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ex_3_5.sce
//Example 3.5: miller indices clc; clear; close; //given data x1=1;// x2=1;// x3=0;// h1=1/x1// h2=1/x2;// h3=%inf;// disp("Miller indices of the plane (110) are: "+string(h1)+","+string(h2)+","+string(h3)) x11=1;// x21=1;// x31=1;// h11=1/x11;// h21=1/x21;// h31=1/x31;// disp("Miller indices of the plane (111) are : "+string(h11)+","+string(h21)+","+string(h31))
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EX31_4.sce
// Grob's Basic Electronics 11e // Chapter No. 31 // Example No. 31_4 clear; clc; // Calculate the following quantities Pl, Pcc & percent efficiency // Given data Rl = 8; // Load Resistor=8 Ohms Vopp = 50; // Output Voltage(p-p)=50 Volts(p-p) Vcc = 30; // Supply Voltage(Collector)=30 Volts Vopk = Vopp/2; // Output Voltage(peak) Pl = (Vopp*Vopp)/(8*Rl); disp (Pl,'The Load Power in Watts'); Pcc = Vcc*0.636*(Vopk/Rl); disp (Pcc,'The DC Input Power in Watts') efficiency = ((Pl/Pcc)*100); disp (efficiency,'The Efficiency in % is');
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ex25.sce
clear clc xset('window',3) xtitle("My Graph","X axis","Y axis") x=linspace(0,3,30) y1=-sec(x) y2=cosh(x) plot(x,y1,"o-") plot(x,y2,"+-") legend("-sec(x)","cosh(x)") disp("from the graph,it is clear that the point of intersection is nearly x=2.3 ")
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Example13_8.sce
//Example 13.8 clear; clc; fOmin=1*10^6; fI=1*10^3; fOmax=2*10^6; Nmin=fOmin/fI; Nmax=fOmax/fI; f0=(fOmin+fOmax)/2; fR=f0/2; vEmax=3.9; vEmin=1.1; Ko=(2*%pi*2*fR)/(vEmax-vEmin); R1=28*10^3; R2=287*10^3; C=110*10^(-12); VDD=5; Kd=5/(4*%pi); Kv=10^4; Nmean=sqrt(Nmin*Nmax); Kvmean=(Kd*Ko)/Nmean; zeta=0.707; fI=1*10^3; wI=2*%pi*fI; wn=wI/20; wp=(wn^2)/Kv; wz=wn/(2*zeta); printf("R1=%.1f kohms",R1*10^(-3)); printf("\nR2=%.f kohms",R2*10^(-3)); printf("\nC=%.f pF",C*10^12); printf("\nfI=%.d kHz",fI*10^(-3)); R3=6.17*10^3; R4=3.45*10^3; C1=1*10^(-6); //Filter Components are taken from figure 13.33, as no procedure is mentioned for designing the filter printf("\nFilter Components :"); printf("\nR3=%.2f kohms",R3*10^(-3)); printf("\nC1=%.f uF",C1*10^6); printf("\nR4=%.2f kohms",R4*10^(-3));
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Ex25_18.sce
clear //Given T=30.0 //Calculation // l=0.693/T T1=1/l t=log(4)/l t1=log(8)/l //Result printf("\n (i) average life is %0.4f /day",l) printf("\n (ii) The time taken for 3/4 of the original no. to disintegrate is %0.2f days",T1) printf("\n (iii) Time taken is %0.0f days",t) printf("\n (iv) Time taken is %0.0f days",t1)
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Ex9_10.sce
clc kbT = 0.026 disp("kbT = "+string(kbT)+"eV") //initializing value of kbT at 300K apsilen = 11.9*8.85*10^-14 disp("apsilen = "+string(apsilen)+"F/cm") //initializing value of relative permitivity e = 1.6*10^-19 disp("e= "+string(e)+"C")//initializing value of charge of electron Na=2*10^16 disp("Na = "+string(Na)+"cm^-3") //initializing value of doped carrier concentration ni = 1.5*10^10 disp("ni= "+string(ni)+"cm^-3")//initializing value of intrinsic carrier concentration VSB = 1 disp("VSB= "+string(VSB)+"V")//initializing value of sorce body voltage apsilen_ox = 3.9*8.85*10^-14 disp("apsilen_ox= "+string(apsilen_ox))//initializing value of relative permitivity of oxide dox = 500*10^-8 disp("dox= "+string(dox)+"cm")//initializing value of thickness of oxide Cox = apsilen_ox/dox disp("The oxide capicitance per unit area is ,Cox = apsilen_ox/dox= "+string(Cox)+" F*cm^-2")//calculation phi_F= (-kbT*log(Na/ni)) disp("The potential phi_F= (-kbT*log(Na/ni))= "+string(phi_F)+" V")//calculation dVT = ((sqrt(2*e*apsilen*Na)/Cox)*((sqrt((-2*phi_F)+VSB)-sqrt(-2*phi_F)))) disp(" The shift in threshold voltage is ,dVT = ((sqrt(2*e*apsilen*Na)/Cox)*((sqrt((-2*phi_F)+VSB)-sqrt(-2*phi_F)))) = "+string(dVT)+" V")//calculation
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/examples/Presentation Packs/Cognitive Psychology Experiments III (Version 3)/Vigilance/Scenarios/Vigilance.sce
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Vigilance.sce
# -------------------------- Header Parameters -------------------------- scenario = "Vigilance"; write_codes = EXPARAM( "Send ERP Codes" ); default_font_size = EXPARAM( "Default Font Size" ); default_background_color = EXPARAM( "Default Background Color" ); default_text_color = EXPARAM( "Default Font Color" ); default_font = EXPARAM( "Default Font" ); max_y = 100; active_buttons = 1; response_matching = simple_matching; stimulus_properties = event_cond, string, block_name, string, block_number, number, trial_number, number, tgt_location, string, stim_type, string, ISI_dur, number; event_code_delimiter = ";"; # ------------------------------- SDL Part ------------------------------ begin; trial { trial_duration = forever; trial_type = specific_response; terminator_button = 1; picture { text { caption = "Instructions"; preload = false; } instruct_text; x = 0; y = 0; }; } instruct_trial; trial { clear_active_stimuli = false; stimulus_event { picture {} stim_pic; } stim_event; } stim_trial; trial { stimulus_event { picture { text { caption = "+"; font_size = EXPARAM( "Fixation Point Size" ); font_color = EXPARAM( "Fixation Point Color" ); } fix_text; x = 0; y = 0; } ISI_pic; code = "ISI"; } ISI_event; } ISI_trial; # ----------------------------- PCL Program ----------------------------- begin_pcl; include_once "../../Library/lib_visual_utilities.pcl"; include_once "../../Library/lib_utilities.pcl"; # --- Constants --- string SPLIT_LABEL = "[SPLIT]"; string LINE_BREAK = "\n"; int BUTTON_FWD = 1; int BUTTON_BWD = 0; string STIM_EVENT_CODE = "Stim"; string PRACTICE_TYPE_PRACTICE = "Practice"; string PRACTICE_TYPE_MAIN = "Main"; string COND_TGT = "Target"; string COND_NTGT = "Non-target"; string LANGUAGE_FILE_TOTAL_BLOCKS_LABEL = "[TOTAL_BLOCKS]"; string LANGUAGE_FILE_BLOCK_NUMBER_LABEL = "[BLOCK_NUMBER]"; string TARGET_SIDE_LABEL = "[TARGET_SIDE]"; string TGT_LEFT = "Left"; string TGT_RIGHT = "Right"; string TGT_TOP = "Top"; string TGT_BOTTOM = "Bottom"; int PORT_CODE_TGT = 10; int PORT_CODE_NTGT = 110; int COND_TGT_IDX = 1; int COND_NTGT_IDX = 2; int BUTTON_TGT = 1; int BUTTON_NTGT = 0; string CHARACTER_WRAP = "Character"; # --- Set up fixed stimulus parameters --- string language = parameter_manager.get_string( "Language" ); language_file lang = load_language_file( scenario_directory + language + ".xml" ); bool char_wrap = ( get_lang_item( lang, "Word Wrap Mode" ).lower() == CHARACTER_WRAP.lower() ); adjust_used_screen_size( parameter_manager.get_bool( "Use Widescreen if Available" ) ); double font_size = parameter_manager.get_double( "Default Font Size" ); trial_refresh_fix( stim_trial, parameter_manager.get_int( "Stimulus Duration" ) ); # --- Stimulus Setup --- array<double> stim_locs[2][2] = { { 0.0, 0.0 }, { 0.0, 0.0 } }; string tgt_pos = parameter_manager.get_string( "Target Position" ); box stim_box = new box( 1.0, 1.0, parameter_manager.get_color( "Stimulus Box Color" ) ); box tgt_box = new box( 1.0, 1.0, parameter_manager.get_color( "Target Color" ) ); int box_part; begin; # Grab the box dimensions from parameter settings, exit if bad array<double> stim_dims[0]; parameter_manager.get_doubles( "Stimulus Box Dimensions", stim_dims ); if ( stim_dims.count() != 2 ) then exit( "Error: 'Stimulus Box Dimensions' must contain two values (width and height)." ); end; array<double> tgt_dims[0]; parameter_manager.get_doubles( "Target Dimensions", tgt_dims ); if ( tgt_dims.count() != 2 ) then exit( "Error: 'Target Dimensions' must contain two values (width and height)." ); end; # Set the box sizes stim_box.set_width( stim_dims[1] ); stim_box.set_height( stim_dims[2] ); tgt_box.set_width( tgt_dims[1] ); tgt_box.set_height( tgt_dims[2] ); # Find the positions of the tgt and stimulus boxes # Based on buffer size and parameter setting double buffer = parameter_manager.get_double( "Target Position Buffer" ); if ( tgt_pos == TGT_LEFT ) || ( tgt_pos == TGT_RIGHT ) then if ( tgt_dims[1] + buffer >= ( stim_dims[1]/2.0 ) ) then exit( "Error: Target width must be less than half the total stimulus width for left/right targets." ); end; double temp_pos = ( stim_dims[1]/2.0 ) - ( tgt_dims[1]/2.0 ) - buffer; if ( tgt_pos == TGT_LEFT ) then stim_locs[COND_TGT_IDX][1] = -temp_pos; stim_locs[COND_NTGT_IDX][1] = temp_pos; else stim_locs[COND_TGT_IDX][1] = temp_pos; stim_locs[COND_NTGT_IDX][1] = -temp_pos; end; else if ( tgt_dims[2] + buffer >= ( stim_dims[2]/2.0 ) ) then exit( "Error: Target height must be less than half the total stimulus height for top/bottom targets." ); end; double temp_pos = ( stim_dims[2]/2.0 ) - ( tgt_dims[2]/2.0 ) - buffer; if ( tgt_pos == TGT_TOP ) then stim_locs[COND_TGT_IDX][2] = temp_pos; stim_locs[COND_NTGT_IDX][2] = -temp_pos; else stim_locs[COND_TGT_IDX][2] = -temp_pos; stim_locs[COND_NTGT_IDX][2] = temp_pos; end; end; # Add the stim and tgt to the stim picture stim_pic.add_part( stim_box, 0, 0 ); stim_pic.add_part( tgt_box, 0, 0 ); box_part = stim_pic.part_count(); # Build the ISI pic ISI_pic.clear(); if ( parameter_manager.get_bool( "Show Stimulus Box During ISI" ) ) then ISI_pic.add_part( stim_box, 0, 0 ); fix_text.set_background_color( parameter_manager.get_color( "Stimulus Box Color" ) ); fix_text.redraw(); end; if ( parameter_manager.get_bool( "Show Fixation Point" ) ) then ISI_pic.add_part( fix_text, 0, 0 ); fix_text.redraw(); end; end; # --- sub main_instructions --- # string next_screen = get_lang_item( lang, "Next Screen Caption" ); string prev_screen = get_lang_item( lang, "Previous Screen Caption" ); string final_screen = get_lang_item( lang, "Start Experiment Caption" ); string split_final_screen = get_lang_item( lang, "Multi-Screen Start Experiment Caption" ); bool split_instrucs = parameter_manager.get_bool( "Multi-Screen Instructions" ); sub main_instructions( string instruct_string ) begin bool has_splits = instruct_string.find( SPLIT_LABEL ) > 0; # Split screens only if requested and split labels are present if ( has_splits ) then if ( split_instrucs ) then # Split at split points array<string> split_instructions[0]; instruct_string.split( SPLIT_LABEL, split_instructions ); # Hold onto the old terminator buttons for later array<int> old_term_buttons[0]; instruct_trial.get_terminator_buttons( old_term_buttons ); array<int> new_term_buttons[0]; new_term_buttons.add( BUTTON_FWD ); # Present each screen in sequence loop int i = 1 until i > split_instructions.count() begin # Remove labels and add screen switching/start experiment instructions # Remove leading whitespace string this_screen = split_instructions[i]; this_screen = this_screen.trim(); this_screen = this_screen.replace( SPLIT_LABEL, "" ); this_screen.append( LINE_BREAK + LINE_BREAK ); # Add the correct button options bool can_go_backward = ( i > 1 ) && ( BUTTON_BWD > 0 ); new_term_buttons.resize( 0 ); new_term_buttons.add( BUTTON_FWD ); if ( can_go_backward ) then new_term_buttons.add( BUTTON_BWD ); this_screen.append( prev_screen + " " ); end; if ( i < split_instructions.count() ) then this_screen.append( next_screen ); else this_screen.append( split_final_screen ); end; instruct_trial.set_terminator_buttons( new_term_buttons ); # Word wrap & present the screen full_size_word_wrap( this_screen, font_size, char_wrap, instruct_text ); instruct_trial.present(); if ( response_manager.last_response_data().button() == BUTTON_BWD ) then if ( i > 1 ) then i = i - 1; end; else i = i + 1; end; end; # Reset terminator buttons instruct_trial.set_terminator_buttons( old_term_buttons ); else # If the caption has splits but multi-screen isn't requested # Remove split labels and present everything on one screen string this_screen = instruct_string.replace( SPLIT_LABEL, "" ); this_screen = this_screen.trim(); this_screen.append( LINE_BREAK + LINE_BREAK + final_screen ); full_size_word_wrap( this_screen, font_size, char_wrap, instruct_text ); instruct_trial.present(); end; else # If no splits and no multi-screen, present the entire caption at once full_size_word_wrap( instruct_string, font_size, char_wrap, instruct_text ); instruct_trial.present(); end; default.present(); end; # --- sub present_instructions --- sub present_instructions( string instruct_string ) begin full_size_word_wrap( instruct_string, font_size, char_wrap, instruct_text ); instruct_trial.present(); default.present(); end; # --- sub block_status --- string block_complete = get_lang_item( lang, "Block Complete Caption" ); sub block_status( int total_blocks, int current_block ) begin if ( current_block < total_blocks ) then string block_temp = block_complete.replace( LANGUAGE_FILE_TOTAL_BLOCKS_LABEL, string(total_blocks) ); block_temp = block_temp.replace( LANGUAGE_FILE_BLOCK_NUMBER_LABEL, string(current_block) ); present_instructions( block_temp ); end; end; # --- sub show_block int num_blocks = parameter_manager.get_int( "Blocks" ); array<int> ISI_durations[0]; parameter_manager.get_ints( "ISI Durations", ISI_durations ); if ( ISI_durations.count() == 0 ) then exit( "Error: 'ISI Durations' must contain at least one value." ); end; array<string> tgt_conds[2]; tgt_conds[COND_TGT_IDX] = COND_TGT; tgt_conds[COND_NTGT_IDX] = COND_NTGT; array<int> buttons[2]; buttons[COND_TGT_IDX] = BUTTON_TGT; buttons[COND_NTGT_IDX] = BUTTON_NTGT; array<int> p_codes[2]; p_codes[COND_TGT_IDX] = PORT_CODE_TGT; p_codes[COND_NTGT_IDX] = PORT_CODE_NTGT; # -- Set up info for summary stats -- # int SUM_BLOCK_IDX = 1; int SUM_COND_IDX = 2; # Put all the condition names into an array # Used later to add column headings array<string> cond_names[2][0]; cond_names[SUM_COND_IDX].assign( tgt_conds ); loop int i = 1 until i > num_blocks begin cond_names[SUM_BLOCK_IDX].add( string(i) ); i = i + 1; end; # Now build an empty array for all DVs of interest array<int> acc_stats[cond_names[1].count()][cond_names[2].count()][0]; array<int> RT_stats[cond_names[1].count()][cond_names[2].count()][0]; # --- End Summary Stats --- # sub double show_block( array<int,1>& block_order, string prac_check, int block_num ) begin # Randomize the trial order block_order.shuffle(); # Start with an ISI trial_refresh_fix( ISI_trial, ISI_durations[random(1,ISI_durations.count())] ); ISI_trial.present(); # Show the trials double block_acc = 0.0; loop int hits = 0; int i = 1 until i > block_order.count() begin int this_stim = block_order[i]; # Set up the picture stim_pic.set_part_x( box_part, stim_locs[this_stim][1] ); stim_pic.set_part_y( box_part, stim_locs[this_stim][2] ); # Set target button stim_event.set_target_button( buttons[this_stim] ); stim_event.set_response_active( true ); # Set ISI trial_refresh_fix( ISI_trial, ISI_durations[random(1,ISI_durations.count())] ); # Set port code stim_event.set_port_code( p_codes[this_stim] ); # Set event code stim_event.set_event_code( STIM_EVENT_CODE + ";" + prac_check + ";" + string( block_num ) + ";" + string( i ) + ";" + tgt_pos + ";" + tgt_conds[this_stim] + ";" + string( ISI_trial.duration() ) ); # Present the trial sequence stim_trial.present(); stimulus_data last = stimulus_manager.last_stimulus_data(); ISI_trial.present(); # Update the block accuracy if ( last.type() == last.HIT ) || ( last.type() == last.OTHER ) then hits = hits + 1; end; block_acc = double( hits ) / double( i ); # Record trial info for summary stats if ( prac_check == PRACTICE_TYPE_MAIN ) then # Make an int array specifying the condition we're in # This tells us which subarray to store the trial info array<int> this_trial[cond_names.count()]; this_trial[SUM_BLOCK_IDX] = block_num; this_trial[SUM_COND_IDX] = this_stim; int this_acc = int( last.type() == last.HIT || last.type() == last.OTHER ); acc_stats[this_trial[1]][this_trial[2]].add( this_acc ); if ( last.reaction_time() > 0 ) then RT_stats[this_trial[1]][this_trial[2]].add( last.reaction_time() ); end; end; i = i + 1; end; return block_acc end; # --- Conditions & Trial Order --- # array<int> cond_array[0][0]; array<int> prac_array[0]; begin # Grab the trial counts array<int> tgt_set[0]; parameter_manager.get_ints( "Targets per Block", tgt_set ); array<int> ntgt_set[0]; parameter_manager.get_ints( "Non-targets per Block", ntgt_set ); # If the trial count arrays aren't the right size, then exit if ( tgt_set.count() != num_blocks ) || ( ntgt_set.count() != num_blocks ) then exit( "Error: 'Targets per Block' and 'Non-targets per Block' must both contain " + string( num_blocks ) + " values." ); end; # Loop through the trial count arrays to build block orders # Add each block order to the cond array loop int i = 1 until i > num_blocks begin # Make a temporary block order and fill it with the correct # number of targets and non-targets array<int> temp_block[tgt_set[i] + ntgt_set[i]]; temp_block.fill( 1, 0, COND_TGT_IDX, 0 ); temp_block.fill( 1, ntgt_set[i], COND_NTGT_IDX, 0 ); # Shuffle the trial order temp_block.shuffle(); # Add this block to the conditiona array cond_array.add( temp_block ); i = i + 1; end; # Shuffle the block order if requested if ( parameter_manager.get_bool( "Randomize Block Order" ) ) then cond_array.shuffle(); end; # Build the practice array int prac_trials = parameter_manager.get_int( "Practice Trials" ); loop until prac_array.count() >= prac_trials begin prac_array.add( cond_array[1][random(1,cond_array[1].count())] ); end; end; # --- Main Sequence --- bool show_block_status = parameter_manager.get_bool( "Show Status Between Blocks" ); int prac_threshold = parameter_manager.get_int( "Minimum Percent Correct to Complete Practice" ); string instructions = get_lang_item( lang, "Instructions" ); instructions = instructions.replace( TARGET_SIDE_LABEL, parameter_manager.get_string( "Target Position Label" ) ); # Practice trials and/or instructions if ( prac_array.count() > 0 ) then main_instructions( instructions + " " + get_lang_item( lang, "Practice Caption" ) ); loop double block_accuracy = -1.0 until block_accuracy >= ( double( prac_threshold ) / 100.0 ) begin block_accuracy = show_block( prac_array, PRACTICE_TYPE_PRACTICE, 0 ); end; present_instructions( get_lang_item( lang, "Practice Complete Caption" ) ); else main_instructions( instructions ); end; # loop to present blocks loop int a = 1 until a > cond_array.count() begin show_block( cond_array[a], PRACTICE_TYPE_MAIN, a ); if ( show_block_status ) then block_status( cond_array.count(), a ); end; a = a + 1; end; present_instructions( get_lang_item( lang, "Completion Screen Caption" ) ); # --- Print Summary Stats --- # string sum_log = logfile.filename(); if ( sum_log.count() > 0 ) then # Open & name the output file string TAB = "\t"; int ext = sum_log.find( ".log" ); sum_log = sum_log.substring( 1, ext - 1 ) + "-Summary-" + date_time( "yyyymmdd-hhnnss" ) + ".txt"; string subj = logfile.subject(); output_file out = new output_file; out.open( sum_log ); # Print the headings for each columns array<string> cond_headings[cond_names.count() + 1]; cond_headings[1] = "Subject ID"; cond_headings[SUM_BLOCK_IDX + 1] = "Block"; cond_headings[SUM_COND_IDX + 1] = "Target Type"; cond_headings.add( "Accuracy" ); cond_headings.add( "Accuracy (SD)" ); cond_headings.add( "Avg RT" ); cond_headings.add( "Avg RT (SD)" ); cond_headings.add( "Median RT" ); cond_headings.add( "Number of Trials" ); cond_headings.add( "Date/Time" ); loop int i = 1 until i > cond_headings.count() begin out.print( cond_headings[i] + TAB ); i = i + 1; end; # Loop through the DV arrays to print each condition in its own row # Following the headings set up above loop int i = 1 until i > acc_stats.count() begin loop int j = 1 until j > acc_stats[i].count() begin out.print( "\n" + subj + TAB ); out.print( cond_names[1][i] + TAB ); out.print( cond_names[2][j] + TAB ); out.print( round( arithmetic_mean( acc_stats[i][j] ), 3 ) ); out.print( TAB ); out.print( round( sample_std_dev( acc_stats[i][j] ), 3 ) ); out.print( TAB ); out.print( round( arithmetic_mean( RT_stats[i][j] ), 3 ) ); out.print( TAB ); out.print( round( sample_std_dev( RT_stats[i][j] ), 3 ) ); out.print( TAB ); out.print( round( median_value( RT_stats[i][j] ), 3 ) ); out.print( TAB ); out.print( acc_stats[i][j].count() ); out.print( TAB ); out.print( date_time() ); j = j + 1; end; i = i + 1; end; # Close the file and exit out.close(); end;
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[[i= partials/header ]] <pre> ✅ Add a student to the DB 🔄 Record attendance (present in backend - UI not designed) 🔄 Record activity completed (present in backend - UI not designed) ✅ Search for students ✅ By Name ⬛ By Student number ⬛ By Age ⬛ By Activities Completed ⬛ By Activities Not Completed ⬛ Notify staff when a student completes a badge (NO) ⬛ Search for Activities that are widely NOT completed ⬛ Edit details for stuff ⬛ Student ⬛ Attendance ⬛ Activity ⬛ more? ⬛ Activity Planner ⬛ Staff Running Activity ⬛ more? </pre> [[i= partials/footer ]]
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y = imread("M:\Documents\c++\tds\signal_s1\ldussouc_tdimage/koala.jpg") y_mono = y(:,:, 1) function ret = moyenneur(img) ret = img for i = [2:1:299] for j = [2:1:299] moyenne = img(i,j) /9 + img(i+1,j) /9 + img(i-1,j) /9 + img(i,j+1) /9 + img(i,j-1) /9 + img(i-1,j-1) /9 + img(i+1,j+1) /9 + img(i-1,j+1) /9 + img(i+1,j-1) /9 ret(i,j) = floor(moyenne) end end endfunction function ret = derivateurH(img) ret = img for i = [2:1:299] for j = [2:1:299] ret(i,j) = abs(img(i-1,j) - img(i+1,j)) end end endfunction function ret = median(img) ret = img for i = [2:1:299] for j = [2:1:299] tableau = [img(i,j), img(i+1,j), img(i-1,j), img(i,j+1), img(i,j-1), img(i-1,j-1), img(i+1,j+1), img(i-1,j+1), img(i+1,j-1)] tableau_trie = gsort(tableau,'g','i') ret(i,j) = tableau_trie(5) end end endfunction y_mono_moyenneur = moyenneur(y_mono) y_mono_derivateurH = derivateurH(y_mono) y_mono_median = median(y_mono) imshow(y_mono_median)
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clc T1_ = 80 // Initial temperature of air in degree Celsius T2_ = 5 // Final temperature of air in degree Celsius V2 = 2 // Assumed final volume V1 = 1 // Assumed initial volume P0 = 100 // Final pressure of air in kPa P1 = 500 // Initial pressure of air in kPa R = 0.287 // Gas constant cv = 0.718 // Specific heat capacity at constant volume for gas in kJ/kg K m = 2 // Mass of gas in kg printf("\n Example 8.6") T1= T1_+273 // Initial temperature of air in K T2 = T2_+273 // Final temperature of air in K S = integrate('(m*cv)/T','T',T1,T2) + integrate('(m*R)/V','V',V1,V2) // Entropy change U = m*cv*(T1-T2)// Change in internal energy Wmax = U-(T2*(-S)) // Maximum possible work V1_ = (m*R*T1)/P1 // volume calculation CA = Wmax-P0*(V1_) // Change in availability I = T2*S // Irreversibility printf("\n The maximum work is %f kJ",Wmax) printf("\n Change in availability is %f kJ",CA) printf("\n Irreversibility is %f kJ",I) //The answers vary due to round off error
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// Scilab Code Ex1.4 : Page-17 (2006) clc; clear; c_by_a_ratio = 1.633; // Ideal c/a ratio A = cell(2,4); // Declare a cell // Assign values to the elements of the cell from the table A(1,1).entries = 'Mg'; A(2,1).entries = 'Cd'; A(1,2).entries = 5.21; A(2,2).entries = 5.62; A(1,3).entries = 3.21; A(2,3).entries = 2.98; A(1,4).entries = A(1,2).entries/A(1,3).entries; A(2,4).entries = A(2,2).entries/A(2,3).entries; if (A(1,4).entries - c_by_a_ratio) < 0.01 then printf("\n%s satisfies ideal c/a ratio and %s has large deviation from this value.", A(1,1).entries, A(2,1).entries); else if (A(1,4).entries - c_by_a_ratio) < 0.01 then printf("\n%s satisfies ideal c/a ratio and %s has large deviation from this value.", A(2,1).entries, A(1,1).entries); end end // Result // Mg satisfies ideal c/a ratio and Cd has large deviation from this value.
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function mdaq_hs_ai_init(link_id) if link_id < 0 then disp("Wrong link ID!") return; end result = call("sci_mlink_hs_ai_init",.. link_id, 1, "i",.. "out",.. [1, 1], 2, "i"); if result < 0 then mdaq_error(result) end endfunction
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clc // from figure 2.75 (a) r1 = 30 // radius in mm t = 10 // thickness in mm h1 = 300 // height in mm ir1 = r1-t // inner radius of bends in mm L1 = h1-(ir1+t) // mm alpha1 = 90 // degree r2 = 2*t // mm k = 0.33*t // mm L2 = alpha1*2*%pi*(r2+k)/360 // mm w = 200 // mm L3 = w-2*(t+ir1)// mm L4 = L2 //mm h2 = 100 // mm L5 = h2 -(t+ir1) // mm r3 = 150 //mm ir2 = r3 - t // inner radius in mm alpha2 = 180 // degree L6 = alpha2*2*%pi*(ir2+k)/360 // mm dl = L1+L2+L3+L4+L5+L6 // Total developed length in mm printf("\n Total developed length = %0.2f mm" , dl) // Answers vary due to round off error
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//To Calculate the Capacitance of a parallel plate capacitor //Example 31.3 clear; clc; a=20*10^-2;//Length of Side of Parallel Plate Capacitor A=a^2;//Area of the Capacitor Plate d=1*10^-3;//Separation between the two plates e0=8.85*10^-12;//Permitivity in farad/meter C=e0*A/d;//Formula for finding capacitance of parallel plate capacitor printf("capacitance of the parallel plate capacitor=%f pF",C*10^12);
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// Example 17_5 clc;funcprot(0); //Given data T_s=56;// Temperature of steam entering the condenser in °C T_a=46;// Temperature at the air pump suction in °C P_b=76;// The barometer reading in cm of Hg Q=90;// The discharge of dry air pump in m^3/min R=287;// J/kg.k //Calculation //(a) //From steam tables,at saturation temperature of 56°C p_s=0.1684;//Pressure of steam in bar p_s=p_s/0.01359// cm of Hg p_a=0;// Partial pressureair at the inlet of condenser in cm of Hg p_t=p_s+p_a; p_v=P_b-p_t;//Vacuum in the condenser in cm of Hg //(b) //From steam tables,at saturation temperature of 46°C p_s1=0.1028;// bar v_s=14.56;// m^3/kg p_a1=(p_t*0.01359)-p_s1;// bar m_a=(p_a1*10^5*Q*60)/(R*(T_a+273));//The air leakage in the condenser per hour in kg/hr //(c) Ls=(Q*60)/v_s;// Loss of condensate in kg/hr printf('\n(a)The vacuum in the condenser=%0.1f cm of Hg \n(b)The air leakage in the condenser=%0.1f kg/hr \n(c)Loss of condensate=%0.0f kg/hr',p_v,m_a,Ls); // The answer vary due to round off error
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function ns=concomp(i,g) [lhs,rhs]=argn(0), if rhs==1 then g=the_g, end [l,nc]=connex(g) ns=concom(i,nc,g)
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clear; clc; // Stoichiometry // Chapter 6 // Stoichiometry and Unit Operations // Example 6.15 // Page 385 printf("Example 6.15, Page 385 \n \n"); // solution //basis 1kg of dry air entering the air washer //from fig 6.15 H1 = 11.8 //g/kg dry air H2 = 17.76 //g/kg dry air H = H2-H1 // moisture added during saturation DB = 300.95 //K WB = 298.15 //K DP = 297.15 //K Ch = 1.006+1.84*.01776 //kJ/kg dry air K dT = DB-DP Hs = Ch*3.8 A = 25000 //m^3/h actual air at 41 and 24 degree celcius // again from fig 6.15 Vh = .9067 //m^3/kg dry air qm = A/Vh //kg dry air/h fi = qm*Hs //kJ/h P = 300 //kPa lamda= 2163.2 //kJ/kg by appendix IV.2 SC = fi/lamda //kg/h steam consumption at the heater printf(" the moisture added to the air = "+string(H)+" g/kg dry air \n DB temp of final air = "+string(DB)+"K \n WB temp of final air = "+string(WB)+"K \n The heating load of the steam coil per kg dry air = "+string(fi)+" kJ/h \n Steam consumption = "+string(SC)+" kg/h.")
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//exmaple 2.6 clc disp("The circuit is Wien bridge oscillator using op-amp. The gain of the op-amp is") a=1+3 disp(a,"A = 1 + R3/R4 =") disp("So A > 3") disp("This satisfies the required oscillating condition. The feedback is given to non-inverting terminal ensuring the zero phase shift. Hence the circuit will work as the oscillator.") f=1/(2*%pi*5.1*0.001) format(8) disp(f,"f(in kHz) = 1 / 2*pi*R*C =") disp("This will be the frequency of oscillations")
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// Scilab code Exa2.2.2 To calculate the difference in coulomb energy and nucleons' mass difference for mirror nuclei and show in agreement with actual mass difference Page 67 (2011) // Calculation of coulomb energy for mirror nuclei : N-7 and O-8 // For N-7 nucleus a_c = 0.7; // Coulomb energy constant, MeV Z_N = 7; // Atpmic no. A = 15; // Atomic mass E_C_N = a_c*Z_N*(Z_N-1)/(A^(1/3)); // Coulomb energy for N-7, MeV // For O-8 nucleus a_c = 0.7; // Coulomb energy constant, MeV Z_O = 8; // Atpmic no. A = 15; // Atomic mass E_C_O = a_c*Z_O*(Z_O-1)/(A^(1/3)); // Coulomb energy for O-8, MeV C_E_d = E_C_O-E_C_N; // Coulomb energy difference, MeV m_p = 1.007276*931.49; // Mass of proton, MeV m_n = 1.008665*931.49; // Mass of neutron, MeV M_d = m_n-m_p; // Mass difference of nucleons, MeV D_C_M = round(C_E_d-M_d); // Difference in coulomb energy and nucleon mass difference, MeV M_O = 15.003070*931.49; // Mass of O-8, MeV M_N = 15.000108*931.49; // Mass of N-7, MeV D_A = round(M_O-M_N); // Actual mass difference, MeV printf("\nDifference in Coulomb energy = %5.3f MeV\nNucleon mass difference = %6.4f MeV\nDifference in Coulomb energy and nucleon mass difference = %5.3f MeV\nActual mass difference = %5.3f MeV",C_E_d, M_d ,D_C_M, D_A); if D_A == D_C_M then printf("\nResult is verified") end // Result // Difference in Coulomb energy = 3.974 MeV // Nucleon mass difference = 1.2938 MeV // Difference in Coulomb energy and nucleon mass difference = 3.000 MeV // Actual mass difference = 3.000 MeV // Result is verified
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12_03.sce
//mass and area// pathname=get_absolute_file_path('12.03.sce') filename=pathname+filesep()+'12.03-data.sci' exec(filename) //Saturation pressure(in psia): p0=p1*(1+(k-1)/2*M1^2)^(k/(k-1)) //Checking for choking: x=pb/p0; if(x>0.528) //Not choked else //choked end //As there is choking: Mt=1; //Velocity at entry: V1=M1*sqrt(k*R*(T1+460)*32.2) //Density at the entry(in lbm/ft^3): d1=p1/(R*(T1+460))*144 //Mass flow rate(in lbm/sec): m=d1*V1*A1 //Finding the valueof A1/A*; A=1/M1*((1+(k-1)/2*M1^2)/(1+(k-1)/2))^((k+1)/(2*(k-1))) //For choked flow, At=A* At=A1/A printf("\n\nRESULTS\n\n") printf("\n\nMach number at throat: %.3f\n\n",Mt) printf("\n\nMass flow rate: %.3f lbm/sec\n\n",m) printf("\n\nArea at throat: %.3f ft^2\n\n",At)
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Exa4.sce
//Exa4 clc; clear; close; //given data : Vo=500;//in Rs r=16;//in % per annum i=r/100; n=5;//in years //interest is calculated in quarterly basis m=4; //formula Vn=Vo*(1+i/m)^(m*n) Vn=Vo*(1+i/m)^(m*n) disp(Vn," The amount will be(in Rs.) : ") //Note: answer given in the book is not accurate
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Ch01Ex10.sce
// Scilab Code Ex1.10: Page-1.8 (2009) clc; clear; m = 1.67e-027; // Mass of the proton, kg c = 3e+08; // Speed of light, m/s v = 1/20*c; // Velocity of the proton, m/s h = 6.626e-034; // Planck's constant, Js lambda = h/(m*v); // de Broglie wavelength of the neutron, m printf("\nThe de Broglie wavelength associated with moving proton = %5.3e m", lambda); // Result // The de Broglie wavelength associated with moving proton = 2.645e-14 m
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Ex6_6.sce
// Exa 6.6 // To calculate capacity and spectral efficiency of the DS-CDMA system. clc; clear all; nb=0.9;//bandwidth efficiency nf=0.45;//frequency reuse efficiency Cd=0.8; //capacity degradation factor Vf=0.4;//voice activity factor Eb_I0=7; // desired energy-to-interference ratio in dB L=1;// efficiency of sector-antenna in cell BW=12.5;//One way system BW in MHz R=16.2;//Information rate in kbps //solution Eb_I=10^(Eb_I0*0.1);//To convert from dB to a normal value Nu=(nf*nb*Cd*L/Vf)*(BW*1000/(Eb_I*R));//Capacity of system Seff=round(Nu)*R/(12.5*10^3); printf('Capacity of system is %d mobile users per cell\n ',round(Nu)); printf('Spectral efficiency of TDMA system is %.3f bits/sec/Hz\n',Seff); disp("In these calculations, an omnidirectional antenna is assumed. If a three sector antenna (i.e., G=3) is used at a cell site with lamda(efficiency of sector-antenna in a cell)= 2.6, the capacity will be increased to 325 mobile users per cell, and spectral efficiency will be 0.421 bits/sec/Hz.")
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s=poly(0,"s") //roll no. = 18d070046, esha G1 = 46/(s+5) sys1 = syslin("c",G1) disp(G1) //q1b t = 0:0.01:5 y = csim("step",t,sys1) z = 9.016 plot2d(t,y) xlabel("t") ylabel("y") title("Step Response") xpts = [0 5]; ypts = [9.016 9.016]; plot(xpts, ypts); xpts = [0.2 0.2]; ypts = [0 10]; plot(xpts, ypts); //q1c s=poly(0,"s") for a=46:46:4600 G1 = a/(s+5) sys1 = syslin("c",G1); t=0:0.01:5; y = csim('step',t,sys1); plot2d(t,y) end xlabel("t") ylabel("y") title("Step Responses") //q1d s=poly(0,"s") for b=5:5:500 G1 = 46/(s+b) sys1 = syslin("c",G1); t=0:0.01:5; y = csim('step',t,sys1); plot2d(t,y) end xlabel("t") ylabel("y") title("Step Responses")
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3_17.sce
//Network Theorem 2 //pg no 3.18 //example 3.17 disp("removing the 3 Ohm resistor from the network"); disp("Applying KVL to mesh 1"); disp("11*I1-9*I2=50");....//equation 1 disp("Applying KVL to mesh 2"); disp("-9*I1+18*I2=0");....//equation 2 A=[11 -9;-9 18];//solving the equations in matrix form B=[50 0]' X=inv(A)*B; disp(X); disp("I1=7.69 A"); disp("I2=3.85 A"); //Calculation of Vth (Thevenin's voltage) a=7.69; b=3.85; v=-((5*b)+(8*(b-a)));//the B terminal is positive w.r.t A printf("\nWriting Vth equation, \n Vth = %.1f V",v); //Calculation of Rth (Thevenin's resistance) x=4; y=2; z=5; //delta into star network r1=((x*y)/(x+y+z)); r2=((x*z)/(x+y+z)); r3=((z*y)/(x+y+z)); mprintf("\nR1 = %.2f Ohm \nR2 = %.2f Ohm \nR3 = %.2f Ohm",r1,r2,r3); m=1.73; n=8.91; r=(r2+(m*n)/(m+n)); printf("\nRth = %.2f Ohm",r); //Claculation of IL (Load Current) i=v/(r+3); printf("\nIL = %.2f A",i);
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example4_3.sce
clear; clc; //Example4.3[Boiling Eggs] //Given:- T1=5;//Initial temperature of egg[degree Celcius] T2=95;//Temperature of Boiling Water[degree Celcius] h=1200;//Convection heat transfer coefficient of egg[W/m^2.degree Celcius] r=0.025;//Radius of egg[m] T3=70;//Final temperature attained by centre of egg[degree Celcius] k=0.627;//Thermal conductivity[W/m.degree Celcius] a=0.151*(10^(-6));//Thermal diffusivity[m^2/s] //Solution:- Bi=(h*r)/k;//Biot Number if(Bi>0.1) then, disp("the lumped system analysis is not applicable") //Findinf coefficient for a sphere corresponding to this bi are, lambda1=3.0754,A1=1.9959; x=(T3-T2)/(T1-T2); tau=(-1/(lambda1^2))*log(x/A1); disp(tau,"Fourier no is") //Since fourier no is greater than 0.2, cooking time is determined from the definition of fourier no to be t=(tau*(r^2))/a;//[seconds] disp("minutes",(t/60),"The time taken for center of egg to reach 70 degree Celcius temperature") else, disp("the lumped system is not applicable") end
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6_17.sce
////Variable Declaration T = 298.15 //Std. Temperature, K P = 1.0 //Initial Pressure, bar [Hm0,Sm0] = (0.0,154.8) [Sm0H2,Sm0O2] = (130.7,205.2) dGfH2O = -237.1 //Gibbs energy of formation for H2O(l), kJ/mol [nH2,nO2] = (1,1/2) //Calculations Gm0 = Hm0 - T*Sm0 dGmH2O = dGfH2O*1000 - T*(nH2*Sm0H2 + nO2*Sm0O2) //Results printf("\n Molar Gibbs energy of Ar %4.3f kJ/mol",Gm0/1e3) printf("\n Molar Gibbs energy of Water %4.3f kJ/mol",dGmH2O/1e3)
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5_6data.sci
r=1000;//in mm M0=1000;//in N.mm
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ex2_4.sce
function y=f(t),y=20*sin(t),endfunction //defining the voltage function T=2*%pi; Res=intg(0,%pi,f)/(T); disp("Volts",Res,"Average voltage value");
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Ex2_22.sce
//Example 2_22 clc(); clear; //To calculate slit width lemda=6000 //units in angstrom x=4.2 //units in millimeters x=4.2*10^-3 //units in meters D=60 //units in centimeters D=60*10^-3 //units in meters d=((D*lemda)/x)*10^-9 printf("The Slit width of the screen is %f",d)
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18_16.sce
//ques-18.16 //Calculating increase in entropy clc v1=2.8;//volume of O2 (in L) v2=19.6;//volume of H2 (in L) n1=v1/22.4; n2=v2/22.4;//(in moles) x1=n1/(n1+n2); x2=n2/(n1+n2); S=-8.314*2.303*(x1*log10(x1)+x2*log10(x2)); printf("The increase in entropy is %.3f J/K.",S);
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Ch02Ex61.sce
// Scilab Code Ex2.61:: Page-2.48(2009) clc; clear; R1 = 200; // Radius of curvature of the convex surface, cm R2 = 250; // Radius of curvature of the concave surface, cm lambda = 5500e-008; // Wavelength of light used, cm n = 15; // Order of interfernce Newton ring // As r_n^2*(1/R1-1/R2) = (2*n-1)*lambda/2, solving for r_n r_n = sqrt((2*n-1)*lambda/(2*(1/R1-1/R2))); // Radius of nth ring, cm D_15 = 2*r_n; // Daimeter of 15th bright ring, cm printf("\nThe daimeter of 15th bright ring = %4.2f cm", D_15); // Result // The daimeter of 15th bright ring = 1.79 cm
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load.man.tst
clear;lines(0); a=eye(2,2);b=ones(a); save('vals.dat',a,b); clear a clear b load('vals.dat','a','b');
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FIR_INTERPOLATION_5.sce
//Graphical// //Example 10.5.2 //Interpolation by 5, Filter Length = 30 //Cutoff Frequency Wc = %pi/5 //Pass band Edge frequency fp = 0.1 and a Stop band edge frequency fs = 0.16 // Choose the number of cosine functions and create a dense grid // in [0,0.1) and [0.16,0.5) //magnitude for pass band = 1 & stop band = 0 (i.e) [1 0] //Weighting function =[3 1] clear; clc; close; M = 30; //Filter Length I = 5; //Interpolation Factor = 5 Wc = %pi/5; //Cutoff Frequency Wp = Wc/(2*%pi); //Passband Edge Frequency Ws = 0.16; //Stopband Edge Frequency hn=eqfir(M,[0 Wp;Ws .5],[1 0],[3 1]); [hm,fr]=frmag(hn,256); disp('The LPF Filter Coefficients are:') hn //Obtaining Polyphase Filter Coefficients from hn p = zeros(I,M/I); for k = 1:I for n = 1:(length(hn)/I) p(k,n) = hn(I*(n-1)+k); end end disp('The Polyphase Interpolator for I =5 are:') p figure plot(fr,hm) xlabel('Normalized Digital Frequency fr'); ylabel('Magnitude'); title('Frequency Response of FIR LPF using REMEZ algorithm M=61') figure plot(.5*(0:255)/256,20*log10(frmag(hn,256))); xlabel('Normalized Digital Frequency fr'); ylabel('Magnitude in dB'); title('Frequency Response of INTERPOLATOR(I=5) using REMEZ algorithm M=30')
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//Example 3.1 clc clear A = [2 3 -1; 4 4 -3; -2 3 -1]; //Coefficient Matrix B = [5; 3; 1]; //Constant Matrix n = length(B); Aug = [A,B]; // Forward Elimination for j = 1:n-1 for i = j+1:n Aug(i,j:n+1) = Aug(i,j:n+1) - Aug(i,j) / Aug(j,j) * Aug(j,j:n+1); end end // Backward Substitution x = zeros(n,1); x(n) = Aug(n,n+1) / Aug(n,n); for i = n-1:-1:1 x(i) = (Aug(i,n+1)-Aug(i,i+1:n)*x(i+1:n))/Aug(i,i); end disp(strcat(["x = ",string(x(1))])) disp(strcat(["y = ",string(x(2))])) disp(strcat(["z = ",string(x(3))]))
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test16.tst
type t = array 100 of array 100 of array 100 of int; main() {}
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V=400 w=2*50*%pi P=25000 pf1=0.7 theta1=acos(pf1) Il1=P/(sqrt(3)*V*pf1)*exp(-%i*theta1) Ip1=Il1/sqrt(3) pf2=0.85 theta2=acos(pf2) Il2=P/(sqrt(3)*V*pf2)*exp(-%i*theta2) Ip2=Il2/sqrt(3) Ic=Ip2-Ip1 ////calculation mistake in the book at this step C=real(Ic/(V*w*%i)) disp(C)
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//By Manas,FOSSEE,IITB hz=iir(3,'bp','ellip',[.15 .25],[.08 .03]); [hzm,fr]=frmag(hz,256); plot2d(fr',hzm') xtitle('Discrete IIR filter band pass); q=poly(0,'q'); //to express the result in terms of the delay operator q=z^-1 hzd=horner(hz,1/q)
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clc disp("the solution of eg 5.3 -->Discretization in 1-D space"); //given the source term f(x)=4x^2-2x-4 //given eqn d2y/dx2-2y=f(x) y_1=0 y_4=-1 delta_x=1/3 //since given 3 parts and length=1 for i=0:3,j=0:delta_x:1; end //given to divide the line in 3 parts //at node 2 //y_3-2*y_2 function d=fx3(x), d=(4*x^2-2*x-4) endfunction f2=fx3(j(2)) f3=fx3(j(3)) y_3=((f2)*delta_x^2+(2+2*delta_x^2)*((f3)*delta_x^2-y_4)-y_1)/(1-(2+2*delta_x^2)^2) y_2=(f3+2*y_3)*delta_x^2+2*y_3-y_4 disp(y_3,y_2,"is respectively",j(3),j(2),"the value of y at x=");
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tempcostrevenue.sce
tempcost= read("tempCostRevenue.txt",-1,2); time = tempcost(:,$-1); tempcost= tempcost(:,$); plot2d(time,tempcost);
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local scene = {} local cfg = require("frontend/config") function scene:onLoad() local color_bg, color1, color2 = cfg.bgColor, cfg.color1, cfg.color2 love.graphics.setBackgroundColor(unpack(color_bg)) local sw,sh = love.window.getDimensions() local layer = cine.layer.new() local sprite = cine.sprite.new(sw/2,-265,cine.sourceImage.new("frontend/lovelogo.png")) --sprite:setTint(unpack(color1)) sprite:center("middle","bottom") local iD = love.image.newImageData(3,3) iD:setPixel(1,1,0,0,0,255) local shadow = cine.sprite.new(sw/2,sh/2-15,cine.sourceImage.new(iD)) local sfx = love.audio.newSource("frontend/sounds/fadein.wav", "static") sfx:play() shadow:setSca(256/10,64/10) shadow:setTint(255,255,255,0) shadow:center() layer:insertSprite(shadow) layer:insertSprite(sprite) shadow:moveScaTo(256/2,64/2,1) shadow:moveTintTo(255,255,255,128,1) sprite:setTweenStyle("easein") sprite:moveScaTo(0.8,1.2,0.4) cine.thread.waitThread(sprite:movePosTo(sw/2,sh/2,1)) cine.thread.waitThread(sprite:moveScaTo(1.2,0.8,0.1)) shadow:moveScaTo(256/2.5,64/2.5,0.25) shadow:moveTintTo(255,255,255,100,0.25) sprite:setTweenStyle("easeout") sprite:moveScaTo(0.8,1.2,0.25) cine.thread.waitThread(sprite:movePos(0,-100,0.25)) shadow:moveScaTo(256/2,64/2,0.15) shadow:moveTintTo(255,255,255,128,0.15) sprite:setTweenStyle("easein") cine.thread.waitThread(sprite:movePosTo(sw/2,sh/2,0.15)) cine.thread.waitThread(sprite:moveScaTo(1,1,0.1)) local sfx2 = love.audio.newSource("frontend/sounds/logo.wav", "static") cine.thread.wait(1) --rolling sprite:center() sprite:movePos(0,-128) sprite:setTweenStyle("easeout") shadow:setTweenStyle("easeout") sprite:movePos(60,0,1) local r,g,b = unpack(color2) shadow:movePos(60,0,1) sprite:moveRot(math.rad(30),1) local r,g,b = unpack(color1) sprite:moveTintTo(r,g,b,255,0.5) local sFont4 = cfg.font[5] local sRetro = cine.sprite.new(sw/2-50,sh/2,sFont4,"retrr ") sRetro:setTweenStyle("easeinout") sRetro:center("right","top") sRetro:setIndex("retro") local r,g,b = unpack(color1) sRetro:setTint(r,g,b,0) local sLove = cine.sprite.new(sw/2+50,sh/2,sFont4,"löve") sRetro:setTweenStyle("easeinout") local r,g,b = unpack(color2) sLove:setTint(r,g,b,0) layer:insertSprite(sRetro) layer:insertSprite(sLove) sfx2:play() sRetro:moveTint(0,0,0,255,1) sRetro:movePos(50,0,1) cine.thread.wait(1) sprite:movePos(-60,0,1) local r,g,b = unpack(color2) shadow:movePos(-60,0,1) sprite:moveRot(math.rad(-30),1) local r,g,b = unpack(color2) sprite:moveTintTo(r,g,b,255,1) sLove:moveTint(0,0,0,255,1) sLove:movePos(-50,0,1) cine.thread.wait(2.5) local sprite = cine.sprite.new(0,0,cine.sourceRectangle.new(),{sw,sh}) sprite:setTint(255,255,255,0) layer:insertSprite(sprite) sprite:moveTintTo(255,255,255,255,1) cine.thread.wait(1) cine.layer.remove(layer) cine.thread.wait(0.25) self:stop() --initialize your scene here end function scene:onUpdate() --update your scene here. end function scene:onStop() --define what is going to happen when your scene stops end return scene
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11ex4.sci
disp('Divisibility and Primes') x=50; disp('prime numbers less than 50 are') y=primes(x) disp('the prime factorisation of 21,24 and 1729 respectively are:') k=factor(21) l=factor(24) n=factor(1729)
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//Example No. 7.10.1 clc; clear; close; format('v',6); A=1;//m²(Area of loop) N=400;//no. of turns Q=100;//Quality factor theta=60;//degree(angle) Erms=10;//µV/m(field strength) f=1;//MHz(tuned frequency) c=3*10^8;//m/s////Speed of light lambda=c/(f*10^6);//m(Wavelength) Vr=Q*2*%pi*A*N*cosd(theta)*Erms*10^-6/lambda;//V(reciever input voltage) disp(Vr*1000,"Input voltage to the receiver in mV : ");
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//example10.3 //calculate factor of safety for slope clc;funcprot(0); //given x=4; //given scale An=14.4; //area of N rectangle At=6.4; //area of T rectangle Au=4.9; //area of U rectangle L=12.6; //length of arc; gamma_m=19; //unit weigth of soil gamma_w=9.81; //unit weigth of water fi=26; //effective angle(degree) co=19.5; //cohesion value //consider 1m length of dam SumN=An*x^2*gamma_m; SumT=At*x^2*gamma_m; SumU=Au*x^2*gamma_w; Le=x*L; F=((Le*co)+(SumN-SumU)*tand(fi))/SumT; F=round(F*100)/100; mprintf("Factor of safety for slope=%f.",F);
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// Example no 2.8 // To find the total loss and output power in mW and dBm in fiber // Page no. 72 clc; clear; // Given data losscoe=0.046; // Loss coefficient in km^-1 L=80; // Length of fiber in km PindBm=3; // Input power in dBm // To find total loss of fiber loss=round(4.343*losscoe*L); // Total loss in fiber // Displaying the result in command window printf('\n Total loss in fiber = %0.0f dB',loss); // To find output power PoutdBm=PindBm-loss; // Output power in dBm PoutmW=10^(PoutdBm/10); // Output power in mW //Displaying the result in command window printf('\n Output power of fiber = %0.0f dBm',PoutdBm); printf('\n Output power of fiber = %0.2f mW',PoutmW);
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2023-05-31T04:06:22.931111
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function scs_m=do_color(scs_m) // do_block - edit a block icon // Copyright INRIA while %t [btn,xc,yc,win,Cmenu]=getclick() if Cmenu<>[] then Cmenu=resume(Cmenu) end K=getobj(scs_m,[xc;yc]) if K<>[] then break,end end o=scs_m(K) if o(1)=='Link' then [nam,pos,ct]=o(5:7) c=getcolor('Choose a color',ct(1)); if c<>[] then connected=connected_links(scs_m,K) for kc=connected o=scs_m(kc);ct=o(7) if ct(1)<>c then drawobj(o) o(7)(1)=c; drawobj(o) scs_m(kc)=o end end end elseif o(1)=='Block' then graphics=o(2) gr_i=graphics(9) if type(gr_i)==10 then,gr_i=list(gr_i,[]),end if gr_i(2)==[] then coli=0 else coli=gr_i(2) end coln=getcolor('color',coli) if coln<>[] then if coln<>coli then gr_i(2)=coln graphics(9)=gr_i drawblock(o) o(2)=graphics scs_m(K)=o drawblock(o) end end elseif o(1)=='Text' then //not implemented end
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ex12.sce
clc clear //Input data Z=70;//Vaccum gauge reading in cm of Hg Pa=101.325;//Atmospheric pressure in kPa d=13.6*10^3;//Density of Hg in kg/m^3 g=9.81;//Gravity in m/sec^2 //Calculations Pv=(d*g*Z)/10^5;//Vaccum pressure in kPa Pab=Pa-Pv;//Absolute pressure in kPa //Output printf('Absolute pressure Pab = %3.4f kPa ',Pab)
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EliminacaoGaussiana.sci
function u=EliminacaoGaussiana(a) [l,c]=size(a) u=[a] np=1 //numero do pivo disp(a) for n=1:c // numero da coluna a ser escalonada if np==l+1 then // numero do pivo e menor ou igual ao numero de linhas break end // if u(np,n)==0 then for i=np+1:l // se a primeira entrada for zero, entao procure entradas não nulas if u(i,n)~=0 then disp("L"+string(i)+" <=> L"+string(np)) for j=n:c // permutar a linha da primeira entrada com uma linha de entrada nao nula aux=u(i,j) u(i,j)=u(np,j); u(np,j)=aux; end disp(u) break end end end if u(np,n)~=0 then //se a linha possui entrada nao nula, entao escalonar if u(np,n)~=1 then k=u(np,n) u(np,n)=1 disp("(1/"+string(k)+")L"+string(np)+" => L"+string(np)) for j=n+1:c // deixar o pivo igual a 1 e dividir as demais entradas u(np,j)=u(np,j)/k end disp(u) end for i=np+1:l if u(i,n)~=0 then disp("L"+string(i)+"+("+string(-u(i,n))+")L"+string(np)+ " => L"+string(i)) u(i,:)=u(i,:)-u(i,n)*u(np,:) // zerar as entradas abaixo do pivo disp(u) end end b(np)=n np=np+1 end // end //m = np-1 //for n=2:m //for i=1:m-n+1 // disp("L"+string(i)+"+("+string(-u(i,b(m-n+2)))+")L"+string(n)+ " => L"+string(i)) // u(i,:)=u(i,:)-u(i,b(m-n+2))*u(m-n+2,:) // zerar as entradas acima do pivo // disp(u) //end //end endfunction
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//chapter 4 //example 4.7 //page 112 clear all; clc ; //given Vcc=15;//supply voltage Vce=5;//collector to emitter voltage Ic=5;//mA hfe=100;Vbe=0.7; //drop across RE & RC Vrc=Vcc-Vce; VRC=Vrc/2; Ve=VRC; Rc=VRC/Ic; printf("\nRc=%d kohm,standard value 1 kohm",Rc); Ie=Ic; Re=Ve/Ic; printf("\nRe=%d kohm,standard value 1 kohm",Re); Vb=Ve+Vbe; I2=Ic/10; R2=Vb/I2; printf("\nR2=%.1f kohm,standard value 12 kohm",R2); R1=(Vcc-Vb)/I2; printf("\nR1=%.1f kohm,standard value 18 kohm",R1);
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clear;lines(0); A=diag([3,-3,7,4,-4,8]); B=[eye(3,3);zeros(3,3)]; C=[0,0,1,2,3,4;0,0,0,0,0,1]; D=[1,2,3;0,0,0]; rand('seed',0);w=ss2ss(syslin('c',A,B,C,D),rand(6,6)); [A,B,C,D]=abcd(w); B=[B,matrix(1:18,6,3)];D=[D,matrix(-(1:6),2,3)]; reject=1:3; Sys=syslin('c',A,B,C,D); N1=[-2,-3];C1=-N1*C;D1=-N1*D; nw=length(reject);nu=size(Sys('B'),2)-nw; ny=size(Sys('C'),1);nz=size(C1,1); [UIobs,J,N]=ui_observer(Sys,reject,C1,D1); W=[zeros(nu,nw),eye(nu,nu);Sys];UIobsW=UIobs*W; //(w,u) --> z=UIobs*[0,I;Sys](w,u) clean(ss2tf(UIobsW)); wu_to_z=syslin('c',A,B,C1,D1);clean(ss2tf(wu_to_z)); clean(ss2tf(wu_to_z)-ss2tf(UIobsW),1.d-7) /////2nd example////// nx=2;ny=3;nwu=2;Sys=ssrand(ny,nwu,nx); C1=rand(1,nx);D1=[0,1]; UIobs=ui_observer(Sys,1,C1,D1);
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// Example 9.2 // Calculation of the total power at the fiber output. // Page no 393 clc; clear; close; //Given data p=0; // Power per channel fl=0.2; // Fiber loss f=50; // Wavelength // The total power at the fiber output. pc=10^(0.1*p); tp=pc*11; tp1=10*log10(tp); tfl=fl*f; to=tp1-tfl; //Displaying results in the command window printf("\n The total power at the fiber output = %0.3f dBm ",to);
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function OneDIndx = Convert2DIndexTo1D(rowNum, colNum, numberOfCols) OneDIndx = rowNum * numberOfCols + colNum; endfunction
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-- Fuzzy Logix, LLC: Functional Testing Script for DB Lytix functions on Netezza -- -- Copyright (c): 2014 Fuzzy Logix, LLC -- -- NOTICE: All information contained herein is, and remains the property of Fuzzy Logix, LLC. -- The intellectual and technical concepts contained herein are proprietary to Fuzzy Logix, LLC. -- and may be covered by U.S. and Foreign Patents, patents in process, and are protected by trade -- secret or copyright law. Dissemination of this information or reproduction of this material is -- strictly forbidden unless prior written permission is obtained from Fuzzy Logix, LLC. -- Functional Test Specifications: -- -- Test Category: Basic Statistics -- -- Test Unit Number: FLrank-Netezza-01 -- -- Name(s): FLRank -- -- Description: Calculates the rank of each observation in a data series -- -- Applications: -- -- Signature: FLRank(pValue DOUBLE PRECISION, -- pOrder VARCHAR(10)) -- -- Parameters: See Documentation -- -- Return value: INTEGER -- -- Last Updated: 03-04-2017 -- -- Author: Kamlesh Meena -- -- BEGIN: TEST SCRIPT \time --.run file=../PulsarLogOn.sql --.set width 2500 SELECT COUNT(*) AS CNT, CASE WHEN CNT = 0 THEN ' Please Load Test Data!!! ' ELSE ' Test Data Loaded ' END AS TestOutcome FROM fzzlSerial a; -- BEGIN: POSITIVE TEST(s) ---- Positive Test 1: Returns expected result --- Return expected results, Good WITH z (pTxnDate,pGroupID,pTickerSymbol,pValue, pRankOrder) AS ( SELECT a.TxnDate, a.TickerID, a.TickerSymbol, a.ClosePrice, 'D' FROM finStockPrice a WHERE a.TickerSymbol IN ('AAPL','HPQ','IBM','MSFT','ORCL') AND a.TxnDate BETWEEN '2002-01-01' AND '2002-02-01') SELECT z.pTickerSymbol,z.pTxnDate,z.pGroupID,z.pValue, FLRank(z.pValue, z.pRankOrder) OVER (PARTITION BY z.pTickerSymbol) AS Rank FROM z ORDER BY 1,2 LIMIT 20 ; ---- Positive Test 2: One observation --- Return 1, Good WITH z (pGroupID, pRandVal,pRankOrder) AS ( SELECT 1, a.RandVal, 'A' FROM fzzlSerial a WHERE a.SerialVal <=1 ) SELECT z.pGroupID,z.pRandVal, FLRank(z.pRandVal,pRankOrder) OVER (PARTITION BY 1) AS Rank FROM z ORDER BY 1 LIMIT 20 ; ---- Positive Test 3: Two observations --- Return expected results, Good WITH z (pGroupID, pRandVal,pRankOrder) AS ( SELECT 1, a.RandVal, 'A' FROM fzzlSerial a WHERE a.SerialVal <=2 ) SELECT z.pGroupID,z.pRandVal, FLRank(z.pRandVal,pRankOrder) OVER (PARTITION BY 1) AS Rank FROM z ORDER BY 1 LIMIT 20 ; ---- Positive Test 4: With all ties, Results should be 1 --- Return expected results, Good WITH z (pGroupID, pSerialVal,pRankOrder) AS ( SELECT 1, CASE WHEN a.SerialVal <= 100 THEN 1 ELSE a.SerialVal END, 'A' FROM fzzlSerial a WHERE a.SerialVal <=100 ) SELECT z.pGroupID,z.pSerialVal, FLRank(z.pSerialVal,pRankOrder) OVER (PARTITION BY 1) AS Rank FROM z ORDER BY 1 LIMIT 20 ; ---- Positive Test 5: Mix with ties --- Return expected results, Good WITH z (pGroupID, pSerialVal,pRankOrder) AS ( SELECT 1, CASE WHEN a.SerialVal <= 10 THEN 1 ELSE a.SerialVal END, 'A' FROM fzzlSerial a WHERE a.SerialVal <=100 ) SELECT z.pGroupID,z.pSerialVal, FLRank(z.pSerialVal,pRankOrder) OVER (PARTITION BY 1) AS Rank FROM z ORDER BY 2 LIMIT 20 ; ---- Positive Test 6: Mix With Nulls --- Output error: The value argument can not be Null, need to be mentioned in manual --- To be investigated WITH z (pGroupID, pSerialVal,pRankOrder) AS ( SELECT 1, CASE WHEN a.SerialVal <= 10 THEN NULL ELSE a.SerialVal END, 'A' FROM fzzlSerial a WHERE a.SerialVal <=100 ) SELECT z.pGroupID,z.pSerialVal, FLRank(z.pSerialVal,z.pRankOrder) OVER (PARTITION BY z.pGroupID) AS Rank FROM z ORDER BY 2 LIMIT 20 ; ---- Positive Test 7: Positive test case with more than one observations --- Return expected results, Good WITH z (pGroupID, pSerialVal,pRankOrder) AS ( SELECT 1, a.SerialVal, 'A' FROM fzzlSerial a WHERE a.SerialVal <=100 ) SELECT z.pGroupID,z.pSerialVal, FLRank(z.pSerialVal,pRankOrder) OVER (PARTITION BY 1) AS Rank FROM z ORDER BY 2 LIMIT 20 ; ---- Positive Test 8: Percent Rank of -1.0 * Value --- Return expected results, Good WITH z (pGroupID, pSerialVal,pRankOrder) AS ( SELECT 1, a.SerialVal, 'A' FROM fzzlSerial a WHERE a.SerialVal <=100 ) SELECT z.pGroupID,-1.0*z.pSerialVal, FLRank(-1.0*z.pSerialVal,pRankOrder) OVER (PARTITION BY 1) AS Rank FROM z ORDER BY 2 DESC LIMIT 20 ; ---- Positive Test 9: Percent Rank of Value + 1.0, Results should not change --- Return expected results, Good WITH z (pGroupID, pSerialVal,pRankOrder) AS ( SELECT 1, a.SerialVal, 'A' FROM fzzlSerial a WHERE a.SerialVal <= 100 ) SELECT z.pGroupID,z.pSerialVal+1.0, FLRank(z.pSerialVal+1.0,pRankOrder) OVER (PARTITION BY 1) AS Rank FROM z ORDER BY 2 LIMIT 20 ; ---- Positive Test 10: Multiply by a very small number, Results should not change --- Return expected results, Good WITH z (pGroupID, pSerialVal,pRankOrder) AS ( SELECT 1, a.SerialVal, 'A' FROM fzzlSerial a WHERE a.SerialVal <= 100 ) SELECT z.pGroupID,z.pSerialVal*1e-100, FLRank(z.pSerialVal*1e-100,pRankOrder) OVER (PARTITION BY 1) AS Rank FROM z ORDER BY 2 LIMIT 20 ; ---- Positive Test 11: Multiply by a very large number, Results should not change --- Return expected results, Good WITH z (pGroupID, pSerialVal,pRankOrder) AS ( SELECT 1, a.SerialVal, 'A' FROM fzzlSerial a WHERE a.SerialVal <= 100 ) SELECT z.pGroupID,z.pSerialVal*1e100, FLRank(z.pSerialVal*1e100,pRankOrder) OVER (PARTITION BY 1) AS Rank FROM z ORDER BY 2 LIMIT 20 ; ---- Positive Test 12: Add a very large number, Results should not change --- Precision of Double issue, all values become 1e100, so output 0, which is expected --- to be investigated WITH z (pGroupID, pSerialVal,pRankOrder) AS ( SELECT 1, a.SerialVal, 'A' FROM fzzlSerial a WHERE a.SerialVal <= 100 ) SELECT z.pGroupID,z.pSerialVal+1e100, FLRank(z.pSerialVal+1e100,pRankOrder) OVER (PARTITION BY 1) AS Rank FROM z ORDER BY 2 LIMIT 20 ; -- END: POSITIVE TEST(s) -- BEGIN: NEGATIVE TEST(s) ---- Negative Test 1: Rank Order can be 'A' or 'D' --- Error WITH z (pTxnDate,pGroupID,pTickerSymbol,pValue, pRankOrder) AS ( SELECT a.TxnDate,a.TickerID,a.TickerSymbol,a.ClosePrice,'X' FROM finStockPrice a WHERE a.TickerSymbol IN ('AAPL','HPQ','IBM','MSFT','ORCL') AND a.TxnDate BETWEEN '2002-01-01' AND '2002-02-01') SELECT z.pTickerSymbol,z.pTxnDate,z.pGroupID,z.pValue, FLRank(z.pValue, z.pRankOrder) OVER (PARTITION BY z.pTickerSymbol) AS Rank FROM z ORDER BY 1,2; ---- Negative test 2: TicketSymbol is set to values which are not present --- No Output WITH z (pTxnDate,pGroupID,pTickerSymbol,pValue, pRankOrder) AS ( SELECT a.TxnDate,a.TickerID,a.TickerSymbol,a.ClosePrice,'D' FROM finStockPrice a WHERE a.TickerSymbol IN ('ORCLX') AND a.TxnDate BETWEEN '2002-01-01' AND '2002-02-01') SELECT z.pTickerSymbol,z.pTxnDate,z.pGroupID,z.pValue, FLRank(z.pValue, z.pRankOrder) OVER (PARTITION BY z.pTickerSymbol) AS Rank FROM z ORDER BY 1,2; ---- Negative Test 3: No data --- No Output WITH z (pGroupID, pRandVal,pRankOrder) AS ( SELECT 1, a.RandVal, 'A' FROM fzzlSerial a WHERE a.SerialVal <= -1 ) SELECT z.pGroupID,z.pRandVal, FLRank(z.pRandVal,pRankOrder) OVER (PARTITION BY 1) AS Rank FROM z ORDER BY 2; ---- Negative Test 4: Value(Double Precision) out of range: Percent Rank of 1.0e400 * Value --- Return expected error, Good WITH z (pGroupID, pSerialVal,pRankOrder) AS ( SELECT 1, a.SerialVal, 'A' FROM fzzlSerial a WHERE a.SerialVal <= 100 ) SELECT z.pGroupID,z.pSerialVal*1e400, FLRank(z.pSerialVal*1e400,pRankOrder) OVER (PARTITION BY 1) AS Rank FROM z ORDER BY 2; ---- Negative Test 5: Value(Double Precision) out of range: Percent Rank of 1.0e-400 * Value --- Return 0 value, Good WITH z (pGroupID, pSerialVal,pRankOrder) AS ( SELECT 1, a.SerialVal, 'A' FROM fzzlSerial a WHERE a.SerialVal <= 100 ) SELECT z.pGroupID,z.pSerialVal*1e-400, FLRank(z.pSerialVal*1e-400,pRankOrder) OVER (PARTITION BY 1) AS Rank FROM z ORDER BY 2 LIMIT 20; ---- Negative Test 6: Invalid Data Type: Input Varchar Value --- Return expected error, Good WITH z (pGroupID, pSerialVal,pRankOrder) AS ( SELECT 1, CAST(a.SerialVal AS VARCHAR(30)), 'A' FROM fzzlSerial a WHERE a.SerialVal <= 100 ) SELECT z.pGroupID,z.pSerialVal, FLRank(z.pSerialVal,pRankOrder) OVER (PARTITION BY 1) AS Rank FROM z ORDER BY 2 LIMIT 20; -- END: NEGATIVE TEST(s) \time -- END: TEST SCRIPT
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clc; clear; close; function g = sigmoid(z) //SIGMOID Compute sigmoid functoon // J = SIGMOID(z) computes the sigmoid of z. g = 1.0 ./ (1.0 + exp(-z)); end function theta = thetaInit(m,n) theta = rand(m,n,'normal') endfunction function val = sigmoidDiff(net) val = sigmoid(net).*(1-sigmoid(net)) endfunction loadmatfile('irisDataset.mat') X = irisInputs'; y = irisTargets'; //load trainingData.dat // loads data into X variable and outputs in y variable // ---------Architecture-------------------------------------- num_h = 4; // number of nodes in each hidden layer n = size(X,2); // number of inputs p = size(y,2); // number of outputs m = size(X,1); // no. of training exaples(patterns) in matrix h = 7; // no.of nodes in the hidden layer eta = 0.3; // learning rate Xnew = [ones(m,1),X]; // numTheta = 6; //----generate random initial thetas ----- theta1 = thetaInit(h,n+1); theta2 = thetaInit(h,h+1); theta3 = thetaInit(h,h+1); theta4 = thetaInit(h,h+1); theta5 = thetaInit(h,h+1); theta6 = thetaInit(p,h+1); //----Calculating outward--------- net2 = Xnew * theta1'; // X(m*n+1) * theta1'((n+1),h1) fNet2 = sigmoid(net2); net3 = [ones(size(fNet2,1),1),fNet2]*theta2'; fNet3 = sigmoid(net3); net4 = [ones(size(fNet3,1),1),fNet3]*theta3'; fNet4 = sigmoid(net4); net5 = [ones(size(fNet4,1),1),fNet4]*theta4'; fNet5 = sigmoid(net5); net6 = [ones(size(fNet5,1),1),fNet5]*theta5'; fNet6 = sigmoid(net6); net7 = [ones(size(fNet6,1),1),fNet6]*theta6'; fNet7 = sigmoid(net7); //------Calculating deltas ------- // at o/p neuron delta7 = (y-fNet7) .* sigmoidDiff(net7); // at hidden neurons delta6 = (delta7 * theta6(:,2:$)) .* sigmoidDiff(net6); delta5 = (delta6 * theta5(:,2:$)) .* sigmoidDiff(net5); delta4 = (delta5 * theta4(:,2:$)) .* sigmoidDiff(net4); delta3 = (delta4 * theta3(:,2:$)) .* sigmoidDiff(net3); delta2 = (delta3 * theta2(:,2:$)) .* sigmoidDiff(net2); //delta1 = (delta2 * theta1(:,2:$)) .* sigmoidDiff(net1); //------ Calculating gradients----- //deltaTheta7 = eta * (delta7*fNet6); deltaTheta6 = zeros(3,8); for i = 1:size(fNet7,1) for j = 1:size(fNet7,2) deltaTheta6(1:3) = deltaTheta6(1:3) + eta* fNet7(i,j)*delta7(i,1:3); end end
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// Theory and Problems of Thermodynamics // Chapter 5 // Second law of Thermodynamics // Example 5 clear ;clc; //Given data n = 0.6 //n = efficiency of carnot engine COP_R = 5 //TH = High temperature of reservoir // To find the energy absorbed from the cold body by the refrigerator for each kJ QL_Q1 = n * COP_R; // energy in kJ // n = W/Q1 => W = n*Q1 // COP_R = QL/W => W = QL/COP_R // n*Q1 = QL/COP_R => QL/Q1 = n * COP_R // Results mprintf('The energy absorbed from the cold body by the refrigerator for each kJ = %1.0f kJ', QL_Q1)
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//Chapter 02:Basic Structures: Sets, Functions, Sequences, Sums and Matrices clc; clear; matA=[] mprintf("Enter the dimensions of MATRIX A:") row=input("Enter the no. of rows:") col=input("Entet the no.of columns:") mprintf("Enter the elements:") for i=1:row for j=1:col mprintf('\nInput for Row %d , Column %d:',i,j) n=input(" ") matA(i)(j)=n end end matB=[] mprintf("Enter the dimensions of MATRIX B:") row1=input("Enter the no. of rows:") col1=input("Entet the no.of columns:") mprintf("Enter the elements:") for i=1:row1 for j=1:col1 mprintf('\nInput for Row %d , Column %d:',i,j) n=input(" ") matB(i)(j)=n end end mprintf("Matrix A:") disp(matA) mprintf("Matrix B:") disp(matB) matADD=matA+matB mprintf("Sum of Matrices:") disp(matADD)
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//Exa 4.12.1 clc; clear; close; // Given data q = 1.6 * 10^-19;// in C N_D = 10^15;// in electrons/cm^3 N_D = N_D * 10^6;// in electrons/m^3 epsilon_r = 12; epsilon_o = (36 * %pi * 10^9)^-1; epsilon = epsilon_o * epsilon_r; a = 3 * 10^-4;// in cm a = a * 10^-2;// in m V_P = (q * N_D * a^2)/( 2 * epsilon);// in V disp(V_P,"The Pinch off voltage in V is"); // V_GS = V_P * (1-(b/a))^2 b = (1-0.707) *a;// in m disp(b*10^6,"The value of b in µm is : ") disp("Hence the channel width has been reduced to about one third of its value for V_GS = 0");// // Note : The unit of b in the book is wrong since the value of b is calculated in µm.
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//fibo clc s=zeros(1,10) s(1)=1; s(2)=1; for i=3:10 s(i)=s(i-2)+s(i-1) end disp(s)
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clc clear n=1.2; P1=1; P2=6; Vs=1.5/60; IP=[n/(n-1)]*[P1*100*Vs]*[((P2/P1)^((n-1)/n))-1]; printf('Indicated Power= %2.1f kW',IP); printf('\n'); MP=6.55; Em=IP/MP; printf('Mechanical Efficiency= %2.1f Percent',Em*100); printf('\n');
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clc T=1.25; //N.m N=9500; W1=2*%pi*N*T/1000; //kJ p=101.3; //kPa d=0.65; //m A=%pi/4*d^2; //m^2 L=0.6; //m W2=p*A*L; //kJ Wnet=(-W1)+W2; disp("The net work transfer for the system=") disp(Wnet) disp("kJ")
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function Out=Unscaling(G) global LOGX LOGY SCALEX SCALEY; GLg=[G(:,1)/SCALEX,G(:,2)/SCALEY]; Out=GLg; if LOGX==1 Out=[10^(GLg(:,1)),GLg(:,2)]; end; if LOGY==1 Out=[GLg(:,1),10^(GLg(:,2))]; end; endfunction;
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// chapter 9 // example 9.19 // Design a self-commutated invertor circuit and compute output power // page-608-609 clear; clc; // given f0=3; // in KHz R=5; // in ohm (load resistance) L=5; // in mH Edc=100; // in V (dc source) // calculate f0=f0*1E3; // changing unit from KHz to Hz fr=1.35*f0; // calculation of resonant frequency L=L*1E-3; // changing unit from mH to H w0=2*%pi*f0; // calculation of normal angular frequency wr=2*%pi*fr; // calculation of resonant angular velocity // since L/L1=200, therefore we get L1=L/200; // calculation of inductance L1 // since fr=1/(2*%pi*sqrt(2*L1*C)), therefore we get C=(1/(2*%pi*fr))^2/(2*L1); // calculation of capacitance tou=R*C; // calculation of time constant T=1/f0; // calculation of time period K=exp(-T/(2*tou)); // calculation of attenuation factor Z0=(R*%i*w0*L)/((R+(%i*w0*L))); // calculation of output impedence Z0_magnitude=abs(Z0); I=(Edc/Z0_magnitude)*(1/(1-4*tou*((1-K)/(1+K)))); // calculation of current flowing through Thyristor E0_max=I*Z0_magnitude*(1-2*K/(1+K)); // calculation of maximum output vltage E0_rms=E0_max/sqrt(2); // calculation of rms output voltage V_BO=2*(Edc+E0_max); // calculation of forward blocking voltage rating I_T=2*I; // calculation of Thyristor current tq=tou*log(2/(1+K)); // calculation of invertor trun off-time Vc=2*E0_max; // calculation of capacitor voltage P0=(E0_max*E0_rms/R)*cosd(atand(imag(Z0),real(Z0))); // calculation of output power printf("\nThe resonant frequency is \t\t\t fr=%.2f KHz",fr*1E-3); printf("\nThe inductance L1 is \t\t\t\t L1=%.f uH",L1*1E6); printf("\nThe capacitance is \t\t\t\t C=%.f uF",C*1E6); printf("\nThe current flowing through Thyristor is \t I=%.f A",I); printf("\nThe maximum output voltage is \t\t\t E0_max=%.2f V",E0_max); printf("\nThe rms output voltage is \t\t\t E0_rms=%.2f V",E0_rms); printf("\nThe forward blocking voltage is \t\t V_BO>=%.2f V",V_BO); printf("\nThe Thyristor current is \t\t\t I_T=%.f A",I_T); printf("\nThe invertor turn-off time is \t\t\t tq=%.1f us",tq*1E6); printf("\nThe output power is \t\t\t\t P0=%.2f W",P0); // Note: The answer varies slightly due to precise calculations and round off as done in the book
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//Ex 5.8 clc;clear;close; format('v',5); //vo/v1=1+R2/R1;// //For v2/v1 i.e. gain=2, R1 & R2 should be equal Vpp=10;//V R1=10;//kohm R2=10;//kohm //Avg=1/T*integrate('Vpp*sin(2*%pi*t/T)','t',0,T/2); Avg=-Vpp/(2*%pi)*[cos(%pi)-cos(0)]; disp(Avg,"Average output voltage(V) : ");
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//Ex2_7 clc C = 0.2*10^-6 f1 = 1.0*10^3 f2 = 50 disp("C = "+string(C)+"F")//capacitance disp("at... f = "+string(f1)+"Hz")//frequency disp("Xc = 1/(2*pi*f*C) = "+string(1/(2*%pi*f1*C))+"ohm")//calculation for capacitive reactance disp("at... f = "+string(f2)+"Hz")//frequency disp("Xc = 1/(2*pi*f*C) = "+string(1/(2*%pi*f2*C))+"ohm")//calculation for capacitive reactance
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disp('the co-efficient matrix is:') a=[1 2;5 12] disp(a) disp('inverse of the matrix is:') disp(inv(a)) disp('solution is:') b=[-1;3]; c=inv(a); disp(c*b)
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function x=g_eye(a) // only to be called by function eye //! select type(a) case 1 then x=eye(a) case 2 then x=eye(a) case 5 then [m,n]=size(a) x=sparse([],[],[m,n]) case 15 then if a(1)=='r' then x=eye(a(2)); elseif a(1)='lss' then x=eye(a(5)) end case 10 then [m,n]=size(a) x=eye(m,n) else error(43) end
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function y=f(x) y = (x^2+5*x+1) endfunction x=linspace(-1,8) plot(x, f)
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exec( get_absolute_file_path('support.sce') + "0_bisection.sce", -1 ); exec( get_absolute_file_path('support.sce') + "1_chord.sce", -1 ); exec( get_absolute_file_path('support.sce') + "2_tangent.sce", -1 ); exec( get_absolute_file_path('support.sce') + "3_simple_iter.sce", -1 ); function [ a, b ] = askBorders( fun ) x = [ 0 : 0.1 : 5 ]'; plot2d( x, fun( x ) ); desc = gca(); desc.x_location = "origin"; desc.y_location = "origin"; xgrid(); while( %T ) a = input( "Input left border of the root isolation interval: " ); b = input( "Input right border of the root isolation interval: " ); if( b < a ) then disp( "a value cant be bigger than b value. Try again." ); else break; end end endfunction
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//Finding of vane angle , Work done , Efficiency //Given D1=0.6; D=0.3; a=30; b=0.05; N=1200; g=9.81; Hm=75; Vf=3; rho=1000; B1=1; //To Find u=(%pi*D*N)/60; u1=(%pi*D1*N)/60; Q=%pi*D1*B1*Vf; a=atand(Vf/u);disp(u1); Vw1=((u1*tan(%pi/6))-Vf)/tan(%pi/6); W=(rho*g*Q*u1*Vw1)/g; W1=W/1000; E=((g*Hm)/(u1*Vw1))*100; disp("Vane Angle ="+string(a)+" degrees"); disp("Work Done ="+string(W1)+" KW/sec"); disp("Manometric Efficiency ="+string(E)+" Percentage");
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exec('myfunc.sci'); //y=ode("rk",y0,t0,t,f) //initial condition at r=0 //chidashi //chii //final condition at tub wal r=R (tube radius) //chidashf //chif n=200; tchi(1:n)=zeros(n); tpi(1:n)=zeros(n); rw(1:4)=zeros(4); dchi(1:4)=zeros(4); dpi(1:4)=zeros(4); rtube=4.2e6; params.m=0; params.k=0.8e-6; params.om=2e-2; //s^-1rad params.p=2.4e4; params.rpi=1e-6; //Uuse initial bc params.rchi=1e-6; //use initial bc tchi(1)=params.rchi; tpi(1)=params.rpi; h=(rtube)/n; for i=1:n res(i)=1./N(rar(i),params.m,params.k,params.om,params.p); end
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// Example 11.4 format('v',5) clc; clear; close; // given data h_fe= 120;// unit less h_ie= 3.5*10^3;//in Ω r_L= 2*10^3;// in Ω h_oe= 8.5*10^-6;// in S h_re= 1.3*10^-4;// unit less // The voltage gain A= h_fe*r_L/(h_ie*(1+h_oe*r_L)-h_re*h_fe*r_L) disp(A,"The voltage gain is : ")
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java -ea make.Main -f make-tests/autograder_make09.mk -D make-tests/autograder_file09 T1
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//Find relative permeability and Intensity of magnetisation //Ex:14.1 clc; clear; close; x=1500;//susceptibility h=2400;//mafnetic field in A/m u_r=1+x; disp(u_r,"relative permeability = "); m=x*h;//in A/m disp(m,"Intensity of magnetisation (in A/m)"); u_0=4*3.14*10^-7; b=u_0*u_r*h;//in T disp(b,"Remanance (in T) = ")
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###grammar S -> NP VP S -> S PP NP -> i NP -> the man NP -> the telescope NP -> the house NP -> NP PP PP -> in NP PP -> with NP VP -> saw NP ###input i saw the man in the house with the telescope ###pformat S( S( S( NP(i) VP( saw NP(the man) ) ) PP( in NP(the house) ) | NP(i) VP( saw NP( NP(the man) PP( in NP(the house) ) ) ) ) PP( with NP(the telescope) ) | S( NP(i) VP( saw NP(the man) ) ) PP( in NP( NP(the house) PP( with NP(the telescope) ) ) ) | NP(i) VP( saw NP( NP( NP(the man) PP( in NP(the house) ) ) PP( with NP(the telescope) ) | NP(the man) PP( in NP( NP(the house) PP( with NP(the telescope) ) ) ) ) ) ) ###pformat_ext S( #2 S( #2 S( #1 NP( #3 i ) VP( #10 saw NP( #4 the man ) ) ) PP( #8 in NP( #6 the house ) ) | #1 NP( #3 i ) VP( #10 saw NP( #7 NP( #4 the man ) PP( #8 in NP( #6 the house ) ) ) ) ) PP( #9 with NP( #5 the telescope ) ) | #2 S( #1 NP( #3 i ) VP( #10 saw NP( #4 the man ) ) ) PP( #8 in NP( #7 NP( #6 the house ) PP( #9 with NP( #5 the telescope ) ) ) ) | #1 NP( #3 i ) VP( #10 saw NP( #7 NP( #7 NP( #4 the man ) PP( #8 in NP( #6 the house ) ) ) PP( #9 with NP( #5 the telescope ) ) | #7 NP( #4 the man ) PP( #8 in NP( #7 NP( #6 the house ) PP( #9 with NP( #5 the telescope ) ) ) ) ) ) ) ###format S(S(S(NP(i) VP(saw NP(the man))) PP(in NP(the house))|NP(i) VP(saw NP(NP(the man) PP(in NP(the house))))) PP(with NP(the telescope))|S(NP(i) VP(saw NP(the man))) PP(in NP(NP(the house) PP(with NP(the telescope))))|NP(i) VP(saw NP(NP(NP(the man) PP(in NP(the house))) PP(with NP(the telescope))|NP(the man) PP(in NP(NP(the house) PP(with NP(the telescope)))))))
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clear; clc; close; disp("Example2.9") d=0.2 //diameter in meters. l=0.2 //length in meters. Cf=0.005 //average wall friction coefficient. M1=0.24 //inlet mach no. gm=1.4 //gamma. //From FANNO tbale L1cr=(9.3866*d/2)/(4*Cf); L2cr=L1cr-l; //from FANNO table M2=0.3; x=2.4956; y=2.0351; a=4.5383; b=3.6191; i1=2.043; i2=1.698; //% total pressure drop due to friction: dpt=(x-y)/(x)*100; //static pressur drop: dps=(a-b)/a*100; //Loss pf fluid: lf=(i2-i1); disp(L1cr,"(a)The choking length of duct in m:") disp(M2,"(b)The exit Mach no.:") disp(dpt,"(c)% total pressure loss:") disp(dps,"(d)The static pressure drop in %:") disp(lf,"(e)Loss of impulse due to friction(I* times):")
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eg2_3d.sce
germ_free_mice = [158 192 193 194 195 202 212 215 229 230 237 240 244 247 259 301 301 321 337 415 434 444 485 496 529 537 624 707 800]; conventional_mice = [159 189 191 198 235 245 250 256 261 265 266 280 343 356 383 403 414 428 432]; disp (mean(germ_free_mice), "Sample mean for germ-free mice is "); disp (median(germ_free_mice), "Sample median for germ-free mice is "); disp (mean(conventional_mice), "Sample mean for conventional mice is "); disp (median(conventional_mice), "Sample mean for conventional mice is ");
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ex4_6.sce
clc; clear; Wo=2*%pi/3; n=-8:8; for i=1:length(n) x(i)=cos(Wo*n(i)); end X=fft(x,-1);
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2019-05-16T14:59:40
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calculs(quentin).sce
t = linspace(0,1,1000) p = poly(0,'p') R=0.8; L=400E-6; Kc=20.52E-3; J=18E-5; Cr=9.23E-3; taum=R*J/Kc^2; taue=L/R; Krpm=60/(2*%pi); Kci=1; Kd=0.001; Kdrad = Kd*Krpm Gi = 1; K1 = Gi*taum/(R*taue + Kci*Gi*taum); tau1 = taum/(1+Kci*Gi*taum/R/taue); Gw = J/(4*(0.7)^2*Kc*Kdrad*K1*tau1) //AI = syslin('c',K1/(1+tau1*p)) Bo = syslin('c',Kdrad*K1*Kc/((J*p)*(1+tau1*p))) //B1 = syslin('c',Gw*AI*Kc/(J*p)/(1+Gw*AI*Kc*Kd/(J*p))) evans(Bo,2000); sgrid(0.7,1787); //e = 11000*ones(t) //s = csim(e,t,Kd*B1) //scf(1) //plot2d(t,s)
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solution11_6.sce
//Obtain the path of solution file path = get_absolute_file_path('solution11_6.sce') //Obtain the path of data file datapath = path + filesep() + 'data11_6.sci' //Clear all clc //Execute the data file exec(datapath) //Step1: Clutch being brand new, apply uniform-pressure theory //Consider torque transmission by one pair of contacting surfaces Mt = Mt / 2 //Total force obtained from n springs P = n * P //Evaluate torque transmitting capacity Mtp (N-mm) Mtp = (mu * P * ((D^3)-(d^3)))/(3 * ((D^2)-(d^2))) //Evaluate corresponding factor of safety fsp = Mtp / (Mt * 1000) //Step2: Clutch subjected to initial wear, apply uniform-wear theory //Assuming there is negligible change in spring force after wear //Evaluate torque transmitting capacity Mtw (N-mm) Mtw = (mu * P * (D + d))/4 //Evaluate corresponding factor of safety fsw = Mtw / (Mt * 1000) //Step3: Wear of friction lining before slippage //Evaluate spring force required to transmit the torque(Mt) Pmax (N) Pmax = (Mt * 4 * 1000)/(mu * (D + d)) //Evaluate force provided by each spring Pmax = Pmax / n //Evaluate stiffness of spring s (N/mm) s = P / (delta * n) //Evaluate allowable wear of friction lining x (mm) x = delta - (Pmax / s) //Print results printf('\nStep1: Clutch being brand new,') printf('applying uniform-pressure theory\n') printf('\nFactor of safety(fsp) = %f\n',fsp) printf('\nStep2: Clutch being subjected to initial wear,') printf('applying uniform-wear theory\n') printf('\nFactor of safety(fsw) = %f\n',fsw) printf('\nStep3: Allowable wear of friction lining(x) = %f mm\n',x)
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4_8.sci
errcatch(-1,"stop");mode(2);//4.8 ; Q=100.5; M=300; q=100.6; m=300.25; r=0.1; S=0.0045; X=((M*S/Q)+((r)/(r+m*q))*((M*q/Q)-(m)))*10^6; printf("Unknown resistance=%.2f micro-ohm",X) exit();
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//ex7.3 I_DSS=9*10^-3; V_GS_off=-8; V_GS=0; I_D=value_of_I_D(9*10^-3,0,-8); disp(I_D,'Value of I_D for V_GS=0V') I_D=value_of_I_D(9*10^-3,-1,-8); disp(I_D,'Value of I_D for V_GS=-1V') I_D=value_of_I_D(9*10^-3,-4,-8); disp(I_D,'Value of I_D for V_GS=-4V')
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newton.sce
//Newton's Method //Amie Demmel //4/1/15 //model to be fitted contained in myfuncn.sci exec myfuncn.sci; disp('Newton Method: ') maxiter=100; tol=10^-6; iter=0; x=input('enter x vector: '); t=input('time vector: '); y=input('y vector: '); [f,g,h]=myfuncn(x,t,y) h0=h; titl=[' iter' ' f(x)' ' df(x)/dx1' ' df(x)/dx2' 'norm(df(x)']; disp(titl); while((norm(g) > tol)&(iter < maxiter)) iter=iter+1; p=-h\g; x=x+p; [f,g,h]=myfuncn(x,t,y); n=[iter f g' norm(g)]; disp(n); end hm=h; disp('Solution: ') disp(x)
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normalluck.sci
exec("zluck.sci",-1); function [L,U]=normalluck(x,mu,Sigma) zl=zluck(x,mu,Sigma); L=0.5*erfc(-zl); U=0.5*erfc(zl); endfunction
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example5_50.sce
clear; clc; // Stoichiometry // Chapter 5 // Energy Balances // Example 5.50 // Page 302 printf("Example 5.50, Page 302 \n \n"); // solution // from fig 5.18 Ta = 379.5 // K dH = -274-(-106.5) // kJ/kg sol Cm = 2.05 // kJ/kg K dHc = Cm*(Ta-298.15) // basis 100 kg of 93 % acid // acid balance x = poly(0, 'x') p = .93*100+x*.15-(100+x)*.77 y = roots(p) //from fig y1 = 25.3 printf(" (a) \n \n Resultant T of 77 percent sol = "+string(Ta)+" K. \n \n \n (b) \n \n Heat to be removed to cool it to 298.15 K = "+string(dH)+" kJ/kg sol \n \n \n (c) \n \n By mean heat capacity method : "+string(dHc)+" kJ/kg sol \n \n \n (d) \n \n Quantity of 15 percent acid to be mixed = "+string(y)+" kg. \n \n \n (e) \n \n from fig : "+string(y1)+" kg.")
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clc; l=0.3;//core length r=0.2;//radius n=20;//speed in r.p.s. Ia=20;//armature current Z=500;//total conductors Bav=0.5;//avg. flux density a=4;//lap-wound P=4;//no of poles Wm=2*%pi*n phi=((0.5*2*%pi*0.2*0.3)/4); Ea=((P*n*Z*phi)/a);//generated emf Pm=Ea*Ia;//gross mechanical power developed Te=((Ea*Ia)/Wm);//internal torque printf('Generated E.M.F. is %f V.\n',Ea); printf('Gross mechanical power developed is %f W.\n',Pm); printf('Internal Torque is %f Nm.',Te);
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2017-01-16T20:09:35
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<scriptConfig name="RR" script="RR"> <params> <param name="invt.pretest_delay" type="int">0</param> <param name="rr.RRnorm_up_min" type="float">2.0</param> <param name="rr.MSARR" type="float">2.5</param> <param name="rr.t_dwell" type="float">3.0</param> <param name="comm.slave_id" type="int">5</param> <param name="invt.verification_delay" type="int">5</param> <param name="invt.posttest_delay" type="int">10</param> <param name="rr.Ilow" type="float">20.0</param> <param name="rr.Irated" type="float">100.0</param> <param name="rr.RRnorm_up_max" type="float">100.0</param> <param name="comm.baudrate" type="int">9600</param> <param name="comm.ifc_name" type="string">COM7</param> <param name="datatrig.dsm_method" type="string">Disabled - Data from EUT</param> <param name="datatrig.trigger_method" type="string">Disabled - Data from EUT</param> <param name="pvsim.mode" type="string">Manual</param> <param name="comm.parity" type="string">N</param> <param name="comm.ifc_type" type="string">RTU</param> </params> </scriptConfig>
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// Scilab Code Ex1.17: Page:35 (2011) clc;clear; c = 3e+008; // Speed of light in vacuum, unit m0 = 9.1e-031; // Rest mass of the electron, kg E_k = 0.1*1e+006*1.6e-019; // Kinetic energy of the electron, J v = sqrt(2*E_k/m0); // Classical speed of the electron, m/s printf("\nThe classical speed of the electron = %5.3e m/s", v); // As E_k = (m-m0)*c^2 = (1/sqrt(1-v^2/c^2)-1)*m0*c^2, solving for v v = c*sqrt(1-(m0*c^2/(E_k+m0*c^2))^2); // Relativistic speed of the electron, m/s printf("\nThe relativistic speed of the electron = %5.3e m/s", v); // Result // The classical speed of the electron = 1.875e+008 m/s // The relativistic speed of the electron = 1.644e+008 m/s
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Ch01Ex2.sce
// Scilab Code Ex1.2: Page-1.5 (2009) clc; clear; m = 1.67e-027; // Mass of the particle, kg h = 6.626e-034; // Planck's constant, Js e = 1.6e-019; // Energy equivalent of 1 eV, J/eV E = 1e+011*e; // Energy of the particle, J lambda = h/sqrt(2*m*E); // de Broglie wavelength of the particle, m printf("\nThe de Broglie wavelength of the particle = %4.2e m", lambda); // Result // The de Broglie wavelength of the particle = 9.06e-017 m
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clear all; clc; cd /home/lavitha/Scilab-Image-Processing-Toolbox-master exec builder.sce exec loader.sce diary("Read_image.txt") A_jpeg=imread("color.jpeg") A_png=imread("color.png") A_bmp=imread("color.bmp") A_tif=imread("color.tif") diary(0) diary("scilab_laplacian.txt") //JPEG B_jpeg_64F=laplacian(A_jpeg, "CV_64F", 5, 5, 1) B_jpeg_32F=laplacian(A_jpeg, "CV_32F", 5, 5, 1) B_jpeg_16S=laplacian(A_jpeg, "CV_16S", 5, 5, 1) B_jpeg_16U=laplacian(A_jpeg, "CV_16U", 5, 5, 1) B_jpeg_8U=laplacian(A_jpeg, "CV_8U", 5, 5, 1) //PNG B_png_64F=laplacian(A_png, "CV_64F", 5, 5, 1) B_png_32F=laplacian(A_png, "CV_32F", 5, 5, 1) B_png_16S=laplacian(A_png, "CV_16S", 5, 5, 1) B_png_16U=laplacian(A_png, "CV_16U", 5, 5, 1) B_png_8U=laplacian(A_png, "CV_8U", 5, 5, 1) //bmp B_bmp_64F=laplacian(A_bmp, "CV_64F", 5, 5, 1) B_bmp_32F=laplacian(A_bmp, "CV_32F", 5, 5, 1) B_bmp_16S=laplacian(A_bmp, "CV_16S", 5, 5, 1) B_bmp_16U=laplacian(A_bmp, "CV_16U", 5, 5, 1) B_bmp_8U=laplacian(A_bmp, "CV_8U", 5, 5, 1) //tif B_tif_64F=laplacian(A_tif, "CV_64F", 5, 5, 1) B_tif_32F=laplacian(A_tif, "CV_32F", 5, 5, 1) B_tif_16S=laplacian(A_tif, "CV_16S", 5, 5, 1) B_tif_16U=laplacian(A_tif, "CV_16U", 5, 5, 1) B_tif_8U=laplacian(A_tif, "CV_8U", 5, 5, 1) diary(0) //jpeg imshow(B_jpeg_64F) xs2png(0,'laplacian_jpeg_64F.png') xs2png(gcf(),'laplacian_jpeg_64F.png') imshow(B_jpeg_32F) xs2png(0,'laplacian_jpeg_32F.png') xs2png(gcf(),'laplacian_jpeg_32F.png') imshow(B_jpeg_16U) xs2png(0,'laplacian_jpeg_16U.png') xs2png(gcf(),'laplacian_jpeg_16U.png') imshow(B_jpeg_16S) xs2png(0,'laplacian_jpeg_16S.png') xs2png(gcf(),'laplacian_jpeg_16S.png') imshow(B_jpeg_16S) xs2png(0,'laplacian_jpeg_16S.png') xs2png(gcf(),'laplacian_jpeg_16S.png') //imshow(B_png) //xs2png(0,'laplacian_png.png') //xs2png(gcf(),'laplacian_png.png') //png imshow(B_png_64F) xs2png(0,'laplacian_png_64F.png') xs2png(gcf(),'laplacian_png_64F.png') imshow(B_png_32F) xs2png(0,'laplacian_png_32F.png') xs2png(gcf(),'laplacian_png_32F.png') imshow(B_png_16U) xs2png(0,'laplacian_png_16U.png') xs2png(gcf(),'laplacian_png_16U.png') imshow(B_png_16S) xs2png(0,'laplacian_png_16S.png') xs2png(gcf(),'laplacian_png_16S.png') imshow(B_png_16S) xs2png(0,'laplacian_png_16S.png') xs2png(gcf(),'laplacian_png_16S.png') //bmp imshow(B_bmp_64F) xs2png(0,'laplacian_bmp_64F.png') xs2png(gcf(),'laplacian_bmp_64F.png') imshow(B_bmp_32F) xs2png(0,'laplacian_bmp_32F.png') xs2png(gcf(),'laplacian_bmp_32F.png') imshow(B_bmp_16U) xs2png(0,'laplacian_bmp_16U.png') xs2png(gcf(),'laplacian_bmp_16U.png') imshow(B_bmp_16S) xs2png(0,'laplacian_bmp_16S.png') xs2png(gcf(),'laplacian_bmp_16S.png') imshow(B_bmp_16S) xs2png(0,'laplacian_bmp_16S.png') xs2png(gcf(),'laplacian_bmp_16S.png') //tif imshow(B_tif_64F) xs2png(0,'laplacian_tif_64F.png') xs2png(gcf(),'laplacian_tif_64F.png') imshow(B_tif_32F) xs2png(0,'laplacian_tif_32F.png') xs2png(gcf(),'laplacian_tif_32F.png') imshow(B_tif_16U) xs2png(0,'laplacian_tif_16U.png') xs2png(gcf(),'laplacian_tif_16U.png') imshow(B_tif_16S) xs2png(0,'laplacian_tif_16S.png') xs2png(gcf(),'laplacian_tif_16S.png') imshow(B_tif_16S) xs2png(0,'laplacian_tif_16S.png') xs2png(gcf(),'laplacian_tif_16S.png')
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filtro PA.sce
f = 25; w = 2*%pi*f; G = 51; R1 = 1000; C = sqrt((-1)/((w^2)*(((sqrt(2) + 2*sqrt(2))/G)-(R1^2))))
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ch1_7.sce
clear; clc; printf("\t\t\tchapter1_example7\n\n\n"); // Identification of all resistances and their values // Estimation of heat transfer per unit area // Determination of the inside and outside wall temperatures printf("\n\t\t\tSolution to part (b)\n"); A=1; // assuming A=1 m^2 for convenience hc1_avg=(5+25)/2; // taking average of extreme values for hc [W/m^2.K] Rc1=1/(hc1_avg*A); // resistance on left side of wall [K/W] printf("\nThe resistance on left side of wall is %.3f K/W",Rc1); k=(0.38+0.52)/2; // thermal conductivity of common brick in W/M.k L=0.1; //10 cm converted into m Rk=(L/(k*A));// resistance of construction material, assume common brick printf("\nThe resistance of construction material of wall is %.3f K/W",Rk); Rc2=Rc1; printf("\nThe resistance on right side of wall is %.3f K/W",Rc2); printf("\n\n\t\t\tSolution to part (c)\n"); T_inf1=1000; // temperature of exhaust gases in K T_inf2=283; // temperature of ambient air in K q=(T_inf1-T_inf2)/(Rc1+Rk+Rc2); // heat transferred per unit area printf("\nThe Heat transferred per unit area is %d W = %.3f kW",q,q/1000); printf("\n\n\t\t\tSolution to part (d)\n"); T_in=T_inf1-Rc1*q; // T_out=T_inf2+Rc2*q; printf("\nThe inside wall temperature is %d K",T_in); printf("\nThe outside wall temperature is %d K",T_out);
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9_4.sce
clc //initialisation of variables m= 0.45 //kg v1= 0.03 //m^3 v2= 0.06 //m^3 P= 6.9*10^5 //Pa K= 1.4 R= 287.1 //J/Kg K //CALCULATIONS T1= (P*v1)/(m*R) T2= T1 P2= P*v1/v2 T3= T2*(v2/v1)^(K-1) P3= P2*(v2/v1)^K //RESULTS printf ('T1 = %.f K ',T1) printf (' \n T2= %.f K',T2) printf (' \n T3= %.f K',T3) printf (' \n P2= %.2e Pa',P2) printf (' \n P3= %.2e Pa',P3)
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Ex6_3.sce
clc //Given that T =40 // Thickness of steel bar in cm t1 = 40 // Time in ms t2 = 80 // Time in ms printf("Example 6.3\n") X = T*t1/t2 // Calculation of depth of defect printf("Depth of defect is %d cm.\n\n\n",X)
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8_1_40.sce
clc clear //Input data To=15+273 //Air Temperature in K Cp=1005 //Specific heat capacity at constnat pressure in J/kg-K //Calculation Cmax=sqrt(2*Cp*To) //Highest possible velocity in m/s //Output printf('Highest possible velocity is %3.2f m/s',Cmax)
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Ex1_42.sce
clear // // // //Variable declaration lamda=5000*10**-8 //wavelength(cm) D=50 //separation between screen and slit(cm) d=0.05 //separation between slits(cm) //Calculation beta1=lamda*D/d //fringe width(cm) //Result printf("\n fringe width is %0.3f cm",beta1)
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SStemperature.sce
//Reference: S.S. Rao,Engineering Optimization Theory and Practice, 3rd enlarged edition, New age international publishers,2011,chapter 6 // The steady state temperature (t1 and t2) at two points (mid point and the free end) of the one dimensional fin correspond to the minimum of the function. // f(t1,t2) = 0.6382*t(1)^2 + 0.3191*t(2)^2 - 0.2809*t(1)*t(2) - 67.906*t(1) - 14.29*t(2) //===================================================================== // Copyright (C) 2018 - IIT Bombay - FOSSEE // This file must be used under the terms of the CeCILL. // This source file is licensed as described in the file COPYING, which // you should have received as part of this distribution. The terms // are also available at // http://www.cecill.info/licences/Licence_CeCILL_V2-en.txt // Author: Remya Kommadath // Organization: FOSSEE, IIT Bombay // Email: [email protected] //===================================================================== clc; // Objective function function f = ObjectiveFunction(t) f = 0.6382*t(1)^2 + 0.3191*t(2)^2 - 0.2809*t(1)*t(2) - 67.906*t(1) - 14.29*t(2); endfunction // Initial guess x0 = [100 200]; disp(x0, "Initial guess given to the solver is ") input("Press enter to proceed: ") [xopt,fopt,exitflag,output,gradient,hessian] = fminunc(ObjectiveFunction,x0) // Result representation clc select exitflag case 0 disp("Optimal Solution Found") disp(xopt', "The steady state temperature at the points are") disp(fopt, "The optimum objective function value is") case 1 disp("Maximum Number of Iterations Exceeded. Output may not be optimal.") disp(xopt', "The temperature at the points are") disp(fopt, "The objective function value is") case 2 disp("Maximum CPU Time exceeded. Output may not be optimal.") disp(xopt', "The temperature at the points are") disp(fopt, "The objective function value is") case 3 disp("Stop at Tiny Step.") disp(xopt', "The temperature at the points are") disp(fopt, "The objective function value is") case 4 disp("Solved To Acceptable Level.") disp(xopt', "The temperature at the points are") disp(fopt, "The objective function value is") case 5 disp("Converged to a point of local infeasibility.") end disp(output)
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sqr_2.sce
a_count = 0 for i = 0:1000 x = grand(1,1,"unf",0,2) f = x * x if sign(2 - f) == 1 then a_count = a_count + 1 end end z = (a_count / 1000.0) * 2 disp(z)
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clc; close; Num_of_pixels_in_width = 2400; // Given width of the image in pixels Num_of_pixels_in_height = 2400;//Given height of the image in pixels Resolution = 300 // Scanning resoltuion in DPI //The Physical size of the Image disp(string(Num_of_pixels_in_width/Resolution)+" inches x "+ string(Num_of_pixels_in_width/Resolution)+" inches","The physical size is = ")
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SimpsonOneThird.sce
clc; clear; close; deff('y=f(x)','y=sin(x)') x0=0; xn=%pi; n=10; //n should be even h=(xn-x0)/n; s=0; for i=1:2:n s=s+f(x0+(i-1)*h)+4*f(x0+i*h)+f(x0+(i+1)*h); end integral=(h*s)/3; printf('\nThe value of integral is=%g\n',integral)