else: letter_grade.append("E") return letter_grade
python
HumanEval/82
prime_length
code_generation
[ [ "'Hello'", "True" ], [ "'abcdcba'", "True" ], [ "'kittens'", "True" ], [ "'orange'", "False" ], [ "'wow'", "True" ], [ "'world'", "True" ], [ "'MadaM'", "True" ], [ "'Wow'", "True" ], [ "''", "False" ], [ "'HI'", "True" ], [ "'go'", "True" ], [ "'gogo'", "False" ], [ "'aaaaaaaaaaaaaaa'", "False" ], [ "'Madam'", "True" ], [ "'M'", "False" ], [ "'0'", "False" ] ]
null
[ [ "'Hello'", "True" ], [ "'abcdcba'", "True" ], [ "'kittens'", "True" ], [ "'orange'", "False" ] ]
[]
Write a function that takes a string and returns True if the string length is a prime number or False otherwise
HumanEval
Write a function that takes a string and returns True if the string length is a prime number or False otherwise
[]
def prime_length(string): """Write a function that takes a string and returns True if the string length is a prime number or False otherwise """
def prime_length(string): """Write a function that takes a string and returns True if the string length is a prime number or False otherwise Examples prime_length('Hello') == True prime_length('abcdcba') == True prime_length('kittens') == True prime_length('orange') == False """ l = len(string) if l == 0 or l == 1: return False for i in range(2, l): if l % i == 0: return False return True
python
HumanEval/83
starts_one_ends
code_generation
[ [ "1", "1" ], [ "2", "18" ], [ "3", "180" ], [ "4", "1800" ], [ "5", "18000" ] ]
null
[]
[]
Given a positive integer n, return the count of the numbers of n-digit positive integers that start or end with 1.
HumanEval
Given a positive integer n, return the count of the numbers of n-digit positive integers that start or end with 1.
[]
def starts_one_ends(n): """ Given a positive integer n, return the count of the numbers of n-digit positive integers that start or end with 1. """
def starts_one_ends(n): """ Given a positive integer n, return the count of the numbers of n-digit positive integers that start or end with 1. """ if n == 1: return 1 return 18 * (10 ** (n - 2))
python
HumanEval/84
solve
code_generation
[ [ "1000", "\"1\"" ], [ "150", "\"110\"" ], [ "147", "\"1100\"" ], [ "333", "\"1001\"" ], [ "963", "\"10010\"" ] ]
null
[ [ "1000", "\"1\"" ], [ "150", "\"110\"" ], [ "147", "\"1100\"" ] ]
[]
Given a positive integer N, return the total sum of its digits in binary.
HumanEval
Given a positive integer N, return the total sum of its digits in binary.
[]
def solve(N): """Given a positive integer N, return the total sum of its digits in binary. """
def solve(N): """Given a positive integer N, return the total sum of its digits in binary. Example For N = 1000, the sum of digits will be 1 the output should be "1". For N = 150, the sum of digits will be 6 the output should be "110". For N = 147, the sum of digits will be 12 the output should be "1100". Variables: @N integer Constraints: 0 โ‰ค N โ‰ค 10000. Output: a string of binary number """ return bin(sum(int(i) for i in str(N)))[2:]
python
HumanEval/85
add
code_generation
[ [ "[4, 88]", "88" ], [ "[4, 5, 6, 7, 2, 122]", "122" ], [ "[4, 0, 6, 7]", "0" ], [ "[4, 4, 6, 8]", "12" ] ]
null
[ [ "[4, 2, 6, 7]", "> 2" ] ]
[]
Given a non-empty list of integers lst. add the even elements that are at odd indices..
HumanEval
Given a non-empty list of integers lst. add the even elements that are at odd indices..
[]
def add(lst): """Given a non-empty list of integers lst. add the even elements that are at odd indices.. """
def add(lst): """Given a non-empty list of integers lst. add the even elements that are at odd indices.. Examples: add([4, 2, 6, 7]) ==> 2 """ return sum([lst[i] for i in range(1, len(lst), 2) if lst[i]%2 == 0])
python
HumanEval/86
anti_shuffle
code_generation
[ [ "'Hi'", "'Hi'" ], [ "'hello'", "'ehllo'" ], [ "'number'", "'bemnru'" ], [ "'abcd'", "'abcd'" ], [ "'Hello World!!!'", "'Hello !!!Wdlor'" ], [ "''", "''" ], [ "'Hi. My name is Mister Robot. How are you?'", "'.Hi My aemn is Meirst .Rboot How aer ?ouy'" ] ]
null
[ [ "'Hi'", "'Hi'" ], [ "'hello'", "'ehllo'" ], [ "'Hello World!!!'", "'Hello !!!Wdlor'" ] ]
[]
Write a function that takes a string and returns an ordered version of it. Ordered version of string, is a string where all words (separated by space) are replaced by a new word where all the characters arranged in ascending order based on ascii value. Note: You should keep the order of words and blank spaces in the sentence.
HumanEval
Write a function that takes a string and returns an ordered version of it. Ordered version of string, is a string where all words (separated by space) are replaced by a new word where all the characters arranged in ascending order based on ascii value. Note: You should keep the order of words and blank spaces in the sentence.
[]
def anti_shuffle(s): """ Write a function that takes a string and returns an ordered version of it. Ordered version of string, is a string where all words (separated by space) are replaced by a new word where all the characters arranged in ascending order based on ascii value. Note: You should keep the order of words and blank spaces in the sentence. """
def anti_shuffle(s): """ Write a function that takes a string and returns an ordered version of it. Ordered version of string, is a string where all words (separated by space) are replaced by a new word where all the characters arranged in ascending order based on ascii value. Note: You should keep the order of words and blank spaces in the sentence. For example: anti_shuffle('Hi') returns 'Hi' anti_shuffle('hello') returns 'ehllo' anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor' """ return ' '.join([''.join(sorted(list(i))) for i in s.split(' ')])
python
HumanEval/87
get_row
code_generation
[ [ "[\n [1,2,3,4,5,6],\n [1,2,3,4,1,6],\n [1,2,3,4,5,1]\n ], 1", "[(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]" ], [ "[\n [1,2,3,4,5,6],\n [1,2,3,4,5,6],\n [1,2,3,4,5,6],\n [1,2,3,4,5,6],\n [1,2,3,4,5,6],\n [1,2,3,4,5,6]\n ], 2", "[(0, 1), (1, 1), (2, 1), (3, 1), (4, 1), (5, 1)]" ], [ "[\n [1,2,3,4,5,6],\n [1,2,3,4,5,6],\n [1,1,3,4,5,6],\n [1,2,1,4,5,6],\n [1,2,3,1,5,6],\n [1,2,3,4,1,6],\n [1,2,3,4,5,1]\n ], 1", "[(0, 0), (1, 0), (2, 1), (2, 0), (3, 2), (3, 0), (4, 3), (4, 0), (5, 4), (5, 0), (6, 5), (6, 0)]" ], [ "[], 1", "[]" ], [ "[[1]], 2", "[]" ], [ "[[], [1], [1, 2, 3]], 3", "[(2, 2)]" ] ]
null
[ [ "[], 1", "[]" ], [ "[[], [1], [1, 2, 3]], 3", "[(2, 2)]" ] ]
[]
You are given a 2 dimensional data, as a nested lists, which is similar to matrix, however, unlike matrices, each row may contain a different number of columns. Given lst, and integer x, find integers x in the list, and return list of tuples, [(x1, y1), (x2, y2) ...] such that each tuple is a coordinate - (row, columns), starting with 0. Sort coordinates initially by rows in ascending order. Also, sort coordinates of the row by columns in descending order.
HumanEval
You are given a 2 dimensional data, as a nested lists, which is similar to matrix, however, unlike matrices, each row may contain a different number of columns. Given lst, and integer x, find integers x in the list, and return list of tuples, [(x1, y1), (x2, y2) ...] such that each tuple is a coordinate - (row, columns), starting with 0. Sort coordinates initially by rows in ascending order. Also, sort coordinates of the row by columns in descending order.
[]
def get_row(lst, x): """ You are given a 2 dimensional data, as a nested lists, which is similar to matrix, however, unlike matrices, each row may contain a different number of columns. Given lst, and integer x, find integers x in the list, and return list of tuples, [(x1, y1), (x2, y2) ...] such that each tuple is a coordinate - (row, columns), starting with 0. Sort coordinates initially by rows in ascending order. Also, sort coordinates of the row by columns in descending order. """
def get_row(lst, x): """ You are given a 2 dimensional data, as a nested lists, which is similar to matrix, however, unlike matrices, each row may contain a different number of columns. Given lst, and integer x, find integers x in the list, and return list of tuples, [(x1, y1), (x2, y2) ...] such that each tuple is a coordinate - (row, columns), starting with 0. Sort coordinates initially by rows in ascending order. Also, sort coordinates of the row by columns in descending order. Examples: get_row([ [1,2,3,4,5,6], [1,2,3,4,1,6], [1,2,3,4,5,1] ], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)] get_row([], 1) == [] get_row([[], [1], [1, 2, 3]], 3) == [(2, 2)] """ coords = [(i, j) for i in range(len(lst)) for j in range(len(lst[i])) if lst[i][j] == x] return sorted(sorted(coords, key=lambda x: x[1], reverse=True), key=lambda x: x[0])
python
HumanEval/88
sort_array
code_generation
[ [ "[]", "[]" ], [ "[5]", "[5]" ], [ "[2, 4, 3, 0, 1, 5]", "[0, 1, 2, 3, 4, 5]" ], [ "[2, 4, 3, 0, 1, 5, 6]", "[6, 5, 4, 3, 2, 1, 0]" ], [ "[2, 1]", "[1, 2]" ], [ "[15, 42, 87, 32 ,11, 0]", "[0, 11, 15, 32, 42, 87]" ], [ "[21, 14, 23, 11]", "[23, 21, 14, 11]" ] ]
null
[ [ "[]", "[]" ], [ "[5]", "[5]" ], [ "[2, 4, 3, 0, 1, 5]", "[0, 1, 2, 3, 4, 5]" ], [ "[2, 4, 3, 0, 1, 5, 6]", "[6, 5, 4, 3, 2, 1, 0]" ] ]
[]
Given an array of non-negative integers, return a copy of the given array after sorting, you will sort the given array in ascending order if the sum( first index value, last index value) is odd, or sort it in descending order if the sum( first index value, last index value) is even. Note: * don't change the given array.
HumanEval
Given an array of non-negative integers, return a copy of the given array after sorting, you will sort the given array in ascending order if the sum( first index value, last index value) is odd, or sort it in descending order if the sum( first index value, last index value) is even. Note: * don't change the given array.
[]
def sort_array(array): """ Given an array of non-negative integers, return a copy of the given array after sorting, you will sort the given array in ascending order if the sum( first index value, last index value) is odd, or sort it in descending order if the sum( first index value, last index value) is even. Note: * don't change the given array. """
def sort_array(array): """ Given an array of non-negative integers, return a copy of the given array after sorting, you will sort the given array in ascending order if the sum( first index value, last index value) is odd, or sort it in descending order if the sum( first index value, last index value) is even. Note: * don't change the given array. Examples: * sort_array([]) => [] * sort_array([5]) => [5] * sort_array([2, 4, 3, 0, 1, 5]) => [0, 1, 2, 3, 4, 5] * sort_array([2, 4, 3, 0, 1, 5, 6]) => [6, 5, 4, 3, 2, 1, 0] """ return [] if len(array) == 0 else sorted(array, reverse= (array[0]+array[-1]) % 2 == 0)
python
HumanEval/89
encrypt
code_generation
[ [ "'hi'", "'lm'" ], [ "'asdfghjkl'", "'ewhjklnop'" ], [ "'gf'", "'kj'" ], [ "'et'", "'ix'" ], [ "'faewfawefaewg'", "'jeiajeaijeiak'" ], [ "'hellomyfriend'", "'lippsqcjvmirh'" ], [ "'dxzdlmnilfuhmilufhlihufnmlimnufhlimnufhfucufh'", "'hbdhpqrmpjylqmpyjlpmlyjrqpmqryjlpmqryjljygyjl'" ], [ "'a'", "'e'" ] ]
null
[ [ "'hi'", "'lm'" ], [ "'asdfghjkl'", "'ewhjklnop'" ], [ "'gf'", "'kj'" ], [ "'et'", "'ix'" ] ]
[]
Create a function encrypt that takes a string as an argument and returns a string encrypted with the alphabet being rotated. The alphabet should be rotated in a manner such that the letters shift down by two multiplied to two places.
HumanEval
Create a function encrypt that takes a string as an argument and returns a string encrypted with the alphabet being rotated. The alphabet should be rotated in a manner such that the letters shift down by two multiplied to two places.
[]
def encrypt(s): """Create a function encrypt that takes a string as an argument and returns a string encrypted with the alphabet being rotated. The alphabet should be rotated in a manner such that the letters shift down by two multiplied to two places. """
def encrypt(s): """Create a function encrypt that takes a string as an argument and returns a string encrypted with the alphabet being rotated. The alphabet should be rotated in a manner such that the letters shift down by two multiplied to two places. For example: encrypt('hi') returns 'lm' encrypt('asdfghjkl') returns 'ewhjklnop' encrypt('gf') returns 'kj' encrypt('et') returns 'ix' """ d = 'abcdefghijklmnopqrstuvwxyz' out = '' for c in s: if c in d: out += d[(d.index(c)+2*2) % 26] else: out += c return out
python
HumanEval/90
next_smallest
code_generation
[ [ "[1, 2, 3, 4, 5]", "2" ], [ "[5, 1, 4, 3, 2]", "2" ], [ "[]", "None" ], [ "[1, 1]", "None" ], [ "[1,1,1,1,0]", "1" ], [ "[1, 0**0]", "None" ], [ "[-35, 34, 12, -45]", "-35" ] ]
null
[ [ "[1, 2, 3, 4, 5]", "2" ], [ "[5, 1, 4, 3, 2]", "2" ], [ "[]", "None" ], [ "[1, 1]", "None" ] ]
[]
You are given a list of integers. Write a function next_smallest() that returns the 2nd smallest element of the list. Return None if there is no such element. next_smallest([1, 2, 3, 4, 5]) == 2 next_smallest([5, 1, 4, 3, 2]) == 2 next_smallest([]) == None next_smallest([1, 1]) == None
HumanEval
You are given a list of integers. Write a function next_smallest() that returns the 2nd smallest element of the list. Return None if there is no such element.
[]
def next_smallest(lst): """ You are given a list of integers. Write a function next_smallest() that returns the 2nd smallest element of the list. Return None if there is no such element. """
def next_smallest(lst): """ You are given a list of integers. Write a function next_smallest() that returns the 2nd smallest element of the list. Return None if there is no such element. next_smallest([1, 2, 3, 4, 5]) == 2 next_smallest([5, 1, 4, 3, 2]) == 2 next_smallest([]) == None next_smallest([1, 1]) == None """ lst = sorted(set(lst)) return None if len(lst) < 2 else lst[1]
python
HumanEval/91
is_bored
code_generation
[ [ "\"Hello world\"", "0" ], [ "\"Is the sky blue?\"", "0" ], [ "\"I love It !\"", "1" ], [ "\"bIt\"", "0" ], [ "\"I feel good today. I will be productive. will kill It\"", "2" ], [ "\"You and I are going for a walk\"", "0" ] ]
null
[ [ "\"Hello world\"", "0" ], [ "\"The sky is blue. The sun is shining. I love this weather\"", "1" ] ]
[]
You'll be given a string of words, and your task is to count the number of boredoms. A boredom is a sentence that starts with the word "I". Sentences are delimited by '.', '?' or '!'.
HumanEval
You'll be given a string of words, and your task is to count the number of boredoms. A boredom is a sentence that starts with the word "I". Sentences are delimited by '.', '?' or '!'.
[]
def is_bored(S): """ You'll be given a string of words, and your task is to count the number of boredoms. A boredom is a sentence that starts with the word "I". Sentences are delimited by '.', '?' or '!'. """
def is_bored(S): """ You'll be given a string of words, and your task is to count the number of boredoms. A boredom is a sentence that starts with the word "I". Sentences are delimited by '.', '?' or '!'. For example: >>> is_bored("Hello world") 0 >>> is_bored("The sky is blue. The sun is shining. I love this weather") 1 """ import re sentences = re.split(r'[.?!]\s*', S) return sum(sentence[0:2] == 'I ' for sentence in sentences)
python
HumanEval/92
any_int
code_generation
[ [ "2, 3, 1", "True" ], [ "2.5, 2, 3", "False" ], [ "1.5, 5, 3.5", "False" ], [ "2, 6, 2", "False" ], [ "4, 2, 2", "True" ], [ "2.2, 2.2, 2.2", "False" ], [ "-4, 6, 2", "True" ], [ "2, 1, 1", "True" ], [ "3, 4, 7", "True" ], [ "3.0, 4, 7", "False" ] ]
null
[ [ "5, 2, 7", "True" ], [ "3, 2, 2", "False" ], [ "3, -2, 1", "True" ], [ "3.6, -2.2, 2", "False" ] ]
[]
HumanEval
Create a function that takes 3 numbers. Returns true if one of the numbers is equal to the sum of the other two, and all numbers are integers. Returns false in any other cases.
[]
def any_int(x, y, z): ''' Create a function that takes 3 numbers. Returns true if one of the numbers is equal to the sum of the other two, and all numbers are integers. Returns false in any other cases. '''
def any_int(x, y, z): ''' Create a function that takes 3 numbers. Returns true if one of the numbers is equal to the sum of the other two, and all numbers are integers. Returns false in any other cases. Examples any_int(5, 2, 7) โžž True any_int(3, 2, 2) โžž False any_int(3, -2, 1) โžž True any_int(3.6, -2.2, 2) โžž False ''' if isinstance(x,int) and isinstance(y,int) and isinstance(z,int): if (x+y==z) or (x+z==y) or (y+z==x): return True return False return False
python
HumanEval/93
encode
code_generation
[ [ "'TEST'", "'tgst'" ], [ "'Mudasir'", "'mWDCSKR'" ], [ "'YES'", "'ygs'" ], [ "'This is a message'", "'tHKS KS C MGSSCGG'" ], [ "\"I DoNt KnOw WhAt tO WrItE\"", "'k dQnT kNqW wHcT Tq wRkTg'" ] ]
null
[ [ "'test'", "'TGST'" ], [ "'This is a message'", "'tHKS KS C MGSSCGG'" ] ]
[]
Write a function that takes a message, and encodes in such a way that it swaps case of all letters, replaces all vowels in the message with the letter that appears 2 places ahead of that vowel in the english alphabet. Assume only letters.
HumanEval
Write a function that takes a message, and encodes in such a way that it swaps case of all letters, replaces all vowels in the message with the letter that appears 2 places ahead of that vowel in the english alphabet. Assume only letters.
[]
def encode(message): """ Write a function that takes a message, and encodes in such a way that it swaps case of all letters, replaces all vowels in the message with the letter that appears 2 places ahead of that vowel in the english alphabet. Assume only letters. """
def encode(message): """ Write a function that takes a message, and encodes in such a way that it swaps case of all letters, replaces all vowels in the message with the letter that appears 2 places ahead of that vowel in the english alphabet. Assume only letters. Examples: >>> encode('test') 'TGST' >>> encode('This is a message') 'tHKS KS C MGSSCGG' """ vowels = "aeiouAEIOU" vowels_replace = dict([(i, chr(ord(i) + 2)) for i in vowels]) message = message.swapcase() return ''.join([vowels_replace[i] if i in vowels else i for i in message])
python
HumanEval/94
skjkasdkd
code_generation
[ [ "[0,3,2,1,3,5,7,4,5,5,5,2,181,32,4,32,3,2,32,324,4,3]", "10" ], [ "[1,0,1,8,2,4597,2,1,3,40,1,2,1,2,4,2,5,1]", "25" ], [ "[1,3,1,32,5107,34,83278,109,163,23,2323,32,30,1,9,3]", "13" ], [ "[0,724,32,71,99,32,6,0,5,91,83,0,5,6]", "11" ], [ "[0,81,12,3,1,21]", "3" ], [ "[0,8,1,2,1,7]", "7" ], [ "[8191]", "19" ], [ "[8191, 123456, 127, 7]", "19" ], [ "[127, 97, 8192]", "10" ] ]
null
[ [ "[0,3,2,1,3,5,7,4,5,5,5,2,181,32,4,32,3,2,32,324,4,3]", "10" ], [ "[1,0,1,8,2,4597,2,1,3,40,1,2,1,2,4,2,5,1]", "25" ], [ "[1,3,1,32,5107,34,83278,109,163,23,2323,32,30,1,9,3]", "13" ], [ "[0,724,32,71,99,32,6,0,5,91,83,0,5,6]", "11" ], [ "[0,81,12,3,1,21]", "3" ], [ "[0,8,1,2,1,7]", "7" ] ]
[]
You are given a list of integers. You need to find the largest prime value and return the sum of its digits.
HumanEval
You are given a list of integers. You need to find the largest prime value and return the sum of its digits.
[]
def skjkasdkd(lst): """You are given a list of integers. You need to find the largest prime value and return the sum of its digits. """
def skjkasdkd(lst): """You are given a list of integers. You need to find the largest prime value and return the sum of its digits. Examples: For lst = [0,3,2,1,3,5,7,4,5,5,5,2,181,32,4,32,3,2,32,324,4,3] the output should be 10 For lst = [1,0,1,8,2,4597,2,1,3,40,1,2,1,2,4,2,5,1] the output should be 25 For lst = [1,3,1,32,5107,34,83278,109,163,23,2323,32,30,1,9,3] the output should be 13 For lst = [0,724,32,71,99,32,6,0,5,91,83,0,5,6] the output should be 11 For lst = [0,81,12,3,1,21] the output should be 3 For lst = [0,8,1,2,1,7] the output should be 7 """ def isPrime(n): for i in range(2,int(n**0.5)+1): if n%i==0: return False return True maxx = 0 i = 0 while i < len(lst): if(lst[i] > maxx and isPrime(lst[i])): maxx = lst[i] i+=1 result = sum(int(digit) for digit in str(maxx)) return result
python
HumanEval/95
check_dict_case
code_generation
[ [ "{\"p\":\"pineapple\", \"b\":\"banana\"}", "True" ], [ "{\"p\":\"pineapple\", \"A\":\"banana\", \"B\":\"banana\"}", "False" ], [ "{\"p\":\"pineapple\", 5:\"banana\", \"a\":\"apple\"}", "False" ], [ "{\"Name\":\"John\", \"Age\":\"36\", \"City\":\"Houston\"}", "False" ], [ "{\"STATE\":\"NC\", \"ZIP\":\"12345\" }", "True" ], [ "{\"fruit\":\"Orange\", \"taste\":\"Sweet\" }", "True" ], [ "{}", "False" ] ]
null
[ [ "{\"a\":\"apple\", \"b\":\"banana\"}", "True" ], [ "{\"a\":\"apple\", \"A\":\"banana\", \"B\":\"banana\"}", "True" ], [ "{\"a\":\"apple\", 8:\"banana\", \"a\":\"apple\"}", "False" ], [ "{\"Name\":\"John\", \"Age\":\"36\", \"City\":\"Houston\"}", "False" ], [ "{\"STATE\":\"NC\", \"ZIP\":\"12345\" }", "True" ] ]
[]
Given a dictionary, return True if all keys are strings in lower case or all keys are strings in upper case, else return False. The function should return False is the given dictionary is empty.
HumanEval
Given a dictionary, return True if all keys are strings in lower case or all keys are strings in upper case, else return False. The function should return False is the given dictionary is empty.
[]
def check_dict_case(dict): """ Given a dictionary, return True if all keys are strings in lower case or all keys are strings in upper case, else return False. The function should return False is the given dictionary is empty. """
def check_dict_case(dict): """ Given a dictionary, return True if all keys are strings in lower case or all keys are strings in upper case, else return False. The function should return False is the given dictionary is empty. Examples: check_dict_case({"a":"apple", "b":"banana"}) should return True. check_dict_case({"a":"apple", "A":"banana", "B":"banana"}) should return False. check_dict_case({"a":"apple", 8:"banana", "a":"apple"}) should return False. check_dict_case({"Name":"John", "Age":"36", "City":"Houston"}) should return False. check_dict_case({"STATE":"NC", "ZIP":"12345" }) should return True. """ if len(dict.keys()) == 0: return False else: state = "start" for key in dict.keys(): if isinstance(key, str) == False: state = "mixed" break if state == "start": if key.isupper(): state = "upper" elif key.islower(): state = "lower" else: break elif (state == "upper" and not key.isupper()) or (state == "lower" and not key.islower()): state = "mixed" break else: break return state == "upper" or state == "lower"
python
HumanEval/96
count_up_to
code_generation
[ [ "5", "[2,3]" ], [ "6", "[2,3,5]" ], [ "7", "[2,3,5]" ], [ "10", "[2,3,5,7]" ], [ "0", "[]" ], [ "22", "[2,3,5,7,11,13,17,19]" ], [ "1", "[]" ], [ "18", "[2,3,5,7,11,13,17]" ], [ "47", "[2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43]" ], [ "101", "[2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53, 59, 61, 67, 71, 73, 79, 83, 89, 97]" ] ]
null
[ [ "5", "[2,3]" ], [ "11", "[2,3,5,7]" ], [ "0", "[]" ], [ "20", "[2,3,5,7,11,13,17,19]" ], [ "1", "[]" ], [ "18", "[2,3,5,7,11,13,17]" ] ]
[]
Implement a function that takes an non-negative integer and returns an array of the first n integers that are prime numbers and less than n.
HumanEval
Implement a function that takes an non-negative integer and returns an array of the first n integers that are prime numbers and less than n.
[]
def count_up_to(n): """Implement a function that takes an non-negative integer and returns an array of the first n integers that are prime numbers and less than n. """
def count_up_to(n): """Implement a function that takes an non-negative integer and returns an array of the first n integers that are prime numbers and less than n. for example: count_up_to(5) => [2,3] count_up_to(11) => [2,3,5,7] count_up_to(0) => [] count_up_to(20) => [2,3,5,7,11,13,17,19] count_up_to(1) => [] count_up_to(18) => [2,3,5,7,11,13,17] """ primes = [] for i in range(2, n): is_prime = True for j in range(2, i): if i % j == 0: is_prime = False break if is_prime: primes.append(i) return primes
python
HumanEval/97
multiply
code_generation
[ [ "148, 412", "16" ], [ "19, 28", "72" ], [ "2020, 1851", "0" ], [ "14, -15", "20" ], [ "76, 67", "42" ], [ "17, 27", "49" ], [ "0, 1", "0" ], [ "0, 0", "0" ] ]
null
[ [ "148, 412", "16" ], [ "19, 28", "72" ], [ "2020, 1851", "0" ], [ "14, -15", "20" ] ]
[]
Complete the function that takes two integers and returns the product of their unit digits. Assume the input is always valid.
HumanEval
Complete the function that takes two integers and returns the product of their unit digits. Assume the input is always valid.
[]
def multiply(a, b): """Complete the function that takes two integers and returns the product of their unit digits. Assume the input is always valid. """
def multiply(a, b): """Complete the function that takes two integers and returns the product of their unit digits. Assume the input is always valid. Examples: multiply(148, 412) should return 16. multiply(19, 28) should return 72. multiply(2020, 1851) should return 0. multiply(14,-15) should return 20. """ return abs(a % 10) * abs(b % 10)
python
HumanEval/98
count_upper
code_generation
[ [ "'aBCdEf'", "1" ], [ "'abcdefg'", "0" ], [ "'dBBE'", "0" ], [ "'B'", "0" ], [ "'U'", "1" ], [ "''", "0" ], [ "'EEEE'", "2" ] ]
null
[ [ "'aBCdEf'", "1" ], [ "'abcdefg'", "0" ], [ "'dBBE'", "0" ] ]
[]
Given a string s, count the number of uppercase vowels in even indices.
HumanEval
Given a string s, count the number of uppercase vowels in even indices.
[]
def count_upper(s): """ Given a string s, count the number of uppercase vowels in even indices. """
def count_upper(s): """ Given a string s, count the number of uppercase vowels in even indices. For example: count_upper('aBCdEf') returns 1 count_upper('abcdefg') returns 0 count_upper('dBBE') returns 0 """ count = 0 for i in range(0,len(s),2): if s[i] in "AEIOU": count += 1 return count
python
HumanEval/99
closest_integer
code_generation
[ [ "\"10\"", "10" ], [ "\"14.5\"", "15" ], [ "\"-15.5\"", "-16" ], [ "\"15.3\"", "15" ], [ "\"0\"", "0" ] ]
null
[ [ "\"10\"", "10" ], [ "\"15.3\"", "15" ] ]
[]
HumanEval
Create a function that takes a value (string) representing a number and returns the closest integer to it. If the number is equidistant from two integers, round it away from zero.
[]
def closest_integer(value): ''' Create a function that takes a value (string) representing a number and returns the closest integer to it. If the number is equidistant from two integers, round it away from zero. '''
def closest_integer(value): ''' Create a function that takes a value (string) representing a number and returns the closest integer to it. If the number is equidistant from two integers, round it away from zero. Examples >>> closest_integer("10") 10 >>> closest_integer("15.3") 15 Note: Rounding away from zero means that if the given number is equidistant from two integers, the one you should return is the one that is the farthest from zero. For example closest_integer("14.5") should return 15 and closest_integer("-14.5") should return -15. ''' from math import floor, ceil if value.count('.') == 1: # remove trailing zeros while (value[-1] == '0'): value = value[:-1] num = float(value) if value[-2:] == '.5': if num > 0: res = ceil(num) else: res = floor(num) elif len(value) > 0: res = int(round(num)) else: res = 0 return res
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