Dataset Viewer
choices
dict | answerKey
sequencelengths 1
1
| question
stringlengths 8
751
| rationale
stringlengths 8
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| dataset
stringclasses 1
value |
|---|---|---|---|---|
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"rs . 400",
"rs . 300",
"rs . 500",
"rs . 350"
]
}
|
[
"A"
] |
the banker ' s gain of a certain sum due 3 years hence at 10 % per annum is rs . 36 . what is the present worth ?
|
"explanation : t = 3 years r = 10 % td = ( bg Γ 100 ) / tr = ( 36 Γ 100 ) / ( 3 Γ 10 ) = 12 Γ 10 = rs . 120 td = ( pw Γ tr ) / 100 β 120 = ( pw Γ 3 Γ 10 ) / 100 β 1200 = pw Γ 3 pw = 1200 / 3 = rs . 400 answer : option a"
|
MathQA
|
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"1200",
"120",
"360",
"240"
]
}
|
[
"D"
] |
average age of students of an adult school is 40 years . 120 new students whose average age is 32 years joined the school . as a result the average age is decreased by 4 years . find the number of students of the school after joining of the new students .
|
"explanation : let the original no . of students be x . according to situation , 40 x + 120 * 32 = ( x + 120 ) 36 β x = 120 so , required no . of students after joining the new students = x + 120 = 240 . answer : d"
|
MathQA
|
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"rs . 40",
"rs . 50",
"rs . 49",
"rs . 59"
]
}
|
[
"B"
] |
the profit obtained by selling an article for rs . 57 is the same as the loss obtained by selling it for rs . 43 . what is the cost price of the article ?
|
"s . p 1 - c . p = c . p β s . p 2 57 - c . p = c . p - 43 2 c . p = 57 + 43 ; c . p = 100 / 2 = 50 answer : b"
|
MathQA
|
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"1 : 2",
"1 : 5",
"2 : 3",
"3 : 2"
]
}
|
[
"B"
] |
5 women can do a work in two days . 10 men can complete the same work in five days . what is the ratio between the capacity of a man and a woman ?
|
"explanation : ( 5 Γ£ β 2 ) women can complete the work in 1 day . Γ’ Λ Β΄ 1 woman ' s 1 day ' s work = 1 / 10 ( 10 Γ£ β 5 ) men can complete the work in 1 day . Γ’ Λ Β΄ 1 man ' s 1 day ' s work = 1 / 50 so , required ratio = 1 / 10 : 1 / 50 = 1 : 5 answer : b"
|
MathQA
|
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
". 3",
". 09",
". 009",
". 0009"
]
}
|
[
"A"
] |
. 003 / ? = . 01
|
"let . 003 / x = . 01 ; then x = . 003 / . 01 = . 3 / 1 = . 3 answer is a"
|
MathQA
|
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"54",
"108",
"216",
"432"
]
}
|
[
"C"
] |
what will be the lcm of 8 , 24 , 36 and 54
|
explanation : lcm of 8 - 24 - 36 - 54 will be 2 * 2 * 2 * 3 * 3 * 3 = 216 answer : option c
|
MathQA
|
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"1.12",
"1.16",
"1.2",
"0.9"
]
}
|
[
"D"
] |
if 0.75 : x : : 5 : 6 , then x is equal to :
|
"explanation : ( x * 5 ) = ( 0.75 * 6 ) x = 4.5 / 5 = 0.9 answer : d"
|
MathQA
|
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"1 / 5",
"1 / 4",
"7 / 20",
"3 / 5"
]
}
|
[
"A"
] |
3 / 5 of all married couples have more than one child . 2 / 5 of all married couples have more than 3 children . what fraction of all married couples have 2 or 3 children ?
|
plug in simple numbers . take 100 couples for example . 3 / 5 of 100 couples have more than one child = 60 couples . 2 / 5 of 100 couples have more than 3 kids = 40 couples . this implies that 40 couples are a subset of 60 couples and the complement of 60 couples within those 100 couples , which equals 20 couples have either one or no kids at all . we need to find couples that have 2 or 3 kids , so essentially , it is 60 - 40 = 20 . fraction will be 20 / 100 = 1 / 5 . option a
|
MathQA
|
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"42",
"36",
"30",
"48"
]
}
|
[
"A"
] |
in a class of 60 children , 30 % children can speak only english , 20 % hindi and english both and the rest of the children can speak only hindi . how many children can speak hindi ?
|
number of students who speak only english = 30 % of 60 = 18 β΅ number of students who speak hindi and english = 20 % of 60 = 12 β΅ number of students who speak only hindi = ( 60 β 30 = ) 30 β΅ no . of students who speak hindi = 30 + 12 = 42 answer a
|
MathQA
|
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"rs . 600",
"rs . 890",
"rs . 895",
"rs . 900"
]
}
|
[
"A"
] |
if the compound interest on a certain sum of money for 2 years at 10 % per annum be rs . 993 , what would be the simple interest ?
|
"let p = principal a - amount we have a = p ( 1 + r / 100 ) 3 and ci = a - p atq 993 = p ( 1 + r / 100 ) 3 - p ? p = 3000 / - now si @ 10 % on 3000 / - for 2 yrs = ( 3000 x 10 x 2 ) / 100 = 600 / - answer : a ."
|
MathQA
|
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"rs . 169.50",
"rs . 1700",
"rs . 185.50",
"rs . 180"
]
}
|
[
"C"
] |
tea worth rs . 126 per kg are mixed with a third variety in the ratio 1 : 1 : 2 . if the mixture is worth rs . 163 per kg , the price of the third variety per kg will be
|
"solution since first second varieties are mixed in equal proportions , so their average price = rs . ( 126 + 135 / 2 ) = rs . 130.50 so , the mixture is formed by mixing two varieties , one at rs . 130.50 per kg and the other at say , rs . x per kg in the ratio 2 : 2 , i . e . , 1 : 1 . we have to find x . x - 163 / 22.50 = 1 = Γ’ β¬ ΒΊ x - 163 = 22.50 = Γ’ β¬ ΒΊ x = 185.50 . hence , price of the third variety = rs . 175.50 per kg . answer c"
|
MathQA
|
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"75 m .",
"80 m .",
"84 m .",
"100 m ."
]
}
|
[
"C"
] |
a runs twice as fast as b and gives b a start of 42 m . how long should the racecourse be so that a and b might reach in the same time ?
|
"ratio of speeds of a and b is 2 : 1 b is 42 m away from a but we know that a covers 1 meter ( 2 - 1 ) more in every second than b the time taken for a to cover 42 m is 42 / 1 = 42 m so the total time taken by a and b to reach = 2 * 42 = 84 m answer : c"
|
MathQA
|
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"1 / 2",
"1 / 3",
"1 / 5",
"1 / 6"
]
}
|
[
"A"
] |
in a throw of dice what is the probability of ge Γ¦ Β« ng number greater than 3
|
"explanation : number greater than 3 is 4 , 5 , 6 , so only 3 number total cases of dice = [ 1,2 , 3,4 , 5,6 ] so probability = 3 / 6 = 1 / 2 answer : a"
|
MathQA
|
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"55",
"56",
"57",
"58"
]
}
|
[
"B"
] |
a rectangular plot measuring 90 metres by 50 metres is to be enclosed by wire fencing . if the poles of the fence are kept 5 metres apart , how many poles will be needed ?
|
"solution perimeter of the plot = 2 ( 90 + 50 ) = 280 m . β΄ number of poles = [ 280 / 5 ] = 56 m answer b"
|
MathQA
|
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"23.75",
"21.6",
"20",
"19.2"
]
}
|
[
"B"
] |
a trader mixes 80 kg of tea at 15 per kg with 20 kg of tea at cost price of 20 per kg . in order to earn a profit of 35 % , what should be the sale price of the mixed tea ?
|
"c . p . of mixture = 80 Γ 15 + 20 Γ 20 / 80 + 20 = 16 β΄ s . p . = ( 100 + 35 ) / 100 Γ 16 = 21.6 answer b"
|
MathQA
|
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"rs . 692.80",
"rs . 905",
"rs . 990",
"rs . 1385"
]
}
|
[
"B"
] |
average monthly income of a family of 3 earning members was rs . 735 . one of the earning members died and therefore , the average income came down to rs 650 . the income of the deceased was ?
|
"answer income of the deceased = total income of 4 members - total income of remaining 3 members . = 735 x 3 - 650 x 2 rs . = 905 rs . correct option : b"
|
MathQA
|
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"25.5",
"2.5",
"25",
". 25"
]
}
|
[
"C"
] |
1 / 0.04 is equal to
|
"explanation : 1 / 0.04 = ( 1 * 100 ) / 4 = 100 / 4 = 25 option c"
|
MathQA
|
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"rs . 4800",
"rs . 2400",
"rs . 3600",
"rs . 5600"
]
}
|
[
"A"
] |
a and b enter into a partnership . a contributed rs . 5000 for 8 months and b rs . 6000 for 5 months . find a ' s share in a total profit of rs . 8400 .
|
explanation : ratio of capitals of a and b = ratio of their investments = 5000 Γ 8 : 6000 Γ 5 = 40000 : 30000 = 4 : 3 . : a ' s share = rs . [ ( 4 / 7 ) Γ 8400 ] = rs . 4800 answer : option a
|
MathQA
|
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"25",
"50",
"75",
"80"
]
}
|
[
"C"
] |
a and b undertake to do a piece of work for rs . 600 . a alone can do it in 6 days while b alone can do it in 8 days . with the help of c , they finish it in 3 days . ! find the share of each .
|
c ' s 1 day ' s work = 1 / 3 - ( 1 / 6 + 1 / 8 ) = 24 a : b : c = ratio of their 1 day ' s work = 1 / 6 : 1 / 8 : 1 / 24 = 4 : 3 : 1 . a β s share = rs . ( 600 * 4 / 8 ) = rs . 300 , b ' s share = rs . ( 600 * 3 / 8 ) = rs . 225 . c ' s share = rs . [ 600 - ( 300 + 225 Β» ) = rs . 75 . answer is c
|
MathQA
|
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"11 : 9",
"13 : 9",
"17 : 9",
"21 : 9"
]
}
|
[
"A"
] |
2 trains starting at the same time from 2 stations 200 km apart and going in opposite direction cross each other at a distance of 110 km from one of the stations . what is the ratio of their speeds
|
"explanation : we know total distance is 200 km if both trains crossed each other at a distance of 110 km then one train covered 110 km and other 90 km [ 110 + 90 = 200 km ] so ratio of their speed = 110 : 90 = 11 : 9 option a"
|
MathQA
|
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"0.3408",
"3.408",
"34.08",
"340.8"
]
}
|
[
"D"
] |
if 213 Γ 16 = 3408 , then 1.6 Γ 213.0 is equal to :
|
solution 1.6 Γ 21.3 = ( 16 / 10 x 213 ) = ( 16 x 213 / 10 ) = 3408 / 10 = 340.8 . answer d
|
MathQA
|
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"17.65 %",
"9 %",
"11.11 %",
"12 %"
]
}
|
[
"A"
] |
a shopkeeper forced to sell at cost price , uses a 850 grams weight for a kilogram . what is his gain percent ?
|
"shopkeeper sells 850 g instead of 1000 g . so , his gain = 1000 - 850 = 150 g . thus , % gain = ( 150 * 100 ) / 850 = 17.65 % . answer : option a"
|
MathQA
|
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"10 hours",
"12.50 hours",
"15.80 hours",
"25 hours"
]
}
|
[
"C"
] |
bella is taking a trip in her car from new york ( point a ) chicago , illinois ( point b ) . she is traveling at an average speed of 50 miles per hour , if the total distance from point a to point b is 790 miles , in approximately how long will bella reach her destination ?
|
answer is ( c ) . if she is traveling at a speed of 50 miles per hour and her trip is a total of 790 miles , 790 miles divided by 50 miles per hours would equal 15.80 hours , just shy of 16 hours .
|
MathQA
|
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"3 .",
"5",
"1 / 2 .",
"1 / 3 ."
]
}
|
[
"B"
] |
two brothers took the gmat exam , the higher score is x and the lower one is y . if the difference between the two scores is 1 / 5 , what is the value of x / y ?
|
"answer is b : 5 x - y = ( x + y ) / 2 solving for x / y = 5"
|
MathQA
|
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"407.09",
"479.75",
"523.93",
"596.95"
]
}
|
[
"D"
] |
3639 + 11.95 - x = 3054 . find the value of x .
|
"explanation : let 3639 + 11.95 β x = 3054 then , x = ( 3639 + 11.95 ) β 3054 = 3650.95 β 3054 = 596.95 answer : d"
|
MathQA
|
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"12 : 7', '",
"10 : 7', '",
"8 : 7', '",
"4 : 3', '"
]
}
|
[
"D"
] |
in a school having roll strength 286 , the ratio of boys and girls is 8 : 5 . if 22 more girls get admitted into the school , the ratio of boys and girls becomes
|
solution : boys : girls = 8 : 5 ; ( let the boys = 8 x ; girl = 5 x ) total strength = 286 ; 8 x + 5 x = 286 ; 13 x = 286 ; or , x = 286 / 13 = 22 ; boys = 176 and girls = 110 ; 22 more girls get admitted then number of girls become , ( 5 x + 22 ) = 110 + 22 = 132 ; now , new ratio of boys and girls = 176 : 132 = 4 : 3 . answer : option d
|
MathQA
|
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"15', '",
"25', '",
"35', '",
"30', '"
]
}
|
[
"B"
] |
the ratio of sum of squares of first n natural numbers to square of sum of first n natural numbers is 17 : 325 . the value of n is
|
sum of 1 st n natural no . s is n ( n + 1 ) / 2 , sum of sqaures of 1 st n natural no . s is n ( n + 1 ) ( 2 n + 1 ) / 6 , the ratio of sum of squares of first n natural numbers to square of sum of first n natural numbers = n ( n + 1 ) ( 2 n + 1 ) * 2 * 2 / ( n * n * ( n + 1 ) * ( n + 1 ) ) = 2 ( 2 n + 1 ) / ( 3 n ( n + 1 ) ) now by hit and trial for the given options , if we put 25 then this will give 17 / 325 therefore the answer is 25 answer : b
|
MathQA
|
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"48 min .",
"50 min .",
"45 min .",
"55 min ."
]
}
|
[
"B"
] |
a man is walking at a speed of 10 km per hour . after every kilometre , he takes rest for 5 minutes . how much time will be take to cover a distance of 5 kilometres ?
|
rest time = number of rest Γ time for each rest = 4 Γ 5 = 20 minutes total time to cover 5 km = ( 5 β 10 Γ 60 ) minutes + 20 minutes = 50 minutes answer b
|
MathQA
|
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"349",
"541.75",
"224.37",
"370.833"
]
}
|
[
"D"
] |
8900 Γ· 6 Γ· 4 = ?
|
explanation : given exp . 8900 * 1 / 6 * 1 / 4 = 370.833 answer : d
|
MathQA
|
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"18.45 %",
"18.46 %",
"18.47 %",
"18.48 %"
]
}
|
[
"B"
] |
a shopkeeper fixes the marked price of an item 30 % above its cost price . the percentage of discount allowed to gain 6 % is
|
"explanation : let the cost price = rs 100 then , marked price = rs 130 required gain = 6 % , so selling price = rs 106 discount = 130 - 106 = 24 discount % = ( 24 / 130 ) * 100 = 18.46 % option b"
|
MathQA
|
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"( n - m )', '",
"mn / ( m + n )', '",
"( nm )', '",
"( n - m ) / ( m + n )', '"
]
}
|
[
"B"
] |
in an electric circuit , two resistors with resistances m and n are connected in parallel . in this case , if p is the combined resistance of these two resistors , then the reciprocal of p is equal to the sum of the reciprocals of m and n . what is p in terms of m and n ?
|
the wording is a bit confusing , though basically we are told that 1 / p = 1 / m + 1 / n , from which it follows that p = mn / ( m + n ) . answer : b
|
MathQA
|
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"rs . 1200",
"rs . 1500",
"rs . 1860",
"rs . 2000"
]
}
|
[
"C"
] |
a alone can finish a work in 10 days which b alone can finish in 15 days . if they work together and finish it , then out of a total wages of rs . 3100 , a will get :
|
explanation : ratio of working days of a : b = 10 : 15 therefore , their wages ratio = reverse ratio = 15 : 10 therefore , a will get 15 units of ratio total ratio = 25 1 unit of ratio = 3100 / 25 = 124 so , a β s amount = 124 Γ 15 = rs . 1860 . answer : option c
|
MathQA
|
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"8.04 kg', '",
"8.14 kg', '",
"8.24 kg', '",
"9.04 kg', '"
]
}
|
[
"A"
] |
the dimensions of an open box are 50 cm , 40 cm and 23 cm . its thickness is 2 cm . if 1 cubic cm of metal used in the box weighs 0.5 gms , find the weight of the box .
|
explanation : volume of the metal used in the box = external volume - internal volume = [ ( 50 x 40 x 23 ) - ( 44 x 34 x 20 ) ] cm 3 = 16080 cm 3 weight of the metal = [ ( 16080 x 0.5 ) / 1000 ] kg = 8.04 kg . answer : a
|
MathQA
|
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"18.75 % loss",
"18.75 % profit",
"33.33 % loss",
"30.33 % loss"
]
}
|
[
"B"
] |
if the cost price of 19 articles is equal to the selling price of 16 articles , what is the percentage of profit or loss that the merchant makes ?
|
"explanation : let cost price of 1 article be re . 1 . therefore , cost price of 19 articles = rs . 19 . selling price of 16 articles = rs . 19 therefore , selling price of 19 articles is : - = > 19 / 16 Γ£ β 19 = > 22.56 . therefore , profit = selling price - cost price . = > 22.56 Γ’ Λ β 19 = 3.56 . hence , the percentage of profit = profit x 100 / c . p . = > 3.56 / 19 Γ£ β 100 . = > 18.75 % profit . answer : b"
|
MathQA
|
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"19,980",
"19,780",
"19,680",
"19,380"
]
}
|
[
"A"
] |
sonika bought a v . c . r . at the list price of 18,500 . if the rate of sales tax was 8 % , find the amount she had to pay for purchasing the v . c . r .
|
sol . list price of v . c . r . = 18,500 rate of sales tax = 8 % β΄ sales tax = 8 % of 18,500 = 8 β 100 Γ 18500 = 1480 so , total amount which sonika had to pay for purchasing the v . c . r . = 18,500 + 1480 = 19,980 . answer a
|
MathQA
|
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"49 m 2",
"50 m 2",
"53.5 m 2",
"55 m 2"
]
}
|
[
"A"
] |
a cistern 6 m long and 4 m wide contains water up to a depth of 1 m 25 cm . the total area of the west surface is :
|
"solution area of the west surface = [ 2 ( lb + bh + lh ) - lb ] = 2 ( bh + lh ) + lb = [ 2 ( 4 Γ 1.25 + 6 Γ 1.25 ) + 6 Γ 4 ] m 2 = 49 m 2 . answer a"
|
MathQA
|
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"rs . 3500",
"rs . 4000",
"rs . 4500",
"rs . 5000"
]
}
|
[
"B"
] |
rakesh credits 15 % of his salary in his fixed deposit account and spends 30 % of the remaining amount on groceries . if the cash in hand is rs . 2380 , what is his salary ?
|
explanation : let salary be rs . x . then , x - 15 % of x - 30 % of 85 % of x = 2380 or x - 15 x / 100 β 30 Γ 85 Γ x / 100 Γ 100 = 2380 or 200 x - 30 x - 51 x = 2380 Γ 2002380 Γ 200 or 119 x = 2380 Γ 2002380 Γ 200 or x 2380 Γ 200 / 119 = 4000 correct option : b
|
MathQA
|
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"rs . 300",
"rs . 200",
"rs . 240",
"rs . 150"
]
}
|
[
"D"
] |
if x gets 25 % more than y and y gets 20 % more than z , the share of z out of rs . 555 will be :
|
"z share = z , y = 1.2 z x = 1.25 Γ£ β 1.2 z , x + y + z = 555 ( 1.25 Γ£ β 1.2 + 1.2 + 1 ) z = 55 3.7 z = 555 , z = 150 answer : . d"
|
MathQA
|
{
"label": [
"B",
"C",
"D",
"E"
],
"text": [
"0",
"3",
"5",
"7"
]
}
|
[
"B"
] |
for integers x , y , and z , if ( 3 ^ x ) ( 4 ^ y ) ( 5 ^ z ) = 13107 , 200000 and x + y + z = 16 , what is the value of xy / z ?
|
the number 13,107 , 200,000 is not divisible by 3 . ( we can verify this by adding the digits of the number to see that the sum is not a multiple of 3 . ) thus x = 0 and xy / z = 0 . the answer is b .
|
MathQA
|
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"7 : 3",
"3 : 7",
"2 : 5",
"5 : 3"
]
}
|
[
"D"
] |
if 40 % of a number is equal to two - thirds of another number , what is the ratio of the first number to the second ?
|
"suppose the first number is x and the second numbery . therefore , 40 % of x = 2 β 3 of y β΄ x β y = 2 β 3 Γ 100 β 40 = 5 β 3 answer d"
|
MathQA
|
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"35.67 %",
"64.75 %",
"68.57 %",
"69.57 %"
]
}
|
[
"B"
] |
in an examination , there were 2,000 candidates , out of which 900 candidates were girls and rest were boys . if 38 % of the boys and 32 % of the girls passed , then the total percentage of failed candidates is ?
|
"girls = 900 , boys = 1100 passed = ( 38 % of 1100 ) + ( 32 % of 900 ) = 418 + 288 = 706 failed = 2000 - 706 = 1294 failed % = [ ( 1294 / 2000 ) x 100 ] % = 64.7 % . answer : b"
|
MathQA
|
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"0.00015",
"0.0015",
"0.015",
"0.15"
]
}
|
[
"B"
] |
0.003 * 0.5 = ?
|
"explanation : 3 * 5 = 15 . sum of decimal places = 4 . 0.003 * 0.5 = 0.0015 = 0.0015 answer b"
|
MathQA
|
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"rs . 432",
"rs . 422",
"rs . 412",
"rs . 442"
]
}
|
[
"A"
] |
the true discount on a bill of rs . 2160 is rs . 360 . what is the banker ' s discount ?
|
"explanation : f = rs . 2160 td = rs . 360 pw = f - td = 2160 - 360 = rs . 1800 true discount is the simple interest on the present value for unexpired time = > simple interest on rs . 1800 for unexpired time = rs . 360 banker ' s discount is the simple interest on the face value of the bill for unexpired time = simple interest on rs . 2160 for unexpired time = 360 / 1800 Γ 2160 = 15 Γ 2160 = rs . 432 answer : option a"
|
MathQA
|
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"rs . 170",
"rs . 17",
"rs . 1.70",
"rs . 4.25"
]
}
|
[
"A"
] |
if 0.5 % of a = 85 paise , then the value of a is ?
|
"answer β΅ 0.5 / 100 of a = 85 / 100 β΄ a = rs . ( 85 / 0.5 ) = rs . 170 correct option : a"
|
MathQA
|
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"rs . 9471",
"rs . 12,628",
"rs . 18,040",
"rs . 7015.56"
]
}
|
[
"D"
] |
suganya and suriya are partners in a business . suganya invests rs . 15,000 for 8 months and suriya invests rs . 42,000 for 10 months . out of a profit of rs . 31,570 . suganya ' s share is
|
"solution ratio of their shares = ( 15000 Γ£ β 8 ) : ( 42000 Γ£ β 10 ) = 2 : 7 . suganya ' s share = rs . ( 31570 Γ£ β 2 / 9 ) = rs . 7015.56 answer d"
|
MathQA
|
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"rs 16123.20",
"rs 16123.30",
"rs 16197.12",
"rs 16123.50"
]
}
|
[
"C"
] |
what will be the compound interest on rs . 40000 after 3 years at the rate of 12 % per annum
|
"explanation : ( 40000 Γ ( 1 + 12 / 100 ) 3 ) = > 40000 Γ 28 / 25 Γ 28 / 25 Γ 28 / 25 = > 56197.12 so compound interest will be 56197.12 - 40000 = rs 16197.12 option c"
|
MathQA
|
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"30",
"40",
"60",
"72"
]
}
|
[
"D"
] |
how many pieces of 75 cm can be cut from a rope 54 meters long ?
|
"explanation : total pieces of 75 cm that can be cut from a rope of 54 meters long is = ( 54 meters ) / ( 75 cm ) = ( 54 meters ) / ( 0.75 meters ) = 72 answer : d"
|
MathQA
|
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"350",
"370",
"390",
"430"
]
}
|
[
"C"
] |
average expenditure of a person for the first 3 days of a week is rs . 350 and for the next 4 days is rs . 420 . average expenditure of the man for the whole week is :
|
"explanation : assumed mean = rs . 350 total excess than assumed mean = 4 Γ ( rs . 420 - rs . 350 ) = rs . 280 therefore , increase in average expenditure = rs . 280 / 7 = rs . 40 therefore , average expenditure for 7 days = rs . 350 + rs . 40 = rs . 390 correct option : c"
|
MathQA
|
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"rs . 473",
"rs . 374",
"rs . 495",
"rs . 157"
]
}
|
[
"D"
] |
compound interest of rs . 1000 at 10 % per annum for 1 1 / 2 years will be ( interest compounded half yearly ) .
|
"10 % interest per annum will be 5 % interest half yearly for 3 terms ( 1 1 / 2 years ) so compound interest = 3000 [ 1 + ( 5 / 100 ) ] ^ 3 - 1000 = 1000 [ ( 21 / 20 ) ^ 3 - 1 ] = 1000 ( 9261 - 8000 ) / 8000 = 1 * 1261 / 8 = 157 answer : d"
|
MathQA
|
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"1 / 4",
"1 / 5",
"3 / 10",
"1 / 11"
]
}
|
[
"C"
] |
what will be the fraction of 30 %
|
"explanation : it will 30 * 1 / 100 = 3 / 10 option c"
|
MathQA
|
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"98",
"165",
"180",
"253"
]
}
|
[
"B"
] |
solve for x and check : 15 x = 165
|
solution : dividing each side by 15 , we obtain ( 15 x / 15 ) = ( 165 / 15 ) therefore : x = 11 check : 15 x = 165 ( 15 * 11 ) = 165 165 = 165 answer : b
|
MathQA
|
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"rs . 2500",
"rs . 2300",
"rs . 2200",
"rs . 1400"
]
}
|
[
"A"
] |
if the price of 357 apples is rs . 1517.25 , what will be the approximate price of 49 dozens of such apples
|
"let the required price be x more apples , more price ( direct proportion ) hence we can write as apples 357 : ( 49 Γ 12 ) } : : 1517.25 : x β 357 x = ( 49 Γ 12 ) Γ 1517.25 β x = ( 49 Γ 12 Γ 1517.25 ) / 357 = ( 7 Γ 12 Γ 1517.25 ) / 51 = ( 7 Γ 4 Γ 1517.25 ) / 17 = 7 Γ 4 Γ 89.25 β 2500 . answer a"
|
MathQA
|
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"82 m",
"150 m",
"172 m",
"200 m"
]
}
|
[
"D"
] |
two trains of equal length are running on parallel lines in the same directions at 46 km / hr . and 36 km / hr . the faster trains pass the slower train in 144 seconds . the length of each train is :
|
"explanation : the relative speed of train is 46 - 36 = 10 km / hr = ( 10 x 5 ) / 18 = 25 / 9 m / s 10 Γ 518 = 259 m / s in 144 secs the total distance traveled is 144 x 25 / 9 = 400 m . therefore the length of each train is = 400 / 2 = 200 m . answer d"
|
MathQA
|
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"6.25",
"6.5",
"6.75",
"7"
]
}
|
[
"A"
] |
in the first 10 overs of a cricket game , the run rate was only 3.2 . what should be the run rate in the remaining 40 0 vers to reach the target of 282 runs ?
|
"sol . required run rate = 282 β ( 3.2 Γ 10 / 40 ) = 240 / 40 = 6.25 . answer a"
|
MathQA
|
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"rs . 571200",
"rs . 180000",
"rs . 201600",
"rs . 504000"
]
}
|
[
"A"
] |
the monthly incomes of a and b are in the ratio 5 : 2 . b ' s monthly income is 12 % more than c ' s monthly income . if c ' s monthly income is rs . 17000 , then find the annual income of a ?
|
"b ' s monthly income = 17000 * 112 / 100 = rs . 19040 b ' s monthly income = 2 parts - - - - > rs . 19040 a ' s monthly income = 5 parts = 5 / 2 * 19040 = rs . 47600 a ' s annual income = rs . 47600 * 12 = rs . 571200 answer : a"
|
MathQA
|
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"rs . 950",
"rs . 1500",
"rs . 1000",
"rs . 1200"
]
}
|
[
"D"
] |
a trader sells 40 metres of cloth for rs . 8200 at a profit of rs . 30 per metre of cloth . how much profit will the trder earn on 40 metres of cloth ?
|
"explanation : sp of 1 metre cloth = 8200 / 40 = rs . 205 . cp of 1 metre cloth = rs . 205 β 30 = rs . 175 cp on 40 metres = 175 x 40 = rs . 7000 profit earned on 40 metres cloth = rs . 8200 β rs . 7000 = rs . 1200 . answer : option d"
|
MathQA
|
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"2 : 4",
"4 : 3",
"6 : 7",
"9 : 16"
]
}
|
[
"A"
] |
two trains , one from howrah to patna and the other from patna to howrah , start simultaneously . after they meet , the trains reach their destinations after 16 hours and 4 hours respectively . the ratio of their speeds is :
|
"let us name the trains as a and b . then , ( a ' s speed ) : ( b ' s speed ) = Γ’ Λ Ε‘ b : Γ’ Λ Ε‘ a = Γ’ Λ Ε‘ 4 : Γ’ Λ Ε‘ 16 = 2 : 4 . answer a"
|
MathQA
|
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"3 / 1",
"3 / 2",
"5 / 2",
"5 / 3"
]
}
|
[
"B"
] |
kul is 22 years old and saras is 33 years . find the ratio of saras ' s age to kul ' s age .
|
explanation : kul is 22 years old . saras is 33 years old . saras ' s age : kul ' s age = 33 : 22 = 3 : 2 answer : b
|
MathQA
|
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"144 mins",
"140 mins",
"136 mins",
"132 minw"
]
}
|
[
"B"
] |
one pipe can fill a tank three times as fast as another pipe . if together the two pipes can fill the tank in 35 minutes , then the slower pipe alone will be able to fill the tank in
|
"explanation : let the slower pipe alone fill the tank in x minutes then faster will fill in x / 3 minutes . part filled by slower pipe in 1 minute = 1 / x part filled by faster pipe in 1 minute = 3 / x part filled by both in 1 minute = 1 / x + 3 / x = 1 / 35 = > 4 / x = 1 / 35 x = 35 β 4 = 140 mins option b"
|
MathQA
|
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"1 / 35",
"3 / 35",
"1 / 21",
"2 / 35"
]
}
|
[
"C"
] |
the hcf and lcm of two numbers m and n are respectively 6 and 210 . if m + n = 60 , then 1 / m + 1 / n is equal to
|
"answer we have , m x n = 6 x 210 = 1260 Γ’ Λ Β΄ 1 / m + 1 / n = ( m + n ) / mn = 60 / 1260 = 1 / 21 correct option : c"
|
MathQA
|
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"25.25 s",
"17.45 s",
"35.75 s",
"41.45 s"
]
}
|
[
"D"
] |
there are 20 poles with a constant distance between each pole . a car takes 24 seconds to reach the 12 th pole . how much time will it take to reach the last pole ?
|
let the distance between each pole be x m . then , the distance up to 12 th pole = 11 xm speed = 11 x β 24 m / s time taken to covers the total distance of 19 x = 19 x Γ 24 / 11 x = 41.45 s answer d
|
MathQA
|
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"1.2",
"1.45",
"2.2",
"2.9"
]
}
|
[
"D"
] |
given that 100.48 = x , 100.70 = y and xz = y Β² , then the value of z is close to
|
sol . xz = y Β² β ( 10 0.48 ) z ( 100.70 ) 2 ( 10 0.48 z ) = 10 ( 2 Γ 0.70 ) = 101.40 β 0.48 z = 1.40 β z = 140 / 48 = 35 / 12 = 2.9 ( approx ) . answer d
|
MathQA
|
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"2984",
"2983",
"3500",
"2981"
]
}
|
[
"C"
] |
3550 - ( 1002 / 20.04 ) = ?
|
"3550 - 50 = 3500 answer : c"
|
MathQA
|
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"20,20",
"20,10",
"25,9",
"30,10"
]
}
|
[
"C"
] |
the ages of two persons differ by 16 years . if 5 years ago , the elder one be 5 times as old as the younger one , their present ages ( in years ) are respectively
|
"explanation : let their ages be x and ( x + 16 ) years . 5 ( x - 5 ) = ( x + 16 - 5 ) or 4 x = 36 or x = 9 . their present ages are 25 years and 9 years option c"
|
MathQA
|
{
"label": [
"B",
"C",
"D",
"E"
],
"text": [
"6 p . m .",
"3 pm .",
"2 p . m .",
"1 p . m ."
]
}
|
[
"B"
] |
the distance between 2 cities a and b is 1000 km . a train starts from a at 1 p . m . and travels towards b at 100 km / hr . another starts from b at 2 p . m . and travels towards a at 150 km / hr . at what time do they meet ?
|
"suppose they meet x hrs after 1 p . m . distance moved by first in x hrs + distance moved by second in ( x - 1 ) hrs = 1000 100 x + 150 ( x - 1 ) = 1000 x = 4.60 = 5 hrs they meet at 1 + 5 = 6 p . m . answer is b"
|
MathQA
|
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"rs . 169.50",
"rs . 1700",
"rs . 175.50",
"rs . 180"
]
}
|
[
"C"
] |
tea worth rs . 126 per kg are mixed with a third variety in the ratio 1 : 1 : 2 . if the mixture is worth rs . 153 per kg , the price of the third variety per kg will be
|
"solution since first second varieties are mixed in equal proportions , so their average price = rs . ( 126 + 135 / 2 ) = rs . 130.50 so , the mixture is formed by mixing two varieties , one at rs . 130.50 per kg and the other at say , rs . x per kg in the ratio 2 : 2 , i . e . , 1 : 1 . we have to find x . x - 153 / 22.50 = 1 = βΊ x - 153 = 22.50 = βΊ x = 175.50 . hence , price of the third variety = rs . 175.50 per kg . answer c"
|
MathQA
|
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"2 : 3",
"3 : 4",
"9 : 80",
"20 : 3"
]
}
|
[
"C"
] |
if 0.8 of a number is equal to 0.09 of another number , the ratio of the numbers i
|
"sol . 0.8 a = 0.09 b Γ’ β‘ β a / b = 0.09 / 0.8 = 9 / 80 = . Γ’ Λ Β΄ a : b = 9 : 80 . answer c"
|
MathQA
|
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"55', '",
"70', '",
"57', '",
"58', '"
]
}
|
[
"B"
] |
a rectangular plot measuring 90 metres by 50 metres is to be enclosed by wire fencing . if the poles of the fence are kept 4 metres apart , how many poles will be needed ?
|
solution perimeter of the plot = 2 ( 90 + 50 ) = 280 m . β΄ number of poles = [ 280 / 4 ] = 70 m answer b
|
MathQA
|
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"10', '",
"11', '",
"12', '",
"13', '"
]
}
|
[
"C"
] |
if the capacity of a cylindrical tank is 1848 m 3 and the diameter of its base is 14 m , then find the depth of the tank .
|
let the depth of the tank be h meters . then , β x 72 x h = 1848 ο h = ( 1848 x ( 7 / 22 ) x ( 1 / 49 ) = 12 m answer is c
|
MathQA
|
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"rs . 234.80",
"rs . 334.80",
"rs . 434.80",
"rs . 534.80"
]
}
|
[
"B"
] |
a tank is 25 m long 12 m wide and 6 m deep . the cost of plastering its walls and bottom at 45 paise per sq m is
|
"explanation : area to be plastered = [ 2 ( l + b ) Γ£ β h ] + ( l Γ£ β b ) = [ 2 ( 25 + 12 ) Γ£ β 6 ] + ( 25 Γ£ β 12 ) = 744 sq m cost of plastering = 744 Γ£ β ( 45 / 100 ) = rs . 334.80 answer : b"
|
MathQA
|
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"14 m",
"24 m",
"28 m",
"40 m"
]
}
|
[
"C"
] |
for covering 88 km a wheel revolve 1000 times . what is the radius of wheel ?
|
distance travel in 1 round = 88000 / 1000 m = 88 m perimeter = 88 m , 2 Ο r = 882 r = [ 88 * 7 / 22 ] = 28 m hence , diameter = 28 m answer c
|
MathQA
|
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"5",
"10",
"15",
"20"
]
}
|
[
"B"
] |
a retailer buys 40 pens at the market price of 36 pens from a wholesaler , if he sells these pens giving a discount of 1 % , what is the profit % ?
|
"let the market price of each pen be rs 1 then , c . p of 40 pens = rs 36 s . p of 40 pens = 99 % of rs 40 = rs 39.60 profit % = ( ( 3.60 * 100 ) / 36 ) % = 10 % answer is b ."
|
MathQA
|
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"rs . 768",
"rs . 968",
"rs . 1960",
"rs . 2400"
]
}
|
[
"A"
] |
if the true discount on a sum due 2 years hence at 14 % per annum be rs . 168 , the sum due is :
|
solution p . w = 100 xt . d . / r x t = 100 x 168 / 14 x 2 = 600 . β΄ sum = ( p . w . + td . ) = rs . 768 . answer a
|
MathQA
|
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"36",
"42",
"44",
"43"
]
}
|
[
"D"
] |
if p and q are positive integers each greater than 1 , and 17 ( p + 1 ) = 28 ( q + 1 ) , what is the least possible value of p + q ?
|
"17 ( p + 1 ) = 29 ( q + 1 ) - - > ( p + 1 ) / ( q + 1 ) = 28 / 17 - - > the least positive value of p + 1 is 28 , so the least value of p is 27 and the least positive value of q + 1 is 17 , so the least value of q is 16 - - > the least value of p + q is 27 + 16 = 43 . answer : d"
|
MathQA
|
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"350 m",
"200 m",
"400 m",
"900 m"
]
}
|
[
"D"
] |
a thief is spotted by a policeman from a distance of 225 meters . when the policeman starts the chase , the thief also starts running . if the speed of the thief be 8 km / hr and that of the policeman 10 km / hr , how far the thief will have run before he is overtaken ?
|
"relative speed of the policeman = ( 10 - 8 ) km / hr = 2 km / hr . time taken by police man to cover ( 225 m / 1000 ) x 1 / 2 hr = 9 / 80 hr . in 9 / 80 hrs , the thief covers a distance of 8 x 9 / 80 km = 9 / 10 km = 900 m answer is d ."
|
MathQA
|
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"100 m",
"80 m",
"130 m",
"150 m"
]
}
|
[
"B"
] |
a policeman noticed a criminal from a distance of 180 km . the criminal starts running and the policeman chases him . the criminal and the policeman run at the rate of 8 km and 10 km per hour respectively . what is the distance between them after 3 minutes ?
|
"explanation : solution : relative speed = ( 10 - 8 ) = 2 km / hr . distance covered in 3 minutes = ( 2 * 3 / 60 ) km = 1 / 10 km = 100 m . . ' . distance between the criminal and policeman = ( 180 - 100 ) m = 80 m . answer : b"
|
MathQA
|
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"85",
"94",
"82",
"72"
]
}
|
[
"C"
] |
the sum of digits of a two digit number is 10 , the difference between the digits is 6 . find the number
|
description : = > x + y = 10 , x - y = 6 adding these 2 x = 16 = > x = 8 , y = 2 . thus the number is 82 answer c
|
MathQA
|
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"60 m 2",
"64 m 2",
"68 m 2",
"66 m 2"
]
}
|
[
"D"
] |
the diameter of a garden roller is 1.4 m and it is 3 m long . how much area will it cover in 5 revolutions ? ( use Γ― β¬ = 22 Γ’ Β β 7 )
|
"required area covered in 5 revolutions = 5 Γ£ β 2 Γ― β¬ rh = 5 Γ£ β 2 Γ£ β 22 Γ’ Β β 7 Γ£ β 0.7 Γ£ β 3 = 66 m 2 answer d"
|
MathQA
|
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"1 / 20",
"1 / 50",
"1 / 75",
"2 / 25"
]
}
|
[
"D"
] |
what will be the fraction of 8 %
|
"explanation : 8 * 1 / 100 = 2 / 25 . option d"
|
MathQA
|
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"rs . 1148",
"rs . 1160",
"rs . 1190",
"rs . 1202"
]
}
|
[
"A"
] |
a man buys a cycle for rs . 1400 and sells it at a loss of 18 % . what is the selling price of the cycle ?
|
"solution s . p = 82 % of rs . 1400 = rs . ( 82 / 100 Γ 1400 ) rs . 1148 . answer a"
|
MathQA
|
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"47.55 kgs",
"48 kgs",
"48.55 kgs",
"49.25 kgs"
]
}
|
[
"C"
] |
the average weight of 16 boys in a class is 50.25 kgs and that of the remaining 8 boys is 45.15 kgs . find the average weight of all the boys in the class .
|
"solution required average = ( 50.25 x 16 + 45.15 x 8 / 16 + 8 ) = ( 804 + 361.20 / 24 ) = 1165.20 / 24 = 48.55 answer c"
|
MathQA
|
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"2 β 2",
"4",
"5",
"4 β 2"
]
}
|
[
"B"
] |
16 meters of wire is available to fence off a flower bed in the form of a circular sector . what must the radius of the circle in meters be , if we wish to have a flower bed with the greatest possible surface area ?
|
"area of sector , a = x / 360 * pi * r ^ 2 circumference of the sector = 16 = > x / 360 * 2 * pi * r + 2 r = 16 = > 2 a / r + 2 r = 16 = > a = ( r 16 - 2 r ^ 2 ) / 2 = r 8 - r ^ 2 we will now max using derivations max value of a will found at a = 0 i . e 8 - 2 r = 0 r = 4 b"
|
MathQA
|
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"180 m 2', '",
"164 m 2', '",
"152 m 2', '",
"143 m 2', '"
]
}
|
[
"D"
] |
a square carpet with an area 169 m 2 must have 2 metres cut - off one of its edges in order to be a perfect fit for a rectangular room . what is the area of rectangular room ?
|
side of square carpet = β area = β 169 = 13 m after cutting of one side , measure of one side = 13 β 2 = 11 m and other side = 13 m ( remain same ) β΄ area of rectangular room = 13 Γ 11 = 143 m 2 answer d
|
MathQA
|
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"9,6",
"8,2",
"9,3",
"6,6"
]
}
|
[
"B"
] |
a man can row downstream at the rate of 10 km / hr and upstream at 6 km / hr . find man ' s rate in still water and the rate of current ?
|
"explanation : rate of still water = 1 / 2 ( 10 + 6 ) = 8 km / hr rate of current = 1 / 2 ( 10 - 6 ) = 2 km / hr answer : option b"
|
MathQA
|
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"229.623",
"224.777",
"233.523",
"414.637"
]
}
|
[
"A"
] |
897.7 β 573.07 β 95.007 = ?
|
"solution given expression = 897.7 - ( 573.07 + 95.007 ) = 897.7 - 668.077 = 229.623 . answer a"
|
MathQA
|
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
". 7",
". 07",
". 007",
". 0007"
]
}
|
[
"A"
] |
. 007 / ? = . 01
|
"let . 007 / x = . 01 ; then x = . 007 / . 01 = . 7 / 1 = . 7 answer is a"
|
MathQA
|
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"3.75 kg",
"2.4 kg",
"2.5 kg",
"10 kg"
]
}
|
[
"A"
] |
fresh grapes contain 90 % by weight while dried grapes contain 20 % water by weight . what is the weight of dry grapes available from 30 kg of fresh grapes ?
|
"the weight of non - water in 30 kg of fresh grapes ( which is 100 - 90 = 10 % of whole weight ) will be the same as the weight of non - water in x kg of dried grapes ( which is 100 - 20 = 80 % of whole weight ) , so 30 Γ’ Λ β 0.1 = x Γ’ Λ β 0.8 - - > x = 3.75 answer : a"
|
MathQA
|
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"1 : 2",
"3 : 4",
"3 : 5",
"2 : 3"
]
}
|
[
"D"
] |
the average age of a class is 15.8 years . the average age of boys in the class is 16.4 years while that of girls is 15.4 years . what is the ratio of boys to girls in the class ?
|
let x = number of girls y = number of boys sum of girls ages / x = 15.4 sum of boys ages / y = 16.4 the sum of the girls ' ages is 15.4 x , and boys ' sum is 16.4 y ( sum of girls ages + sum of boys ages ) / ( x + y ) = 15.8 ( 15.4 x + 16.4 y ) / ( x + y ) = 15.8 15.4 x + 16.4 y = 15.8 ( x + y ) 15.4 x + 16.4 y = 15.8 x + 15.8 y 0.6 y = 0.4 x 0.6 y / x = 0.4 y / x = 0.4 / 0.6 y / x = 2 / 3 which is the ratio of boys to girls answer : d
|
MathQA
|
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"0.93",
"9.4",
"0.094",
"94"
]
}
|
[
"A"
] |
subtracting 7 % of a from a is equivalent to multiplying a by how much ?
|
"answer let a - 7 % of a = ab . β ( 93 x a ) / 100 = ab β΄ b = 0.93 correct option : a"
|
MathQA
|
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"rs . 2250', '",
"rs . 3600', '",
"rs . 2700', '",
"rs . 1800', '"
]
}
|
[
"D"
] |
paper charge is rs . 60 per kg . how much expenditure would be there to cover a cube of edge 10 m with a paper , if one kg of paper covers 20 sq . m . area ?
|
explanation : total surface area of the cube = 6 x ( 10 ) 2 = 600 sq . m 1 kg covers 20 sq . m area , for 600 we need = 600 / 20 = 30 kg paper . expenditure = rate x quantity = rs . 60 x 30 kg = rs . 1800 answer is d
|
MathQA
|
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"3 : 1",
"3 : 2",
"4 : 3",
"7 : 3"
]
}
|
[
"D"
] |
in what ratio must tea at rs . 60 per kg be mixed with tea at rs . 70 per kg so that the mixture must be worth rs . 63 per kg ?
|
"required ratio = 700 : 300 = 7 : 3 answer d"
|
MathQA
|
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"20",
"27",
"28",
"30"
]
}
|
[
"B"
] |
the average of the first 5 multiples of 9 is :
|
solution : required average = ( total sum of multiple of 9 ) / 5 = ( 9 + 18 + 27 + 36 + 45 ) / 5 = 27 note that , average of 9 and 45 is also 27 . and average of 18 and 36 is also 27 . answer : option b
|
MathQA
|
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"rs . 72",
"rs . 60",
"rs . 75",
"rs . 76"
]
}
|
[
"A"
] |
the cost of an article was rs . 75 . the cost was first increased by 20 % and later on it was reduced by 20 % . the present cost of the article is :
|
solution : initial cost = rs . 75 after 20 % increase in the cost , it becomes , ( 75 + 20 % of 75 ) = rs . 90 now , cost is decreased by 20 % , so cost will become , ( 90 - 20 % of 90 ) = rs . 72 . so , present cost is rs . 72 . mind calculation method : 75 - - - - - 20 % β - - β 90 - - - - - 20 % β - - - - - β 72 . answer : option a
|
MathQA
|
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"rs . 700",
"rs . 708.50",
"rs . 732.50",
"rs . 742.50"
]
}
|
[
"D"
] |
a rectangular grassy plot 100 m . by 70 m has a gravel path 2.5 m wide all round it on the inside . find the cost of gravelling the path at 90 paise per sq . metre .
|
"explanation : area of the plot = ( 100 x 70 ) m 2 = 7000 m 2 area of the plot excluding the path = [ ( 100 - 5 ) * ( 70 - 5 ) ] m 2 = 6175 m 2 . area of the path = ( 7000 - 6175 ) m 2 = 825 m 2 . cost of gravelling the path = rs . 825 * ( 90 / 100 ) = rs . 742.50 answer : option d"
|
MathQA
|
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"2984",
"3029",
"2982",
"2981"
]
}
|
[
"B"
] |
3034 - ( 1002 / 200.4 ) = ?
|
"3034 - 5 = 3029 answer : b"
|
MathQA
|
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"65",
"69",
"72",
"75"
]
}
|
[
"D"
] |
kamal obtained 76 , 65 , 82 , 67 and 85 marks ( out of 100 ) in english , mathematics , physics , chemistry and biology . what are his average marks ?
|
"sol . average = 76 + 65 + 82 + 67 + 85 / 5 ) = ( 375 / 5 ) = 75 . answer d"
|
MathQA
|
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"4 %",
"6 %",
"5 %",
"50 %"
]
}
|
[
"C"
] |
the population of a town increased from 1 , 75000 to 2 , 62500 in a decade . what is the average percent increase of population per year ?
|
explanation : increase in the population in 10 years = 2 , 62500 - 1 , 75000 = 87500 % ncrease in the population in 10 years = ( 87500 / 175000 ) Γ 100 = 8750 / 175 = 50 % average % increase of population per year = 50 % / 10 = 5 % answer : option c
|
MathQA
|
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"364724",
"365387",
"365737",
"366757"
]
}
|
[
"C"
] |
on dividing a number by 999 , the quotient is 366 and the remainder is 103 . the number is :
|
"required number = 999 * 366 + 103 = ( 1000 - 1 ) * 366 + 103 = 366000 - 366 + 103 = 365737 . answer : c"
|
MathQA
|
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"12 h",
"10 h",
"8 h",
"6 h"
]
}
|
[
"C"
] |
the area of a square field is 576 km 2 . how long will it take for a horse to run around at the speed of 12 km / h ?
|
"area of field = 576 km 2 . then , each side of field = β 576 = 24 km distance covered by the horse = perimeter of square field = 24 Γ 4 = 96 km β΄ time taken by horse = distances / peed = 96 / 12 = 8 h answer c"
|
MathQA
|
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"46.2 %",
"54.54 %",
"63 %",
"70 %"
]
}
|
[
"B"
] |
a cricketer scored 132 runs which included 12 boundaries and 2 sixes . what percent of his total score did he make by running between the wickets .
|
"explanation : number of runs made by running = 132 - ( 12 x 4 + 2 x 6 ) = 132 - ( 60 ) = 72 now , we need to calculate 72 is what percent of 132 . = > 72 / 132 * 100 = 54.54 % answer : b"
|
MathQA
|
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